Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 15, Problem 15.6P
To determine
Find the maximum height (H) of the slope.
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Given an infinite slope with the following properties: γ = 17 kN/m3, H = 5 m, β = 34°, φ = 25° and c = 20 kPa.
a. Determine the normal stress.
b. Determine the shear stress.
c. Determine the factor of safety.
A cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following.
a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?
A cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the stability factor?
Chapter 15 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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- A 45 ° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties: C₁ = 50 kN/m² ₂ 0 = 0 and y = 19 kN/m²³ Determine the factor of safety. [Take area of wedge 39 m²] ok 3.4 m f 2.65 m 6m 45° 90° = 9marrow_forward4. A cut is to be made in a soil having γ = 18 kN/m3, c = 40 kPa, and φ = 15°. The cut slope makes an angle of 30°. a. If H = 6 m and θ = 15°, find the force that tend to cause sliding.b. Find the frictional force.c. Find the cohesive force.d. Find the factor of safety.e. For a factor of safety of 2.0, find the value of the critical angle along which the maximum developed cohesion occurs. f. Determine the depth of cut for a factor of safety of 2.0g. Determine the developed shear stress along the failure plane h. Determine the developed normal stress alongthe failure plane.arrow_forwardFor a railway track 7 m high embankment is required. The clay to be used for the embankment was found to have c = 20 kN/m2and unit weight = 19 kN/m3 Compute the critical maximum side slope angle for the embankment if a hard rocky stratum was found 3.5 m below the ground level. Assume ϕ for the clay equal to zero. The following values are given from Taylor's chart for depth factor D = 1.5 :arrow_forward
- Figure below gives details of an embankment to be made of cohesive soil with c, = 20 kPa. Unit weight of soil is 19 kN/m³. For the trial circle shown, determine the factor of safety against failure. The weight of the sliding sector is 329 kN acting at an eccentricity of 4.8 m from the centre of rotation. What would be the factor of safety if the shaded portion of the embankment were removed? Assume no tension crack develops. 71° R = 9 m e = 4.8 m 3 m 1.5 m 1.1 3 m VINISarrow_forwardExample 13.1 An infinite slope is shown in Figure 13.4. The shear strength parameters at the interface of soil and rock are as follows: c = 18 kN/m², ' = 25°. a. If H-8 m and 3 = 20°, find the factor of safety against sliding on the rock surface. b. If 3= 30°, find the height, H, for which F,-1. FIG. 13.4 #1 Density.p1500 kg Rock (ivarrow_forwardA deep cut of 10 m depth is made in sandy clay for a road. The sides of the cut make an angle of 60° with the horizontal. The shear strength parameters of the soil are c' = 20 kN/m², Ø' = 25°, and y= 18.5 kN/m³. If AC is the failure plane (SEE FIGURE BELOW), estimate the factor of safety of the slope using Culmann's method. 10 m 60⁰ 40⁰ 10° c²= 20 kN/m² p' = 25° y = 18.5 kN/m³arrow_forward
- A cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the maximum depth in meters up to which the cut could be made?arrow_forwardE A 40° slope is excavated to a depth of 10 m is a deep layer of saturated clay of unit weight 20 kN/m3; the relevant shear strength parameters are c, = 72 kN/m2 and o, = 0. The rock ledge is at %3D a great depth. The Taylor's stability coefficient for O, = 0 and 40° slope angle is 0.18. The factor of safety of the load is %3Darrow_forwardThe infinite sand slope shown in the figure is on theverge of sliding failure. The ground water tablecoincides with the ground surface. Unit weight of water % = 9.81kN/m² The value of the effective angle of internal friction (indegrees, up to one decimal place) of the sand is. 111 7sat = 21 kN/m²³arrow_forward
- 1.) A concrete dam retaining water is shown. If the specific weight of the concrete is 23.5 kN/m3. Assume there is a hydrostatic uplift that varies uniformly from full hydrostatic head at the heel of the dam to zero at the toe and that the coefficient of friction between dam and foundation soil is 0.45. What is the magnitude of the uplift force at the bottom of the dam? CHOICES: a.) 1530.10 b.) 3010.50 c.) 1,030.05 d.) 5030.10arrow_forward3. An infinite slope has shear strength parameters at the interface: c = 30 kPa, φ = 30°, γ = 17 kN/m3 (Assume 1 m strip perpendicular to the paper and 1 m strip along the inclination of the infinite slope). a. If H = 5 m, and β = 20°, find the sliding force. b. If H = 5 m, and β = 20°, find the force that resist sliding on the rock surface. c. If HCR = 8 m, find the minimum angle β so that the slope is stable.arrow_forwardA 40° slope is excavated to a depth of 10 m is a deep layer of saturated clay of unit weight 20 kN/m', the relevant shear strength parameters c= 72 kN/m? and =0. The rock are ledge is at a great depth. The Taylor's stability coefficient for o=0 and 40° slope angle is 0.18. The factor of safety of the load isarrow_forward
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