Chapter 17, Problem 41A

To determine

The angle of the reflection, and the angle between the incident ray and the reflected ray.

Answer to Problem 41A

  $53°$ and $106°$ , respectively

Explanation of Solution

Given:

The angle made by the incident ray with the normal, ${\theta }_i=53°$

Formula used:

For the mirror,

  $\begin{array}{c}\text{angle of incidence = angle of reflection}\\ {\theta }_i={\theta }_r\end{array}$

Calculation:

Then, using the property of mirrors, angle of reflection will be,

  ${\theta }_r={\theta }_i=53°$

And, the angle between the incident and the reflected ray will be,

  $\begin{array}{c}{\theta }_t={\theta }_i+{\theta }_r\\ =53°+53°\\ =106°\end{array}$

Conclusion:

Hence, the angle of the reflection is $53°$ , and the angle between the incident ray and the reflected ray is $106°$ .