Campbell Biology
12th Edition
ISBN: 9780135188743
Author: Urry
Publisher: PEARSON
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Chapter 17.5, Problem 2CC
MAKE CONNECTIONS → Individuals heterozygous for the sickle-cell allele are generally healthy but show
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Q17. In a dog breed, a gene B coding for fur color has a dominant allele B for black fur. Gene B has a recessive
allele b that produces brown fur. A second gene I, has a dominant allele I that is epistatic to the color locus and
can inhibit pigment formation. Gene I has a recessive allele, i, on that permits pigment deposition in the fur.
Note: the inhibition of pigment formation by the epistatic allele I causes the fur to be white.
A) What is the phenotype of the individuals with the below genotypes?
bbii
Bbli
Bbii
bbli
BBIi
B) What are the phenotypes and genotypes of the offspring of each of these dog crosses?
a. bbii x Bbli
b. bbii x Bbii
c. bbli x BBli
C) What type of epistasis is described in this problem?
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Q11. One of the two genes known to be mutated in cases of Hypokalemic periodic paralysis (which is inherited in an autosomal dominant pattern but known to affect males more often than females) is the calcium voltage-gated channel subunit alpha1 S (CACNA1S). What is known about the gene is recorded here:
https://www.ensembl.org/Homo_sapiens/Gene/Summary?db=core;g=ENSG00000081248;r=1:201039512-201112451
Please navigate to the link above and ensure that you click to reveal the transcript table. Then use the information in the table to answer the following question.
What is the NCBI accession number (including the version) of the RefSeq Match for the first transcript (CACNA1S-201)?
Answer: NCBI accession number (including the version) of the RefSeq Match for the first transcript (CACNA1S-201) is ...
Think Critically. Provide a concise explanation of your answer.
A mutation on an autosome causes a particular protein to be overproduced, and the excess protein accumulates in the liver and damages it. Would the resulting disorder most likely be inherited in an autosomal dominant or recessive pattern?
Expression of the SYR gene on the Y chromosome gives rise to the male phenotype in humans. What do you think the inheritance pattern of SYR alleles is called?
22q11.2 deletion syndrome, also called DiGeorge syndrome, causes atypical parathyroid glands, a heart defect, and an underdeveloped thymus gland. About 85% of patients have a microdeletion of part of chromosome 22. A girl, her mother, and a maternal aunt have very mild DiGeorge syndrome. They all have a reciprocal translocation of chromosomes 22 and 2.
How can a microdeletion and a translocation cause the same symptoms?
Why were the people with the translocation less severely affected than the people with microdeletion?
What other…
Chapter 17 Solutions
Campbell Biology
Ch. 17.1 - Prob. 1CCCh. 17.1 - What polypeptide product would you expect from a...Ch. 17.1 - Prob. 3CCCh. 17.2 - MAKE CONNECTIONS In a research artide about...Ch. 17.2 - What enables RNA polymerase to start transcribing...Ch. 17.2 - WHAT IF? Suppose X-rays caused a sequence change...Ch. 17.3 - There are about 20,000 human protein-coding genes....Ch. 17.3 - How is RNA splicing similar to how you would watch...Ch. 17.3 - Prob. 3CCCh. 17.4 - What two processes ensure that the correct amino...
Ch. 17.4 - Prob. 2CCCh. 17.4 - Prob. 3CCCh. 17.4 - WH AT IF? In eukaryotic cells, mRNAs have been...Ch. 17.5 - What happens when one nucleotide pair is lost from...Ch. 17.5 - MAKE CONNECTIONS Individuals heterozygous for the...Ch. 17.5 - WHAT IF? DRAW IT The template strand of a gene...Ch. 17.5 - Prob. 4CCCh. 17 - Describe the process of gene expression, by which...Ch. 17 - What are the similarities and differences in the...Ch. 17 - What function do the 5' cap and the poly-A tail...Ch. 17 - Prob. 17.4CRCh. 17 - What will be the results of chemically modifying...Ch. 17 - In eukaryotic cells, transcription cannot begin...Ch. 17 - Prob. 2TYUCh. 17 - The anticodon of a particular tRNA molecule is (A)...Ch. 17 - Prob. 4TYUCh. 17 - Which component is not directly involved in...Ch. 17 - Using Figure 17.6, identify a 5' 3' sequence of...Ch. 17 - Prob. 7TYUCh. 17 - Would the coupling of the processes shown in...Ch. 17 - Prob. 9TYUCh. 17 - Prob. 10TYUCh. 17 - scientific inquiry Knowing that the genetic code...Ch. 17 - Prob. 12TYUCh. 17 - Prob. 13TYU
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- Discuss Concepts Many human diseases are caused by recessive alleles that are not expressed in heterozygotes. Some people think that eugenicsthe selective breeding of humans to eliminate undesirable genetic traitsprovides a way for us to rid our populations of such harmful alleles. Explain why eugenics cannot eliminate such genetic traits from human populations.arrow_forward4e. You also study the expression of 3 different mutants for this gene. For each mutant answer the following: Does this mutation change the sequence of the protein produced? Why or why not? If it does change the sequence of protein be sure to write out the new sequence. If it does not change the protein sequence, what effect (if any) would you expect it to have on expression of the gene? 1 20 ORI 40 60 5'...TTCGAGCTCTCGTCGTCGAGATACGCGATGATATTACTGGTAATATGGGGATGCACTATC...3' 3' ...AAGCTCGAGAGCAGCAGCTCTATGCGCTACTATAATGACCATTATACCCCTACGTGATAG...5' * promoterarrow_forward4e. You also study the expression of 3 different mutants for this gene. For each mutant answer the following: Does this mutation change the sequence of the protein produced? Why or why not? If it does change the sequence of protein be sure to write out the new sequence. If it does not change the protein sequence, what effect (if any) would you expect it to have on expression of the gene? 1 20 ORI 40 60 5'..TTCGAGCTCTCGTCGTCGAGATACGCGATGATATTACTGGTAATATGGGGATGCACTATC...3’ 3'...AAGCTCGAGAGCAGCAGCTCTATGCGCTACTATAATGACCATTATACCCCTACGTGATAG...5’ promoter i. Mutant A has a single base pair substitution with the T/A being replaced with C/G base pair at position 35 (position denoted by the * in the sequence above). ii. Mutant B has a 2 G/C pairs inserted between position 19 and 20 (position denoted by the ^ in the sequence above).arrow_forward
- . The production of pigment in the outer layer of seedsof corn requires each of the three independently assorting genes A, C, and R to be represented by at leastone dominant allele, as specified in Problem 64. Thedominant allele Pr of a fourth independently assortinggene is required to convert the biochemical precursorinto a purple pigment, and its recessive allele pr makesthe pigment red. Plants that do not produce pigmenthave yellow seeds. Consider a cross of a strain of genotype A/A ; C/C ; R/R ; pr/pr with a strain of genotypea/a ; c/c ; r/r ; Pr/Pr.a. What are the phenotypes of the parents?b. What will be the phenotype of the F1?c. What phenotypes, and in what proportions, willappear in the progeny of a selfed F1?d. What progeny proportions do you predict from thetestcross of an F1?arrow_forwardl Metro by T-Mobile 1 2:29 PM • 16% I In flies, long wings are a dominant trait, and short wings are a recessive trait. Medium wings are the heterozygous trait. Based on this information, if a homozygous long-winged fly is crossed with another a heterozygous'fly, their offspring will have which percentages for long, medium, and short wings? Assume random chromosome segregation. 17) A) 25% long, 75% medium, 0% short B) 50% long, 25% medium, 25% short 50% long, 50% medium, 0% short D) 100% medium, 0% long, 0% shortarrow_forwardEC4. In a test-cross of trihybrid drosophila the following phenotypes and number of offspring were found. Without doing any calculations, answer the following questions: +++ 669 abc 653 ++c 121 ab+ 139 +b+ 2280 a+c 2215 +bc 3 a++ 2 a) What were the genotypes of the parental strains? (fill in) b). What is the gene order?arrow_forward
- AaBbCc x AaBbcc How would you characterize this kind of relationship between the genes: A-B- (gray); A-bb (yellow); aaB- (black); aabb (cream) The CC and Cc genotypes allow color according to the expression of the A and B alleles. However, the cc genotype results in albino rats regardless of the A and B alleles presentarrow_forwardQ. The nuclear membrane disintegrates late in prophase of mitosis in most eukaryotic cells. Once the membrane is reformed in telophase in a daughter cell, several components of gene expression might therefore be “caught” out in the cytoplasm when they would otherwise only ever be found inside the nucleus. Consider where the following components of gene expression are made and where they function. Which component is normally never found in the cytoplasm outside the nucleus? spliced intron RNA polymerase snRNA DNA polymerase A. 1, 2 and 3 B. 1 and 3 C. 2 and 4 D. 4 only E. All of 1, 2, 3 & 4 are correctarrow_forward. In the plant Arabidopsis thaliana, a geneticist is interested in the development of trichomes (small projections). A large screen turns up two mutant plants (A and B) that have no trichomes, and these mutants seem to be potentially useful in studying trichome development. (If they were determined by single-gene mutations, then finding the normal and abnormal functions of these genes would be instructive.) Each plant is crossed with wild type; in both cases, the next generation (F1) had normal trichomes. When F1 plants were selfed, the resulting F2’s were as follows: F2 from mutant A: 602 normal; 198 no trichomes F2 from mutant B: 267 normal; 93 no trichomesa. What do these results show? Include proposed genotypes of all plants in your answer. b. Under your explanation to part a, is it possible to confidently predict the F1 from crossing the original mutant A with the original mutant B?arrow_forward
- 10. Fur colour in mice is an example of the effects of interaction between different genes. Wild type mice have agouti fur where the individual hairs are black with a yellow band producing the typical grey-like colour of agouti fur. Two different independently segregating genes are involved in the expression of coat colour: • A single gene with two alleles, A and a, determines the colour of the coat; Agouti (AA or Aa) is dominant over black (aa). • A different gene is required for the hair pigment to be synthesised and therefore expressed. When the dominant allele of this gene is present (C), pigment is roduced and the agouti and black phenotypes can be expressed. A null allele (c, which produces an inactive form of the enzyme for pigment production) is recessive; when in the homozygous form (cc), no pigment is produced and the mice are albino. a) Write down the colour of the coat of mice with the following genotypes: Genotype Phenotype aaCc b)Consider the following cross: Parents…arrow_forward. The human IGF2 gene is autosomal and maternallyimprinted. Copies of the gene received from themother are not expressed, but copies received fromthe father are expressed. You have found two allelesof this gene that encode two different forms of theIGF2 protein distinguishable by gel electrophoresis.One allele encodes a 60K (Kilodalton) blood protein;the other allele encodes a 50K blood protein. In ananalysis of blood proteins from a couple named Billand Joan, you find only the 60K protein in Joan’sblood and only the 50K protein in Bill’s blood. Youthen look at their children: Jill is producing only the50K protein, while Bill Jr. is producing only the 60Kprotein.a. With these data alone, what can you say about theIGF2 genotype of Bill Sr. and Joan?b. Bill Jr. and a woman named Sara have two children, Pat and Tim. Pat produces only the 60K protein and Tim produces only the 50K protein. Withthe accumulated data, what can you now say aboutthe genotypes of Joan and Bill Sr.?arrow_forward10. Fur colour in mice is an example of the effects of interaction between different genes. Wild type mice have agouti fur where the individual hairs are black with a yellow band producing the typical grey-like colour of agouti fur. Two different independently segregating genes are involved in the expression of coat colour: • A single gene with two alleles, A and a, determines the colour of the coat; Agouti (AA or Aa) is dominant over black (aa). • A different gene is required for the hair pigment to be synthesised and therefore expressed. When the dominant allele of this gene is present (C), pigment is produced and the agouti and black phenotypes can be expressed. A null allele (c, which produces an inactive form of the enzyme for pigment production) is recessive; when in the homozygous form (cc), no pigment is produced and the mice are albino. a) Write down the colour of the coat of mice with the following genotypes: Genotype Phenotype aaCc b) Consider the following cross: Parents…arrow_forward
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