Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 15, Problem 15.31P
(a)
To determine
Find the location of the center of the critical circle.
(b)
To determine
Find the length of the radius of the critical circle.
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Students have asked these similar questions
Find slope at D in degrees using double integration method. Consider 250 mm x 400 mm (b x h) section and E = 120 GPa. Use a = 3.2 m, b = 19.1 kN/m, and c = 25.5 kN
The rock slope has been mapped and analysed. The data of slope geometry and rock
Q1
parameters tabulated in Table 1. The face slope facing toward south and the upper slope is
flatted. The discontinuity sets are as follow (dip direction / dip angle); set 1: 10/46', set 2:
190%40, and set 3: 140 /70°.
Parameters
Values
Face slope dip angle
65°
Slope height
50 meter
Slope length
150 meter
Unit weight of the rock
25 kN/m3
Depth of tension crack
2 m
Unit weight of water
9.81 kN/m³
The cohesion of all discontinuities
50 kPa
Friction angle for all discontinuities
30°
) Calculate the factor of safety for the planar failure mode when the tension crack is
completely filled with water.
Question 2
Calculate the slope at point C in degrees. E- 200 GPa, I= 1240 x 106 mm4
Express your answer in two decimal places. No need to indicate sign convention (just in your solution sheet)
1.5 m
10 kN/m
20 kN/m
10 kN/m
1.5 m
C
D
A
2 m
5 m
4 m
Chapter 15 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32P
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Similar questions
- This is a question from slope stability bishop method Please Note i am not asking for the entire problem to be completed, i am simply seeking guidance on how to calculate slice 1 entire row that is highlighted in red. example how did we derive the values of (W) in the table. formula ....W=ybz but im not getting the values see diagram attached Question A compacted earth fill is constructed on a soft, saturated clay (figure below). The fill was compacted to an average dry unit weight of 19 kN m3 ⁄ and water content of 15%. The shearing strength of the fill was determined by CU tests on samples compacted to representative field conditions. The shear strength parameters are ?? = 45 kPa, ??′ = 34°, and ???′ = 28°. The variation of undrained shear strength of the soft clay with depth as determined by simple shear tests is shown in the figure below, and the friction angle at the critical state is ???′ = 30°. The average water content of the soft clay is 40%. Compute the factor of safety…arrow_forwardA slope is shown in the figure below. If AC represents a trial failure plane, determine the factor of safety against sliding for the wedge ABC. Given: β= 570 , ϒ = 17.5 kN/m3 , φ’ = 13.50 , and c’ =27 kN/m2Please use the Culmann’s method B. Briefly Comment on how to analyze a slope and determine the factor of safety against overturning.arrow_forwardA cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the stability factor?arrow_forward
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