Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 15, Problem 15.9P
To determine
Find the factor of safety
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A cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following.
a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?
A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.
Sand is placed on a rock slope, as shown in Figure Q2.
(a) Show that sand will be stable (i.e., no sliding sliding) if
Chapter 15 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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- Problem 1Explain whether the following are true or false. 1. A lower safety factor implies that a greater fraction of the shear strength is mobilized along the failure surface. 2. In an undrained slope of 1.0 (horizontal): 1.5 (vertical), the critical circle is always a toe circle. 3. The mid-point circle passes through the toe. 4. Taylor’s stability charts can be used only for homogeneous soils.arrow_forward(Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forwardA trench was cut in a clay slope as shown in the figure. When the trench reached a depth of 3 m, the top portion of the clay suddenly failed. On investigating, the failure was observed to be a slip plane approximately parallel to the original slope. Clay Y = 17.5 kN/m² 3m 36° The undrained shear strength (in kPa) of the clay will be.arrow_forward
- Q.4 A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay having strength parameters c = 60 kN/m2 , Ø = 0, and ɣ = 19 kN/m3 . Determine the factor of safety for the trial failure surface shown in Fig. 4arrow_forwardQ.4 A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay having strength parameters c = 58 kN/m², Ø = 0, and y = 18 kN/m³. Determine the factor of safety for the trial failure surface shown in Fig. 4 Q.5 Figure 5 shows an infinite slope with H = 32 ft and the groundwater table coincidingarrow_forwardQ1. For the slope shown in the figure, determine P (kN/m) so that the factor of safety for the given failure surface in terms of total 7.25 m P(kN/m) 1,5 28* stress (short term stability) is 2. The unit weight for both soils is 17 kN/m'. For soil 1, the relevant shear strength parameters c, = 30kPa, o=0°, and for soil 2, c, 55 kPa, @=0°. .72 4.0 Soill are Area -2.0--1.9- 41.7 m 3.0 Soil 2arrow_forward
- 3. For the planar wedge shown below: 22 m Slip surface 39° 28° Calculate the factor of safety against plane failure assuming: 9 (degree) 7 (kN/m³) c (kPa) 4) 50 2600 1950 c: cohesion of rock mass; y: unit weight of rock mass; q: friction angle of rock mass 1 1arrow_forwardA cut slope was excavated in saturated clay for installation of water piping system. The angle Bof cut slope is 45° with the horizontal. During excavation works, slope failure was occurred when the cut reached a depth of 4.0 m. Previous soil explorations showed that a hard layer was located at a depth of 6 m below the ground surface. The unit weight of saturated clay is 17.5 kN/m. (Assuming an undrained condition). 1. a) Determine the undrained cohesion of the clay. b) Determine Factor of Safety (FoS) if the depth of cut slope is 3m. c) What is the maximum depth of saturated clay can be excavated if the Factor of Safety (FoS) 1.4 to be implemented?arrow_forward3. For the planar wedge shown below: 22 m Slip surface 39° 28° Calculate the factor of safety against plane failure assuming: p (degree) > (kN/m³) c (kPa) 55 2800 1850 c: cohesion of rock mass; y: unit weight of rock mass; p: friction angle of rock mass جیهان کاظیarrow_forward
- Q.3. A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 19 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forwardA level site underlain by fully saturated clays is cut over a few days as shown in the figure below. The water table is located at the ground surface across the site. Determine the resisting moment in kN.m for the circular slip surface depicted in the Figure below shortly after excavation. Consider the soil wedge above the circular slip surface as a single free body, whose plane area is equal to 100 m2 and the centre of gravity of the soil wedge is given at Point C.arrow_forward4. A slope is 5 m high and has an angle of 45°. The soil parameters of the soil are: c'= 18 kN/m?, O'=15° and y = 17.1 kN/m³. Determine the factor of safety, Fs, using Michalowski's (2002) kinematic approach for c'-o' soils.arrow_forward
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