Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 15.2, Problem 22SSC
Interpretation Introduction

Interpretation:

A procedure to determine the specific heat of a 45g piece of metal is to be described.

Concept introduction:

Heat capacity:The heat absorbed or released by a substance is dependent on three factors:

  1. The mass of the substance.
  2. The nature of the substance, its specific heat capacity.
  3. The change in temperature of the substance.

The unit of heat is Joules (J), specific heat capacity is J/(kg degree Celsius), and that of mass is kg.

Calorimeter: A device used to measure the amount of heat exchanged between an unknown substance and fixed amount of water present in it.

Expert Solution & Answer
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Answer to Problem 22SSC

Take a calorimeter with a fixed quantity of water at temperature Ti.

Drop the 45g metal at room temperature, t, into the calorimeter.

Record the change in temperature of the calorimeter when the metal comes in contact with the water. Let say the final temperature of water becomes Tf.

Since, the heat exchange is happening in an isolated system,

Qm=Qwatercm×45g×(tTf)=cwater×mwater×(TiTf)cm=cwater×mwater×(TiTf)45g×(tTf)

By substituting the recorded values of temperatures and mass of water, the specific heat of metal can be calculated.

Explanation of Solution

The experiment uses the fact that in an isolated system, the amount of heat released or absorbed is zero. The metal and water exchange heat inside the calorimeter and attain equilibrium. At equilibrium, the final temperature of both metal and water is the same. The known parameters like the amount of water, specific heat of water, room temperature, initial temperature of water, and final temperature can be substituted in the heat exchange formula to get the specific heat of the metal.

Conclusion

The specific heat of the 45g piece of metal can be calculated using the formula:

cm=cwater×mwater×(TiTf)45g×(tTf)

Chapter 15 Solutions

Chemistry: Matter and Change

Ch. 15.1 - Prob. 11SSCCh. 15.2 - Prob. 12PPCh. 15.2 - Prob. 13PPCh. 15.2 - Prob. 14PPCh. 15.2 - Prob. 15PPCh. 15.2 - Prob. 16SSCCh. 15.2 - Prob. 17SSCCh. 15.2 - Prob. 18SSCCh. 15.2 - Prob. 19SSCCh. 15.2 - Prob. 20SSCCh. 15.2 - Prob. 21SSCCh. 15.2 - Prob. 22SSCCh. 15.3 - Prob. 23PPCh. 15.3 - Prob. 24PPCh. 15.3 - Prob. 25PPCh. 15.3 - Prob. 26SSCCh. 15.3 - Prob. 27SSCCh. 15.3 - Prob. 28SSCCh. 15.3 - Prob. 29SSCCh. 15.3 - Prob. 30SSCCh. 15.3 - Prob. 31SSCCh. 15.4 - Prob. 32PPCh. 15.4 - Prob. 33PPCh. 15.4 - Prob. 34PPCh. 15.4 - Prob. 35PPCh. 15.4 - Prob. 36PPCh. 15.4 - Prob. 37PPCh. 15.4 - Prob. 38SSCCh. 15.4 - Prob. 39SSCCh. 15.4 - Prob. 40SSCCh. 15.4 - Prob. 41SSCCh. 15.4 - Prob. 42SSCCh. 15.4 - Prob. 43SSCCh. 15.5 - Prob. 44PPCh. 15.5 - Prob. 45PPCh. 15.5 - Prob. 46PPCh. 15.5 - Prob. 47PPCh. 15.5 - Prob. 48SSCCh. 15.5 - Prob. 49SSCCh. 15.5 - Prob. 50SSCCh. 15.5 - Prob. 51SSCCh. 15.5 - Prob. 52SSCCh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Metallurgy A 25.0-g bolt made of an alloy...Ch. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - How many joules of heat are lost by 3580 kg of...Ch. 15 - Swimming Pool A swimming pool measuring 20.0m12.5m...Ch. 15 - How much heat is absorbed by a 44.7-g piece of...Ch. 15 - Prob. 77ACh. 15 - Alloys When a 58.8-g piece of hot alloy is placed...Ch. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - sUse information from Figure 15.24 to calculate...Ch. 15 - Agriculture Water is sprayed on oranges during...Ch. 15 - Grilling What mass of propane (C3H8) must be...Ch. 15 - Heating with Coal How much heat is liberated...Ch. 15 - How much heat is evolved when 1255 g of water...Ch. 15 - A sample of ammonia (Hsolid=5.66kJ/mol)...Ch. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Heat was added consistently to a sample of water...Ch. 15 - Bicycling Describe the energy conversions that...Ch. 15 - Hiking Imagine that on a cold day you are planning...Ch. 15 - Differentiate between the enthalpy of formation of...Ch. 15 - Analyze both of the images in Figure 15.27 in...Ch. 15 - Apply Phosphorus trichloride is a starting...Ch. 15 - Calculate Suppose that two pieces of iron, one...Ch. 15 - Prob. 111ACh. 15 - sample of natural gas is analyzed and found to...Ch. 15 - Prob. 113ACh. 15 - Prob. 114ACh. 15 - Prob. 115ACh. 15 - Prob. 116ACh. 15 - Prob. 117ACh. 15 - Prob. 118ACh. 15 - Prob. 119ACh. 15 - Prob. 120ACh. 15 - Prob. 121ACh. 15 - Prob. 122ACh. 15 - Prob. 123ACh. 15 - Prob. 124ACh. 15 - Prob. 125ACh. 15 - Prob. 126ACh. 15 - Prob. 127ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STPCh. 15 - Prob. 11STPCh. 15 - Prob. 12STPCh. 15 - Prob. 13STPCh. 15 - Prob. 14STPCh. 15 - Prob. 15STPCh. 15 - Prob. 16STPCh. 15 - Prob. 17STPCh. 15 - Prob. 18STP
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