Concept explainers
To find: Number of excess electron.
Answer to Problem 57GP
Explanation of Solution
Given:
Electric field of the earth =
Radius of water droplet
Formula used:
For the droplet to remain stationary, the magnitude of the electric force must be the same as the weight of the droplet which is given by,
r = radius of droplet
e = charge of electron
So number of electron is given by:
Calculation:
The radius of water
Electric field E=150N/c
The density of water
Acceleration due to gravity
The magnitude of electric force on the droplet,
Here charge on the water droplets is q and E is the electric field.
The weight of the water droplet (w)=mg
Here mass of the droplet
Therefore weight of the droplet
Let the number of excess electrons on the water droplet = n
The charge on the droplets
For the droplet to remain stationary, the magnitude of the electric force on the droplet must be the same as the weight of the droplets. Therefore from equation (1) and (2).
Substituting the values,
Conclusion:
The number of electrons water droplet contains is
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