
(a)
To find: The graph for the paths of both the particle and the number of intersection in the path.
(a)

Answer to Problem 41E
The number of intersection is two and the required graph is shown in Figure 1
Explanation of Solution
Given:
The position of the particle at time t is,
x1=3sinty1=2cost
The range of the time t is,
0≤t≤2π
The position of the second particle is,
x2=−3+costy2=1+sint
Calculation:
Consider the position of the first particle is,
x1=3sinty1=2cost
Consider the position of the second particle is,
x2=−3+costy2=1+sint
The sketch for the path of both the particle is shown in Figure 1
Figure 1
From the above figure it is clear that the number of intersection is 2
(b)
To find: Whether any of the points are the point of collision, if yes than find the collision points.
(b)

Answer to Problem 41E
There is only one collision point s (−3,0) at time 3π2 .
Explanation of Solution
Given:
The position of the particle at time t is,
x1=3sinty1=2cost
The range of the time t is,
0≤t≤2π
The position of the second particle is,
x2=−3+costy2=1+sint
Calculation:
From figure 1, the points of intersection are at,
(−3,0)
Consider the position x is,
x=3sint
Then, the time for the particle for collision is,
x=3sint−3=3sintt=3π2
Consider the position of the particle is,
x2=−3+cost
Then,
x2=−3+cost−3=−3+costcost=0t=π2,3π2,5π2
From figure 1, the other points of intersection are at,
(−2.1,1.4)
Consider the position of the first particle is,
x1=3sint
Then,
−2.1=3sintsint=(−2.12)t=−0.78
Consider the position of the second particle is,
x2=−3+cost
Then,
−2.7=−3+costcost=0.9t=3π2
The time for both the particle is not same then there is only one collision point that is,
(−3,0) at time 3π2
(b)
To find: The scenario for the give path of the second particle.
(b)

Answer to Problem 41E
The position of the particle changes to (3,1) and the point of intersection are (3,0),(2.1,1.4) .
Explanation of Solution
Given:
The range of the time t is,
0≤t≤2π
The position of the second particle is,
x2=3+costy2=1+sint
Calculation:
Consider position of the second particle is,
x2=3+costy2=1+sint
For the above position the centre of the particle is,
(3,1)
The point of intersection of the particle is,
(3,0),(2.1,1.4)
Chapter 1 Solutions
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