Becker's World of the Cell (9th Edition)
9th Edition
ISBN: 9780321934925
Author: Jeff Hardin, Gregory Paul Bertoni
Publisher: PEARSON
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Chapter 17, Problem 17.2CC
Nonhomologous end-joining and synthesis-dependent strand annealing are both strategies eukaryotes use to repair double-strand breaks in DNA. Because SDSA is error-free and NHEJ is error-prone, why don’t eukaryotic cells always use SDSA?
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Chapter 17 Solutions
Becker's World of the Cell (9th Edition)
Ch. 17 - The theoretical amplification accomplished by n...Ch. 17 - Bacterial replication and that in typical...Ch. 17 - Nonhomologous end-joining and synthesis-dependent...Ch. 17 - Prob. 17.3CCCh. 17 - Meselson and Stahl Revisited. For each of the...Ch. 17 - DNA Replication. Sketch a replication fork of...Ch. 17 - More DNA Replication. The following are...Ch. 17 - QUANTITATIVE Still More DNA Replication. Suppose...Ch. 17 - The Minimal Chromosome. To enable it to be...Ch. 17 - Prob. 17.6PS
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- Why would a mutation in a somatic cell of a multicellular organism escape detection?arrow_forwardCytosine can be deaminated to form Uracil What type of mutation is this classified as? Discuss what happens to the base-pairing properties from switching from C to U? When U is replicated in two rounds of synthesis, what substitution does this result in? Before Uracil alters the DNA during replication, what repair system can be used to correct this error? Describe how this type of DNA repair works?arrow_forwardTwo pathways, homologous recombination and nonhomologous end joining (NHEJ), can repair double-strandbreaks in DNA. If homologous recombination is an errorfree pathway whereas NHEJ is not always error free, whyis NHEJ used most of the time in eukaryotes?arrow_forward
- The sequences of DNA bases below represent parts of the genes responsible for the production of one type of protein, an enzyme, produced by Botana curus and Species X, Y, and Z Under each DNA sequence, write the complementary messenger RNA base sequences that each of these gene fragments would produce. Note: Unlike during DNA replication, in the production of messenger RNA, the DNA base “A” specifies the RNA base “U.”. Use the universal genetic code table provided (see Universal Code attachment) to translate the messenger RNA base sequences into sequences of amino acids in the protein produced by each species. Write the sequences of amino acids under the messenger RNA sequences.arrow_forwardA pyrimidine dimer which is a bulky lesion has mutated an E. coli cell's DNA. Describe both the photoreactivation enzyme repair (PRE) and Nucleotide excision repair describe how the cell uses Uvr A, B, C, D gene products to effect repair.arrow_forwardThe E coli cell contains 107 non-specific DNA binding sites for R, 10 R molecules, and 1 Operator. And the mechanism of specific binding of R to O works well with these concentrations. Would it work if R = 1? Explain with a calculation.arrow_forward
- Many of the gene products involved in DNA synthesis were initially defined by studying mutant E. coli strains that could not synthesize DNA. (a) The dnaE gene encodes the a subunit of DNA polymerase III. What effect is expected from a mutation in this gene? How could the mutant strain be maintained? (b) The dnaQ gene encodes the e subunit of DNA polymerase. What effect is expected from a mutation in this gene?arrow_forwardConsidering that prokaryote genomes do not have large introns, how is it possible to move a eukaryotic gene into a transformed bacterium, since they lack a spliceosome?arrow_forwardExtreme UV exposure leads to the SOS response in bacteria. By what mechanism does the SOS response function? Answer choices induction of photolyase and the addition of white light to remove the thymine dimer destruction of lexA, which leads to expression of an alternate, error-prone DNA polymerase homologous recombination repair non-homologous end joining exinuclease removal of a segment of DNA including a thymine dimer, followed by the replacement of DNA using the complementary strand of DNAarrow_forward
- Considering prokaryotes, what is the enzyme that helps hold DNA polymerase III in place when nucleotides are being added?arrow_forwardWhat distinguishes topoisomerase type I from topoisomerase type II (“gyrase”) in E. coli bacteria? Both types of topoisomerases participate in the formation of nucleosomes. Topoisomerase type I cleaves one strand of a DNA duplex to remove DNA supercoils, and topoisomerase type II cleaves both strands of the DNA duplex when introducing negative supercoils into the molecule. Topoisomerase type I works to replicate DNA and topoisomerase type II works to transcribe RNA. Topoisomerase type I works on double-stranded DNA, and topoisomerase type II ("gyrase") works on single-stranded DNA. Topoisomerase type I adds negative DNA supercoils, and topoisomerase type II removes them.arrow_forwardSupercoiled DNA is slightly unwound compared to relaxed DNA and this enables it to assume a more compact structure with enhanced physical stability. Describe the enzymes that control the number of supercoils present in the E. coli chromosome. How much would you have to reduce the linking number to increase the number of supercoils by five?arrow_forward
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license