Biology: The Unity and Diversity of Life (MindTap Course List)
15th Edition
ISBN: 9781337408332
Author: Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Publisher: Cengage Learning
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Chapter 14, Problem 4SQ
Summary Introduction
Introduction: Tay–Sachs disease is caused due to mutations in the HEXA gene that encodes lysosomal enzyme. It follows autosomal recessive inheritance, that is, two copies of mutated gene are required for the occurrence of the disease.
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Duchenne muscular dystrophy is sex linked and usually affects only males. Victims of the disease become progressively weaker, starting early in life.a. What is the probability that a woman whose brother has Duchenne’s disease will have an affected child?b. If your mother’s brother (your uncle) had Duchenne’s disease, what is the probability that you have received the allele?c. If your father’s brother had the disease, what is the probability that you have received the allele?
15. The following pedigree shows inheritance of Huntington's disease, a fatal genetic
disorder that causes neurodegeneration. Since signs and symptoms usually do not
appear until adulthood, many who are carriers may not realize their risk of passing on
the disease-causing allele. The following pedigree represents a family in which some
people are affected by Huntington's disease.
Reeessive Trit
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Mec
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Hinhetee
If a mouse has a dominant phenotype (P_), how would you determine if it is
homozygous (PP) or heterozygous (Pp)?
Select one:
O a.
O b.
O c.
O d.
O e.
cross it to a mouse with the dominant trait but a similarly unknown genotype.
cross it to a mouse with the recessive trait.
cross it to a homozygous dominant mouse.
it cannot be determined.
cross it to a heterozygous dominant mouse.
O
Chapter 14 Solutions
Biology: The Unity and Diversity of Life (MindTap Course List)
Ch. 14 - Prob. 1DAACh. 14 - Prob. 2DAACh. 14 - Prob. 3DAACh. 14 - Prob. 4DAACh. 14 - Prob. 5DAACh. 14 - Prob. 1SQCh. 14 - Pedigree analysis is necessary when studying human...Ch. 14 - A recognized set of symptoms that characterize a...Ch. 14 - Prob. 4SQCh. 14 - A trait that is present in a male child but not in...
Ch. 14 - Choose the statement that is incorrect. a. A son...Ch. 14 - Prob. 7SQCh. 14 - Prob. 8SQCh. 14 - Klinefelter syndrome (XXY) can most be easily...Ch. 14 - Prob. 10SQCh. 14 - Does the phenotype indicated by the red circles...Ch. 14 - G6PD deficiency is an X-Linked recessive disorder....Ch. 14 - Marian syndrome (Section 13.5) is inherited in an...Ch. 14 - Duchenne muscular dystrophy, which is inherited in...Ch. 14 - Human females have two X chromosomes (XX); males...Ch. 14 - A mutation on an autosome causes a particular...Ch. 14 - Expression of the SRY gene on the Y chromosome...Ch. 14 - The somatic cells of most individuals with Down...Ch. 14 - Mutations in the genes for clotting factor VIII...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Duchenne muscular dystrophy is sex linked and usuallyaffects only males. Victims of the disease become progressively weaker, starting early in life.a. What is the probability that a woman whose brotherhas Duchenne’s disease will have an affected child?b. If your mother’s brother (your uncle) had Duchenne’sdisease, what is the probability that you have receivedthe allele?c. If your father’s brother had the disease, what is theprobability that you have received the allele?arrow_forwardFragile X syndrome is an X-linked recessive Achondroplasia is an autosomal dominant trait characterized by a shortened stature. An XX individual is a carrier for Fragile X disorder and is unaffected by achondroplasia. An XY individual is not affected by Fragile X disorder and has achondroplasia. a. What is the XX individual’s genotype b. What is the XY individual’s genotype? c. If the two individuals where to have children, what are the possible genotypes and phenotypes of their children? Use a Punnett square. d. What is the probability of them having a child with Fragile X and achondroplasia?arrow_forwardThe condition phenylketonuria is caused by a recessive allele. There are two carriers who have progeny.a. Give the gene notation. b. Give the expected genotypic and phenotypic ratios. c. What is the probability that their child will be heterozygous if they have a normal child?d. What is the probability of having two affected children and one normal child if they have three children?arrow_forward
- Color blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?arrow_forwardSickle cell anemia is an inherited red blood cell disorder in which there are not enough healthy red blood cells to carry oxygen throughout the body. The allele that causes sickle-cell anemia is autosomal recessive (s), and the dominant allele can be represented by S. How many offspring will be affected by the disorder if the mother is a carrier, and the father appears to be normal? (Include the gender) a. b. How many will become carriers? (include the gender) A- 三三三 四 四 II !!arrow_forwardGlucose-6-phosphate dehydrogenase (G6PD) deficiency is a disorder that affects the normal function of red blood cells and can eventually lead to anemia. The trait is controlled by a recessive allele found on 4. the X chromosome. An affected son was born to a man and woman who were unaffected. The woman's mother was affected while the father was normal. a. Indicate the gene notation. b. Give the genotypes of the affected boy's parents. Derive the genotypic and phenotypic ratios for the offspring. Show and label your solutions properly. What is the probability that they will have a phenotypically normal daughter as their first child? C. d.arrow_forward
- Which of the following is indicated by roman numerals in a pedigree? a.Presence of the studied trait b.Generation c.Sex d.Marriage status Which of the following disorders in humans has an autosomal dominant inheritance pattern? a.Albinism b.Hemophilia c.Tay-Sachs disease d.Huntington’s disease For an X-linked recessive allele, what proportion of female offspring will be carriers in the cross of an affected father and a noncarrying mother? a.50 percent b.0 percent c.100 percentarrow_forwardIf a genetic disease is inherited as an autosomal recessive, one would expect to find which of the following? A. Two affected individuals never have an unaffected child. B. Two affected individuals have affected male offspring but no affected female children. C. If a child has the disease, one of his or her grandparents will have had it. D. In a marriage between an affected individual and an unaffected one, all the children are unaffected.arrow_forwardA woman with a rare autosomal recessive disorder was told that it was unlikely that her children would have the disorderas her husband did not have it. However, her first child has the disorder. a. What is the most likely explanation? b. Diagram the cross between the woman and her husband using a Punnett square, give the genotypic ratio (GR) and phenotypic ratio (PR) from the Punnett square. c. Based on the Punnett square results, what is the chance that her next child will have the disorder?arrow_forward
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