A deep cut of 10 m depth is made in sandy clay for a road. The sides of the cut make an angle of 60° with the horizontal. The shear strength parameters of the soil are c' = 20 kN/m², Ø' = 25°, and y= 18.5 kN/m³. If AC is the failure plane (SEE FIGURE BELOW), estimate the factor of safety of the slope using Culmann's method. 10 m 60⁰ 40⁰ 10° c²= 20 kN/m² $' = 25° y = 18.5 kN/m³

A level site underlain by fully saturated clays is cut over a few days as shown in the figure below. The water table is located at the ground surface across the site. Determine the resisting

From the figure shown the soil has a unit weight of 28.5 kN/m^3 and the undrained shear strength cu = 20 kN/m^2. The slope makes an angle 62 degrees with the horizontal. Assume a stability number m = 0.16761. Compute the stability factor. a. 6.78b. 6.7c. 5.99d. 5.012. Compute the maximum depth up to which the cut could be made. a. 5.18 mb. 4.97 mc. 4.20 md. 3.84 m3. Compute angle that the failure plane makes with the horizontal if BC is 9 m. a. 22.32 degreesb. 28.25 degreesc. 21.05 degreesd. 20.15 degrees

3. The following convergence measurements (U) have been made in a 4.6-m-diameter circular vertical shaft in good quality granitic rock mass (Em = 40 GPa, ν = 0.2): θ (deg) U (mm) 0 2.25 45 2.39 90 1.50 135 1.00 a) Derive the equations that relate convergence to in situ stress. b) The angle θ is measured (clockwise) with respect to the x-axis, which is oriented 30 degrees clockwise from True North. What is the orientation of the maximum principal stress with respect to True North?