Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 16, Problem 42P

(a)

To determine

The direction required for the electric field.

(a)

Expert Solution
Check Mark

Explanation of Solution

Introduction:

The electron will experience a force in the opposite direction of the electric field.

Since, the electron is to be brought to rest. The electric field must be in the same direction as the initial velocity of the electron. So, the required direction is right.

Conclusion:

Thus, the required direction is right.

(b)

To determine

The strength of the electric field.

(b)

Expert Solution
Check Mark

Answer to Problem 42P

The strength of the electric field is 640.5N/C .

Explanation of Solution

Given info:

The mass of the electron is m=9.11×1031kg .

The charge on electron is q=1.6×1019C .

The electric field is E=1.45×104N/C .

The space is S=4cm .

Formula used:

The initial speed of the electron is v0=0.01c .

The final speed of the electron is v=0 .

The negative acceleration is,

  a=eEme … (1)

So,

  v2=v022as0=v022asa=v022s … (2)

Equate the equation (1) and (2).

  eEme=v022sE=me(0.01c)22es

Calculation:

Substituting the given values, we get

  E=(9.11×1031)(0.01×3×108)22(1.6×1019)(4×103)N/C=640.5N/C

Conclusion:

Thus, the strength is 640.5N/C .

Chapter 16 Solutions

Physics: Principles with Applications

Ch. 16 - Prob. 11QCh. 16 - Prob. 12QCh. 16 - Prob. 13QCh. 16 - Prob. 14QCh. 16 - Prob. 15QCh. 16 - Prob. 16QCh. 16 - Prob. 17QCh. 16 - Assume that the two opposite charges in Fig....Ch. 16 - Consider the electric field at the three points...Ch. 16 - Why can electric field lines never cross?Ch. 16 - Show, using the three rules for field lines given...Ch. 16 - Given two point charges, Q and 2Q, a distance l...Ch. 16 - Consider a small positive test charge located on...Ch. 16 - A point charge is surrounded by a spherical...Ch. 16 - Prob. 1PCh. 16 - Prob. 2PCh. 16 - Prob. 3PCh. 16 - Prob. 4PCh. 16 - Prob. 5PCh. 16 - Prob. 6PCh. 16 - Prob. 7PCh. 16 - Prob. 8PCh. 16 - Prob. 9PCh. 16 - Prob. 10PCh. 16 - Prob. 11PCh. 16 - Prob. 12PCh. 16 - Prob. 13PCh. 16 - Prob. 14PCh. 16 - Prob. 15PCh. 16 - Prob. 16PCh. 16 - Prob. 17PCh. 16 - Prob. 18PCh. 16 - Prob. 19PCh. 16 - Prob. 20PCh. 16 - Prob. 21PCh. 16 - Prob. 22PCh. 16 - Prob. 23PCh. 16 - Prob. 24PCh. 16 - Prob. 25PCh. 16 - Prob. 26PCh. 16 - Prob. 27PCh. 16 - Prob. 28PCh. 16 - Prob. 29PCh. 16 - Prob. 30PCh. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Prob. 33PCh. 16 - Prob. 34PCh. 16 - Prob. 35PCh. 16 - Prob. 36PCh. 16 - Prob. 37PCh. 16 - Prob. 38PCh. 16 - Prob. 39PCh. 16 - Prob. 40PCh. 16 - Prob. 41PCh. 16 - Prob. 42PCh. 16 - Prob. 43PCh. 16 - Prob. 44PCh. 16 - Prob. 45PCh. 16 - Prob. 46PCh. 16 - Prob. 47PCh. 16 - Prob. 48PCh. 16 - Prob. 49PCh. 16 - Prob. 50PCh. 16 - Prob. 51PCh. 16 - Prob. 52GPCh. 16 - Prob. 53GPCh. 16 - Prob. 54GPCh. 16 - Prob. 55GPCh. 16 - Prob. 56GPCh. 16 - Prob. 57GPCh. 16 - Prob. 58GPCh. 16 - Prob. 59GPCh. 16 - Prob. 60GPCh. 16 - Prob. 61GPCh. 16 - Prob. 62GPCh. 16 - Prob. 63GPCh. 16 - Prob. 64GPCh. 16 - Prob. 65GPCh. 16 - Prob. 66GPCh. 16 - Prob. 67GPCh. 16 - Prob. 68GPCh. 16 - Prob. 69GPCh. 16 - Prob. 70GPCh. 16 - Prob. 71GPCh. 16 - Prob. 72GPCh. 16 - Prob. 73GP

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