
Concept explainers
(a)
To match: The equation y=x2 with its graph without using a computer or graphing calculator.
(a)

Answer to Problem 3E
The equation y=x2 is match with the graph h.
Explanation of Solution
The equation y=x2 represents a polynomial function that is quadratic in nature. For the null value of x, the value of y is zero, so the graph of the equation passes through the origin (0,0) and symmetric about y-axis. Thus, the graph of y=x2 is shown below in Figure 1.
From Figure 1, it can be concluded that the equation y=x2 matches with the graph h.
(b)
To match: The equation y=x5 with its graph without using a computer or graphing calculator.
(b)

Answer to Problem 3E
The equation y=x5 is match with the graph f.
Explanation of Solution
The equation y=x5 represents an odd polynomial function of degree 5. For the null value of x, the value of y is zero, so the graph of the equation passes through the origin (0,0). Since the function is odd, it is symmetric about the origin. Thus, the graph of an odd polynomial function of degree 5 is shown below in Figure 2.
From Figure 2, it can be concluded that the equation y=x5 matches with the graph f.
(c)
To match: The equation y=x8 with its graph without using a computer or graphing calculator.
(c)

Answer to Problem 3E
Solution:
The equation y=x8 is match with the graph g.
Explanation of Solution
The equation y=x8 represents an even polynomial function. For the null value of x, the value of y is zero, so the graph of the equation passes through the origin (0,0). Since the function is even, it is symmetric about y-axis. Thus, the graph of an even polynomial function of degree 8 is shown below in Figure 3.
From Figure 3, it can be concluded that the equation y=x8 matches with the graph g.
Chapter 1 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
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