Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 16, Problem 71SDP
To determine
Explain the reason behind sheet has a lower limiting drawing ratio than it had before being annealed. However, in order to improve its ductility, a coil of sheet metal is placed in a furnace and annealed.
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5) A steel specimen of rectangular cross section with 120 mm width, 180 mm
thickness and 90 mm height was upset at room temperature by open-die forging to
a height of 55 mm. If the strength coefficient and strain hardening exponent of this
material were 1015 MPa and 0.17 respectively, the coefficient of friction is 0.2, and
assuming that the thickness would not change during forging; determine the
required upsetting force at the end of stroke.
5) In order to improve its ductility, a coil of sheet metal is placed in a furnace and
annealed. However, it is observed that the sheet has a lower limiting drawing ratio
than it had before being annealed. Explain the reasons for this behavior.
A stainless steel part is blanked from a larger sheet (0.5m wide, 1.0m long, 0.004m thick). Determine the tonnage (force) requirement for the blanking operation if the material shear strength is 600 MPa.
Chapter 16 Solutions
Manufacturing Engineering & Technology
Ch. 16 - How does sheet-metal forming differ from rolling,...Ch. 16 - What causes burrs? How can they be reduced or...Ch. 16 - Prob. 3RQCh. 16 - Describe the difference between compound,...Ch. 16 - Describe the characteristics of sheet metals that...Ch. 16 - Describe the features of forming-limit diagrams...Ch. 16 - List the properties of materials that influence...Ch. 16 - Give one specific application for each of the...Ch. 16 - Why do tubes buckle when bent? What is the effect...Ch. 16 - Define normal anisotropy, and explain why it is...
Ch. 16 - Describe earing and why it occurs.Ch. 16 - What are the advantages of rubber forming? Which...Ch. 16 - Explain the difference between deep drawing and...Ch. 16 - How is roll forming fundamentally different from...Ch. 16 - What is nesting? What is its significance?Ch. 16 - Describe the differences between compound,...Ch. 16 - What is microforming?Ch. 16 - Explain the advantages of superplastic forming.Ch. 16 - What is hot stamping? For what materials is it...Ch. 16 - What is springback? What is negative springback?Ch. 16 - Explain the differences that you have observed...Ch. 16 - Take any three topics from Chapter 2, and, with...Ch. 16 - Do the same as for Problem 16.22, but for Chapter...Ch. 16 - Identify the material and process variables that...Ch. 16 - Explain why springback in bending depends on yield...Ch. 16 - Explain why cupping tests may not predict well the...Ch. 16 - Identify the factors that influence the...Ch. 16 - Why are the beads in Fig. 16.36b placed in those...Ch. 16 - A general rule for dimensional relationships for...Ch. 16 - Section 16.2 stated that the punch stripping force...Ch. 16 - Is it possible to have ironing take place in an...Ch. 16 - Note the roughness of the periphery of the flanged...Ch. 16 - What recommendations would you make in order to...Ch. 16 - It has been stated that the quality of the sheared...Ch. 16 - Give several specific examples from this chapter...Ch. 16 - As you can see, some of the operations described...Ch. 16 - Through changes in clamping or die design, it is...Ch. 16 - How would you produce the part shown in Fig....Ch. 16 - It has been stated that the thicker the sheet...Ch. 16 - Prob. 41QTPCh. 16 - Calculate the value of R in Problem 16.41. Will...Ch. 16 - Estimate the limiting drawing ratio for the...Ch. 16 - Using Eq. (16.15) and the K value for TNT, plot...Ch. 16 - Section 16.5 states that the k values in bend...Ch. 16 - For explosive forming, calculate the peak pressure...Ch. 16 - Measure the respective areas of the solid outlines...Ch. 16 - Plot Eq. (16.6) in terms of the elastic modulus,...Ch. 16 - What is the minimum bend radius for a 1.0-mm-thick...Ch. 16 - Survey the technical literature and explain the...Ch. 16 - Using the data in Table 16.3 and referring to Eq....Ch. 16 - What is the force required to punch a square hole...Ch. 16 - In Case Study 16.2, it was stated that the reason...Ch. 16 - A cup is being drawn from a sheet metal that has a...Ch. 16 - Prob. 55QTPCh. 16 - Figure P16.57 shows a parabolic profile that will...Ch. 16 - Prob. 59SDPCh. 16 - Consider several shapes to be blanked from a large...Ch. 16 - Prob. 61SDPCh. 16 - Many axisymmetric missile bodies are made by...Ch. 16 - Metal cans are either two-piece (in which the...Ch. 16 - The design shown in Fig. P16.65 is proposed for a...Ch. 16 - Suggest consumer-product designs that could...Ch. 16 - How would you produce the part shown in Fig. 16.44...Ch. 16 - Using a ball-peen hammer, strike the surface of...Ch. 16 - Inspect a common paper punch and observe the shape...Ch. 16 - Obtain an aluminum beverage can and slit it in...Ch. 16 - Prob. 71SDPCh. 16 - Prob. 73SDPCh. 16 - On the basis of experiments, it has been suggested...Ch. 16 - Design a box that will contain a 4-in. 6-in. ...Ch. 16 - Repeat Problem 16.77, but design the box from a...
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- A compound die will be used to blank and punch a large washer out of 6061ST aluminum alloy sheet stock 3.50 mm thick. The outside diameter of the washer is 50.0 mm and the inside diameter is 15.0 mm. if The aluminum sheet metal has a tensile strength = 310 MPa, a strength coefficient of 350 MPa, and a strain-hardening exponent of 0.12. (a) Assume that blanking and punching occur simultaneously. (b) Assume the punches are staggered so that punching occurs first, then blanking. Determine (1) the punch and die sizes for the blanking operation, and (2) the punch and die sizes for the punching operation.(3) the minimum tonnage press to perform the blanking and punching operationarrow_forwardA 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively Calculate the true strain at the end of the rolling process.arrow_forwardA 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively. Calculate the length of the sheet after the rolling operation in feet.arrow_forward
- Write a detailed note on "Hydrostatic Extrusion". Also draw diagrams to explain the process of hydrostatic extrusion.arrow_forwardA cup of 5o mm diameter and 20 mm height is to be produced by drawing from a 1.5 mm thick sheet metal. What is the maximum drawing force ? If ultimate tensile strength of metal is 650 MPa.arrow_forward1 What is the difference between open-die and closed-die forging? Give an example of a metal product produced by each process.arrow_forward
- An austenitic stainless steel plate with a width of 100 mm, a length of 150 mm and a thickness of 50 mm is to be hot forged in a hydraulic press so that the width remains constant. If it is to be reduced in one step to a thickness of 40 mm, calculatea) the actual load that needs to be applied at the end of the forging, as well as b) the corresponding deformation energy. In previous plane strain compression tests, it was found that the material exhibits an average plane strain yield stress of 80 MPa at the forging temperature. Assume that the efficiency of the process is 0.6 Answer: Pfr= 2.5 MN ; WTr= 25 kJarrow_forwardIn a wire drawing operation diameter of a steel wire is reduced from 10 mm to 8 mm. The mean flow stress of the material is 400 MPa.what is the ideal force required for drawing (ignoring friction and redundant work).?arrow_forwardAn open die forging operation is performed to produce a steel cylinder with a diameter of 9.7mm and a height of 1.7mm. The strength coefficient for this steel is 500MPA, and the strain hardening exponent is 0.25. Coefficient of friction at the die-work interface is 0.12. The initial stock of raw material has a diameter of 5mm. (a) What height/length of stock is needed to provide sufficient volume of material for this forging operation? (b) Compute the maximum force that the punch must apply to form the head in this open- die operation.arrow_forward
- A blank workpiece with 200 mm diameter is to be blanked from 3.2- mm-thick half-hard stainless steel (ultimate tensile strength of 650 MPa). Find (a) the diameters of blank die and punch, and (b) blanking force.arrow_forwardA cylindrical brass rod with a minimum tensile strength of 450 MPa, a ductility of at least 13% EL (elongation), and a final diameter of 12.7mm is required. You have in your inventory some 19.0mm diameter brass stock that has been cold worked to 35%. Assuming that the cross section of the rod is still circular after being cold worked, and that brass experiences cracking at 65% CW, describe the necessary working steps in order to achieve the final product. Take the expression for % cold work to be = (Ao - Af)/ Ao x 100%, where Ao and Af are the original and final circular cross-sectional areas of the rod.arrow_forward3) Which advantages, disadvantages and characteristic properties does hot working Lelative to cold working have?( Explain basic operations in bulk deformation. shortly (with using figures)(arrow_forward
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