Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 15.2, Problem 16SSC
Interpretation Introduction

Interpretation:

The mathematical formula used to calculate the amount of heat absorbed or released by a substance when its temperature changes is to be explained.

Concept introduction:

The heat absorbed or released by a substance is dependent on three factors:

  1. The mass of the substance.
  2. The nature of the substance, its specific heat capacity.
  3. The change in temperature of the substance.

The unit of heat is Joules (J), specific heat capacity is J/(kg degree Celsius), and that of mass is kg.

Expert Solution & Answer
Check Mark

Answer to Problem 16SSC

The mathematical formula to calculate the heat absorbed or released by a substance when the temperature changes is,

Q=m×c×ΔT

Where,

Q is the heat released or absorbed,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the difference between the initial and the final temperatures.

Explanation of Solution

Imagine 1kg of a substance undergoes a temperature change from 10 degree Celsius to 20 degree Celsius. It has a specific heat capacity of 2J/kg°C.

The heat absorbed will be,

Q=m×c×ΔT

Here,

m=1kgc=2J/kg°CΔT=10°C20°C

So,

Q=1kg×(2J/kg°C)×(10°C-20°C)Q=1kg×(2J/kg°C)×(-10°C)Q=-20J

This explains the use of the formula.

Conclusion

The mathematical formula to calculate the heat absorbed or released by a substance when its temperature changes is,

Q=m×c×ΔT

Chapter 15 Solutions

Chemistry: Matter and Change

Ch. 15.1 - Prob. 11SSCCh. 15.2 - Prob. 12PPCh. 15.2 - Prob. 13PPCh. 15.2 - Prob. 14PPCh. 15.2 - Prob. 15PPCh. 15.2 - Prob. 16SSCCh. 15.2 - Prob. 17SSCCh. 15.2 - Prob. 18SSCCh. 15.2 - Prob. 19SSCCh. 15.2 - Prob. 20SSCCh. 15.2 - Prob. 21SSCCh. 15.2 - Prob. 22SSCCh. 15.3 - Prob. 23PPCh. 15.3 - Prob. 24PPCh. 15.3 - Prob. 25PPCh. 15.3 - Prob. 26SSCCh. 15.3 - Prob. 27SSCCh. 15.3 - Prob. 28SSCCh. 15.3 - Prob. 29SSCCh. 15.3 - Prob. 30SSCCh. 15.3 - Prob. 31SSCCh. 15.4 - Prob. 32PPCh. 15.4 - Prob. 33PPCh. 15.4 - Prob. 34PPCh. 15.4 - Prob. 35PPCh. 15.4 - Prob. 36PPCh. 15.4 - Prob. 37PPCh. 15.4 - Prob. 38SSCCh. 15.4 - Prob. 39SSCCh. 15.4 - Prob. 40SSCCh. 15.4 - Prob. 41SSCCh. 15.4 - Prob. 42SSCCh. 15.4 - Prob. 43SSCCh. 15.5 - Prob. 44PPCh. 15.5 - Prob. 45PPCh. 15.5 - Prob. 46PPCh. 15.5 - Prob. 47PPCh. 15.5 - Prob. 48SSCCh. 15.5 - Prob. 49SSCCh. 15.5 - Prob. 50SSCCh. 15.5 - Prob. 51SSCCh. 15.5 - Prob. 52SSCCh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Metallurgy A 25.0-g bolt made of an alloy...Ch. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - How many joules of heat are lost by 3580 kg of...Ch. 15 - Swimming Pool A swimming pool measuring 20.0m12.5m...Ch. 15 - How much heat is absorbed by a 44.7-g piece of...Ch. 15 - Prob. 77ACh. 15 - Alloys When a 58.8-g piece of hot alloy is placed...Ch. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - sUse information from Figure 15.24 to calculate...Ch. 15 - Agriculture Water is sprayed on oranges during...Ch. 15 - Grilling What mass of propane (C3H8) must be...Ch. 15 - Heating with Coal How much heat is liberated...Ch. 15 - How much heat is evolved when 1255 g of water...Ch. 15 - A sample of ammonia (Hsolid=5.66kJ/mol)...Ch. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Heat was added consistently to a sample of water...Ch. 15 - Bicycling Describe the energy conversions that...Ch. 15 - Hiking Imagine that on a cold day you are planning...Ch. 15 - Differentiate between the enthalpy of formation of...Ch. 15 - Analyze both of the images in Figure 15.27 in...Ch. 15 - Apply Phosphorus trichloride is a starting...Ch. 15 - Calculate Suppose that two pieces of iron, one...Ch. 15 - Prob. 111ACh. 15 - sample of natural gas is analyzed and found to...Ch. 15 - Prob. 113ACh. 15 - Prob. 114ACh. 15 - Prob. 115ACh. 15 - Prob. 116ACh. 15 - Prob. 117ACh. 15 - Prob. 118ACh. 15 - Prob. 119ACh. 15 - Prob. 120ACh. 15 - Prob. 121ACh. 15 - Prob. 122ACh. 15 - Prob. 123ACh. 15 - Prob. 124ACh. 15 - Prob. 125ACh. 15 - Prob. 126ACh. 15 - Prob. 127ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STPCh. 15 - Prob. 11STPCh. 15 - Prob. 12STPCh. 15 - Prob. 13STPCh. 15 - Prob. 14STPCh. 15 - Prob. 15STPCh. 15 - Prob. 16STPCh. 15 - Prob. 17STPCh. 15 - Prob. 18STP

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