Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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Mutations in the genes for clotting factor VIII and IX cause hemophilia A and B, respectively. A woman may be heterozygous for mutations in both genes, with a mutated factor VIII allele on one X chromosome, and a mutated factor IX allele on the other. All of her sons should have either hemophilia A or B. However, on rare occasions, one of these women gives birth to a son who does not have hemophilia, and his one X chromosome does not have either mutated allele. Explain.
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- Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?arrow_forwardfor PCOS (polycystic ovarian syndrome) the GENE involved is (CYP19, CYP11a, CYP21, CYP17, ) what Effects of this altered gene product on the affected individual.arrow_forwardGiven the information regarding sickle cell anemia, if two carriers were to have children, what would be the genotypes and phenotypes of their children? Would any of the children show symptoms of the disease?arrow_forward
- Predict the probability (using a Punnett square) of producing an offspring affected by a single gene X-linked mutation given the genotype of the parents. Compare these crosses in two cases: where the mutant allele is “A” vs where the mutant allele is “a” (XAXA x XaY) (XAXa x XAY) (XAXa x XaY) (XaXa x XAY) (XaXa x XaY). Include gender in the phenotype.arrow_forwardHemophilia, disease in which the blood lacks a clotting factor, is caused by an X linked recessive gene. Joe doe not have hemophilia and Lucille is heterozygous for the condition. What is the chance that their MALE child will have hemophilia? (Note: you are calculating the probability for their MALE children only, in other words if they have 1 male child, what is the probability that he will be born with the disease?) 0% 1/4 or 25% 2/4 or 50% 3/4 or 75% 4/4 or 100%arrow_forwardSickle cell anemia is an inheritable red blood cell disorder that results in sickle-shaped red blood cells. The sickle-shaped red blood cells can stick to blood vessel walls and cause a blockage or slow the movement of blood throughout the body. Individuals who are heterozygous produce both normal and sickle-shaped red blood cells which gives them resistance to malaria but they do not develop sickle cell anemia (so heterozygotes are unaffected on the pedigree).Let HbS be the allele for sickle cell anemia and let HbA be the allele for normal red blood cells. Which of the following rows provides the correct genotypes for individuals I-2, I-4, II-1, and III-1? Select one: a. I-2 I-4 II-1 III-1 HbA_ HbAHbS HbAHbS HbA_ b. I-2 I-4 II-1 III-1 HbA_ HbAHbS HbAHbS HbAHbS c. I-2 I-4 II-1 III-1 HbAHbS HbAHbS HbAHbS HbAHbS d. I-2 I-4 II-1 III-1 HbAHbA HbAHbA HbAHbA HbAHbAarrow_forward
- Several genes in humans in addition to the ABO gene () give rise to recognizable antigens on the surface of the red blood cells. The Rh marker is determined by positive (R) and negative alleles () of gene R, where R is completely dominant to r. The presence of M and N surface proteins are controlled by two codominant alleles of gene L (LM and LM. For each mother-child pair, choose the father of the child from among the males in the right column. (Assume that all mothers and fathers are HH; there is no involvement of the Bombay phenotype.) Paternal genotypes maybe used once, more than once, or not at all. Each mother-child pair matches with one or more than one paternal genotype. Maternal phenotype: Child phenotype: Paternal genotype: Reset A, M, Rh(neg) O, M, Rh(pos) B, N, Rh(neg) O, N, Rh(pos) O, M, Rh(neg) A, MN, Rh(pos) A, N, Rh(pos) AB, MN, Rh(pos) B, N, Rh(pos) A, MN, Rh(neg) Genotypes of possible fathers AiLMLN rr BiLMLN RR ii LNLN rr ii LMLM rr AALMLN RRarrow_forwardGive the typical sex-chromosome complement found in the cells of people with Turner syndrome, with Klinefelter syndrome, and with androgen-insensitivity syndrome. What is the sex-chromosome complement of triple-X females?arrow_forwardIn blood groups, Rh positive blood is dominant (R) over the gene for Rh negative blood (r). What types of offspring could be expected for an Rh positive AB woman, (whose father was Rh negative), who marries a man with heterozygous A positive blood?arrow_forward
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