Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 15, Problem 15.22P
To determine
Find the factor of safety
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Students have asked these similar questions
The figure below shows a slope with an inclination of B = 56°. If AC represents a trial failure plane inclined at an angle 0 = 33° with the horizontal, determine the factor of safety against sliding
for the wedge ABC. Given H = 8.4 m; y = 20 kN/m³: ' = 21°; and c' = 36 kN/m?.
(Round your final answer to two decimal places.)
F, =
A slope is shown in the figure below. If AC represents a trial failure plane, determine the factor of safety against sliding for the wedge ABC. Given: β= 570 , ϒ = 17.5 kN/m3 , φ’ = 13.50 , and c’ =27 kN/m2Please use the Culmann’s method
B. Briefly Comment on how to analyze a slope and determine the factor of safety against overturning.
3.
For the slope shown in Figure below, determine the factor of safety against sliding along the circular slip
surface AC. Use the ordinary method of slices.
27 m
7.5 m
3
21 m
y= 19 kN/m3
c' = 31 kN/m2
6.
5
d'= 24°
A
30°
Chapter 15 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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Similar questions
- Figure 5 shows an infinite slope with H = 30 ft and the groundwater table coinciding with the ground surface. If there is seepage through the soil, determine the factor of safety against sliding along the plane AB. The soil properties are Gs = 2.7, e = 0.8, β = 16 ͦ, Ø = 21 ͦ, and c’ = 1250 lb/ft2.arrow_forwardFigure 2 shows a slope with an inclination of : β = 58 ͦ. If AC represents a trial failure plane inclined at an angle θ = 32 ͦ with the horizontal, determine the factor of safety against sliding for the wedge ABC. Given: H = 6 m; ɣ = 19 kN/m3, Ø =21 ͦ, and c’= 38 kN/m2arrow_forwardQuestion No. 16 A long slope is formed in a soil with shear strength parameters: c' = 0 and d' = 34°. A firm stratum lies below the slope and it is assumed that the water table may occasionally rise to the surface, with seepage taking place parallel to the slope. Use Ysat = 18 kN/m³ and Yw = 10 kN/m³. The maximum slope angle (in degrees) to ensure a factor of safety of 1.5, assuming a potential failure surface parallel to the slope, would bearrow_forward
- Q.1. Refer to the infinite slope shown in Figure 1. Given: β = 19 ͦ, ɣ = 20 kN/m3 , Ø = 33 ͦ, and c’ = 47 kN/m2 . Find the height, H, such that a factor of safety, Fs = 3.1 is maintained against sliding along the soil-rock interface.arrow_forwardA cut slope is to be made as shown in the figure. The unit weight of soil is 15.74 kN/m3 and an angle of internal friction of 10°. The soil has as cohesion of 28.8 kN/m2. The trial failure plane makes an angle of 30° with the horizontal while the cut slope makes an angle of 50° with the horizontal. If the height of the slope is 3m, Compute the force that causes sliding. Compute the resistance sliding force. Compute the factor of safety against sliding.arrow_forwardA 10 m high slope of dry clay soil (unil weighi 20 N/m) with a slope angle of 45 and the circular slip surlace, is shown in the figure (not drawn to the scale). The weight of the slip wedge is denoted by W. The undrained unit cohesion (C is 60 kPa. 39. 10m Unit weight = 20 kN m 10m C - 60 kPa 448m, 451 The facter of safety of the slope against slip failure. ISarrow_forward
- Given an infinite slope with the following properties: γ = 17 kN/m3, H = 5 m, β = 34°, φ = 25° and c = 20 kPa. a. Determine the normal stress. b. Determine the shear stress. c. Determine the factor of safety.arrow_forwardFind slope at D in degrees using double integration method. Consider 250 mm x 400 mm (b x h) section and E = 120 GPa. Use a = 3.2 m, b = 19.1 kN/m, and c = 25.5 kNarrow_forwardRefer to Figure 15.50. Given that β = 55°, γ = 19 kN/m3, ϕ′ = 17°, c′ = 57.4 kN/m2, and H = 13.7 m, determine the factor of safety with respect to sliding. Assume that the critical sliding surface is a plane.arrow_forward
- Calculate the safety factor with the following conditions in a rock slope, likewise this slope requires a long-term static SF project equivalent to 2 based on the RCCDMX. b Zw B H a 02 A Rock mass properties: -Cohesion =3.3 T/m2 ; Internal friction angle: = -ymat = 3.8 T/m3; b=3m; B=6m; a=60° - 01=45° ; 0=72°; Zw=4m; Ax=12 m2 35° 01arrow_forwardA long slope is made up of a cohesionless (c'=0) soil with the internal friction angle of 34°. If the water table rises to the surface of the slope, then determine the maximum possible value of the slope angle to get a factor of safety of 1.5. Take saturated unit weight as18 kN/m3 and the unit weight of water as 10 kN/m3.arrow_forwardAn infinite slope is shown in the figure having the given shear strength parameters at the interface of the soil and rock. Angle of internal friction = 26° Cohesion of soil = 18 kPa Unit weight of soil = 18.50 kN/m3 Saturated unit weight of soil = 21.4 kN/m3 Find the factor of safety against sliding assuming there is no water pressure. 2. Find the factor of safety against sliding assuming there is a seepage through the soil and that the ground water level coincides with the ground surfacearrow_forward
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