Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 17, Problem 47A
Interpretation Introduction

Interpretation:

The molar concentration of manganese in the cube is to be calculated

Concept introduction:

The molar concentration is ratio of number of moles of solute dissolved per unit volume of the solution.

M=nV

Where, n = Number of moles of solute

V = Volume of the solution

Expert Solution & Answer
Check Mark

Answer to Problem 47A

The molar concentration of manganese cube is 1.35×102mol/L.

Explanation of Solution

Given information is: edge of the cube = 5.25cm

Mass of the manganese cube = 1076.6g

Volume of the cube,

V=(5.25)3=144.70×10-3

And, number of moles,

n=1076.654.938=19.6

The molar concentration is ratio of number of moles of solute dissolved per unit volume of the solution.

M=nV

Where, n = Number of moles of solute

V = Volume of the solution

M=19.6144.7×10-3=0.135×103=1.35×102mol/L

The molar concentration of manganese cube is 1.35×102mol/L.

Conclusion

The molar concentration of manganese cube is 1.35×102mol/L.

Chapter 17 Solutions

Chemistry: Matter and Change

Ch. 17.1 - Prob. 11SSCCh. 17.1 - Prob. 12SSCCh. 17.2 - Prob. 13SSCCh. 17.2 - Prob. 14SSCCh. 17.2 - Prob. 15SSCCh. 17.2 - Prob. 16SSCCh. 17.2 - Prob. 17SSCCh. 17.3 - Prob. 18PPCh. 17.3 - Prob. 19PPCh. 17.3 - Prob. 20PPCh. 17.3 - Prob. 21PPCh. 17.3 - Prob. 22PPCh. 17.3 - Prob. 23PPCh. 17.3 - Prob. 24PPCh. 17.3 - Prob. 25PPCh. 17.3 - Prob. 26PPCh. 17.3 - Prob. 27SSCCh. 17.3 - Prob. 28SSCCh. 17.3 - Prob. 29SSCCh. 17.3 - Prob. 30SSCCh. 17.3 - Prob. 31SSCCh. 17.3 - Prob. 32SSCCh. 17 - Prob. 33ACh. 17 - Prob. 34ACh. 17 - Prob. 35ACh. 17 - Prob. 36ACh. 17 - Prob. 37ACh. 17 - Prob. 38ACh. 17 - Prob. 39ACh. 17 - Prob. 40ACh. 17 - Prob. 41ACh. 17 - Prob. 42ACh. 17 - Prob. 43ACh. 17 - Prob. 44ACh. 17 - Prob. 45ACh. 17 - Prob. 46ACh. 17 - Prob. 47ACh. 17 - Prob. 48ACh. 17 - Prob. 49ACh. 17 - Prob. 50ACh. 17 - Prob. 51ACh. 17 - Prob. 52ACh. 17 - Prob. 53ACh. 17 - Prob. 54ACh. 17 - Prob. 55ACh. 17 - Prob. 56ACh. 17 - Prob. 57ACh. 17 - Prob. 58ACh. 17 - Prob. 59ACh. 17 - Prob. 60ACh. 17 - Prob. 61ACh. 17 - Prob. 62ACh. 17 - Prob. 63ACh. 17 - Prob. 64ACh. 17 - Why are compounds such as sodium chloride usually...Ch. 17 - Prob. 66ACh. 17 - Prob. 67ACh. 17 - Prob. 68ACh. 17 - Prob. 69ACh. 17 - Prob. 70ACh. 17 - Prob. 71ACh. 17 - Prob. 72ACh. 17 - Prob. 73ACh. 17 - Prob. 74ACh. 17 - Prob. 75ACh. 17 - Prob. 76ACh. 17 - Prob. 77ACh. 17 - Prob. 78ACh. 17 - Evaluate this statement: A low value for Keq means...Ch. 17 - Prob. 80ACh. 17 - Prob. 81ACh. 17 - Prob. 82ACh. 17 - Prob. 83ACh. 17 - Prob. 84ACh. 17 - Prob. 85ACh. 17 - Prob. 86ACh. 17 - Prob. 87ACh. 17 - Prob. 88ACh. 17 - Prob. 89ACh. 17 - Prob. 90ACh. 17 - Prob. 91ACh. 17 - Prob. 92ACh. 17 - Prob. 93ACh. 17 - Prob. 94ACh. 17 - Prob. 95ACh. 17 - Prob. 96ACh. 17 - Prob. 97ACh. 17 - Prob. 98ACh. 17 - Prob. 99ACh. 17 - Prob. 100ACh. 17 - Prob. 101ACh. 17 - Prob. 102ACh. 17 - Prob. 103ACh. 17 - Prob. 104ACh. 17 - Prob. 105ACh. 17 - Prob. 1STPCh. 17 - Prob. 2STPCh. 17 - Prob. 3STPCh. 17 - Prob. 4STPCh. 17 - Prob. 5STPCh. 17 - Prob. 6STPCh. 17 - Prob. 7STPCh. 17 - Prob. 8STPCh. 17 - Prob. 9STPCh. 17 - Prob. 10STPCh. 17 - Prob. 11STPCh. 17 - Prob. 12STPCh. 17 - Prob. 13STPCh. 17 - Prob. 14STPCh. 17 - Prob. 15STPCh. 17 - Prob. 16STPCh. 17 - Prob. 17STPCh. 17 - Prob. 18STP
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY