Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 17, Problem 71A
Interpretation Introduction

Interpretation:

The concentration of hydrogen iodide is to be calculated.

Concept introduction:

The equilibrium constant is the ratio of molar concentration of products to the reactants. It is represented by Keq.

The formula is given as: there is a chemical reaction

    aA+BbcC+dD     

Keq=    [C]C[D][A]a[B]b

Where, [C] and [D] = molar concentration of products

[A] and [B] = molar concentration of reactants

a, b, c, and d are number of molecules.

Expert Solution & Answer
Check Mark

Answer to Problem 71A

The value of equilibrium constant (Keq) is 3.24×10-3mol/L.

Explanation of Solution

Given information: the given reaction is

2HI(g)H2(g) + I2(g)

[H2] = 2.44×10-3 mol/L

[I2] = 7.18×10-5 mol/L

Keq=1.67×10-2

According to the Le Chatelier’s principle, the equilibrium constant is the ratio of molar concentration of products to the molar concentration of reactants. It is represented by Keq.

Keq =  [H2] [I2]   [HI]2[HI]2=[H2] [I2]Keq=2.44×10-3×7.18×10-51.67×10-2=17.52×10-61.67=10.5×10-6

Or, [HI]=10.5×10-6=3.24×10-3M

The concentration of hydrogen iodide is 3.24×10-3M.

Conclusion

The concentration of hydrogen iodide is 3.24×10-3M.

Chapter 17 Solutions

Chemistry: Matter and Change

Ch. 17.1 - Prob. 11SSCCh. 17.1 - Prob. 12SSCCh. 17.2 - Prob. 13SSCCh. 17.2 - Prob. 14SSCCh. 17.2 - Prob. 15SSCCh. 17.2 - Prob. 16SSCCh. 17.2 - Prob. 17SSCCh. 17.3 - Prob. 18PPCh. 17.3 - Prob. 19PPCh. 17.3 - Prob. 20PPCh. 17.3 - Prob. 21PPCh. 17.3 - Prob. 22PPCh. 17.3 - Prob. 23PPCh. 17.3 - Prob. 24PPCh. 17.3 - Prob. 25PPCh. 17.3 - Prob. 26PPCh. 17.3 - Prob. 27SSCCh. 17.3 - Prob. 28SSCCh. 17.3 - Prob. 29SSCCh. 17.3 - Prob. 30SSCCh. 17.3 - Prob. 31SSCCh. 17.3 - Prob. 32SSCCh. 17 - Prob. 33ACh. 17 - Prob. 34ACh. 17 - Prob. 35ACh. 17 - Prob. 36ACh. 17 - Prob. 37ACh. 17 - Prob. 38ACh. 17 - Prob. 39ACh. 17 - Prob. 40ACh. 17 - Prob. 41ACh. 17 - Prob. 42ACh. 17 - Prob. 43ACh. 17 - Prob. 44ACh. 17 - Prob. 45ACh. 17 - Prob. 46ACh. 17 - Prob. 47ACh. 17 - Prob. 48ACh. 17 - Prob. 49ACh. 17 - Prob. 50ACh. 17 - Prob. 51ACh. 17 - Prob. 52ACh. 17 - Prob. 53ACh. 17 - Prob. 54ACh. 17 - Prob. 55ACh. 17 - Prob. 56ACh. 17 - Prob. 57ACh. 17 - Prob. 58ACh. 17 - Prob. 59ACh. 17 - Prob. 60ACh. 17 - Prob. 61ACh. 17 - Prob. 62ACh. 17 - Prob. 63ACh. 17 - Prob. 64ACh. 17 - Why are compounds such as sodium chloride usually...Ch. 17 - Prob. 66ACh. 17 - Prob. 67ACh. 17 - Prob. 68ACh. 17 - Prob. 69ACh. 17 - Prob. 70ACh. 17 - Prob. 71ACh. 17 - Prob. 72ACh. 17 - Prob. 73ACh. 17 - Prob. 74ACh. 17 - Prob. 75ACh. 17 - Prob. 76ACh. 17 - Prob. 77ACh. 17 - Prob. 78ACh. 17 - Evaluate this statement: A low value for Keq means...Ch. 17 - Prob. 80ACh. 17 - Prob. 81ACh. 17 - Prob. 82ACh. 17 - Prob. 83ACh. 17 - Prob. 84ACh. 17 - Prob. 85ACh. 17 - Prob. 86ACh. 17 - Prob. 87ACh. 17 - Prob. 88ACh. 17 - Prob. 89ACh. 17 - Prob. 90ACh. 17 - Prob. 91ACh. 17 - Prob. 92ACh. 17 - Prob. 93ACh. 17 - Prob. 94ACh. 17 - Prob. 95ACh. 17 - Prob. 96ACh. 17 - Prob. 97ACh. 17 - Prob. 98ACh. 17 - Prob. 99ACh. 17 - Prob. 100ACh. 17 - Prob. 101ACh. 17 - Prob. 102ACh. 17 - Prob. 103ACh. 17 - Prob. 104ACh. 17 - Prob. 105ACh. 17 - Prob. 1STPCh. 17 - Prob. 2STPCh. 17 - Prob. 3STPCh. 17 - Prob. 4STPCh. 17 - Prob. 5STPCh. 17 - Prob. 6STPCh. 17 - Prob. 7STPCh. 17 - Prob. 8STPCh. 17 - Prob. 9STPCh. 17 - Prob. 10STPCh. 17 - Prob. 11STPCh. 17 - Prob. 12STPCh. 17 - Prob. 13STPCh. 17 - Prob. 14STPCh. 17 - Prob. 15STPCh. 17 - Prob. 16STPCh. 17 - Prob. 17STPCh. 17 - Prob. 18STP
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