Concept explainers
(a)
Interpretation:
The structure of the compound is to be drawn with the help of details obtained through the NMR spectra.
Concept introduction:
NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.
The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton lesser will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.
(b)
Interpretation:
The structure of the compound is to be given with the help of details obtained through the NMR spectra.
Concept introduction:
Many nuclei and electrons have spin; due to this spin magnetic moment arises. The energy of this magnetic moment depends on the orientation of the applied magnetic field.
In NMR spectroscopy, every nucleus has a spin. There is an
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ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
- Compound C has a molecular ion in its mass spectrum at 146 and a prominent absorption in its IR spectrum at 1762 cm. C shows the following 'H NMR spectral data: 1.47 (doublet, 3 H), 2.07 (singlet, 6 H), and 6.84 (quartet, 1 H) ppm. What is the structure of C?arrow_forward1 (a) In the following reactions, CI (1) LIAIH, A (2) H20 MCPBA (i) Draw the structure of compounds A and B. (ii) For each reaction, explain the type of reaction involved. (iii) Explain the successful transformation of compound A using mass spectra. (b) Complete the following reactions by filling in missing reactants or product. (i) (1) O3 (2) CH;SCH3 (ii) он (CH3)3(COOH) D Ti(OCH(CH3)2l4 (-)-DETarrow_forwardThe 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.arrow_forward
- An unknown compound has a molecular formula of C,H,O. Its IR spectrum shows prominent absorptions at 2980, 2960, and 1718 cm . It exhibits the following signals in its H NMR spectrum (ppm): 1.06 (triplet, 3H), 2.12 (singlet, 3H), 2.45 (quartet, 2H); and the following signals in its ¹3C NMR spectrum ( ppm): 7.6, 29.5, 36.8, 208.8. Draw the structure of the unknown compound. Click and drag to start drawing a structure. 0 X 0:0arrow_forwardCompound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forwardA compound with molecular formula C7H1402 upon hydrolysis produces an alcohol and an acid. It has the following (b) NMR data : 'H-NMR (at 298 K, 600 MHz, CDC13) : 80-92 (d, 6H), 1:52 (т, 2н), 1-69 (m, 1Н), 2-04 (s, ЗH) and 4-09 (t, 2H). 13 C-NMR : 8 21-0, 22:5, 25:1, 37.4, 63·1 and 171-2 ppm DEPT provided two inverted signals. Predict the structure of the alcohol that is obtained through hydrolysis of the mentioned parent compound. Assign appropriate IR values, 'H and 13C-NMR resonances along with a mass spectral pattern for the alcohol.arrow_forward
- Identify this compound from its proton NMR spectrum. The relative intensities of the two peaks is 3:2arrow_forwardIsomer set #1: CH3OCCH,CH3 CH3COCH,CH3 a b Compound D, CHgO2, shows a downfield singlet in its 'H-NMR spectrum. Is it compound a or b? Isomer set #2: CH3OCCH2CH3 CH3COCH2CH3 a b. Compound D, C,H8O2, shows a downficld quartet in its 'H-NMR spectrum. Is it compound a or b?arrow_forwardPhenacetin, a substance formerly used in over-the-counter headache remedies, has the formula C10H13NO2. Phenacetin is neutral and does not dissolve in either acid or base. When warmed with aqueous NaOH, phenacetin yields an amine, C8H11NO, whose 1H NMR spectrum is shown. When heated with HI, the amine is cleaved to an aminophenol, C6H7NO. What is the structure of phenacetin, and what are the structures of the amine and the aminophenol?arrow_forward
- Following are 1H-NMR spectra for compounds G, H, and I, each with the molecular formula C5H12O. Each is a liquid at room temperature, is slightly soluble in water, and reacts with sodium metal with the evolution of a gas. (a) Propose structural formulas of compounds G, H, and I. (b) Explain why there are four lines between 0.86 and 0.90 for compound G. (c) Explain why the 2H multiplets at 1.5 and 3.5 for compound H are so complex.arrow_forwardPropose a structural formula for the analgesic phenacetin, molecular formula C10H13NO2, based on its 1H-NMR spectrum.arrow_forwardCompound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning