Chemical Principles
Chemical Principles
8th Edition
ISBN: 9781305581982
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 14, Problem 10E
Interpretation Introduction

Interpretation:

The hybridization which is needed for central atoms which have tetrahedral arrangement of electron pairs and linear arrangement of electron pairs should be determined. The number of unhybridized p-atomic orbitals present when the geometry of central atom is tetrahedral, trigonal planar and linear. The uses of unhybridized p-atomic orbitals should be determined.

Concept Introduction:

When two atomic orbitals combine with each other to produce hybrid orbitals, redistribution of energy of orbitals of distinct atoms to form orbitals with equal energy occurs. This process is known as hybridization and the formed new orbitals are known as hybrid orbitals.

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What hybridization is required for central atoms that have a tetrahedral arrangement ofelectron pairs? A trigonal planar arrangement of electron pairs? A linear arrangement ofelectron pairs? How many unhybridized p atomic orbitals are present when a centralatom exhibits tetrahedral geometry? Trigonal planar geometry? Linear geometry? Whatare the unhybridized p atomic orbitals used for?
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Chapter 14 Solutions

Chemical Principles

Ch. 14 - Prob. 11ECh. 14 - Prob. 12ECh. 14 - Prob. 13ECh. 14 - Use the localized electron model to describe the...Ch. 14 - Prob. 15ECh. 14 - Use the LE model to describe the bonding in H2CO...Ch. 14 - Prob. 17ECh. 14 - The space-filling models of hydrogen cyanide and...Ch. 14 - Prob. 19ECh. 14 - Prob. 20ECh. 14 - Prob. 21ECh. 14 - Indigo is the dye used in coloring blue jeans. The...Ch. 14 - Prob. 23ECh. 14 - Prob. 24ECh. 14 - Why must all six atoms in C2H4 be in the same...Ch. 14 - The allene molecule has the following Lewis...Ch. 14 - Biacetyl and acetoin are added to margarine to...Ch. 14 - Many important compounds in the chemical industry...Ch. 14 - Prob. 29ECh. 14 - Hot and spicy foods contain molecules that...Ch. 14 - Two molecules used in the polymer industry are...Ch. 14 - Prob. 32ECh. 14 - The three most stable oxides of carbon are carbon...Ch. 14 - Prob. 34ECh. 14 - Prob. 35ECh. 14 - What are the relationships among bond order, bond...Ch. 14 - Prob. 37ECh. 14 - A Lewis structure obeying the octet rule can be...Ch. 14 - Prob. 39ECh. 14 - Why does the molecular orbital model do a better...Ch. 14 - Prob. 41ECh. 14 - Prob. 42ECh. 14 - Prob. 43ECh. 14 - In which of the following diatomic molecules would...Ch. 14 - Prob. 45ECh. 14 - Using the molecular orbital model to describe the...Ch. 14 - The transport of O2 in the blood is carried out by...Ch. 14 - Prob. 48ECh. 14 - Prob. 49ECh. 14 - Consider the following electron configuration:...Ch. 14 - Prob. 51ECh. 14 - Using an MO energy-level diagram, would you expect...Ch. 14 - Use Figs.14.45 and 14.46 to answer the following...Ch. 14 - The diatomic molecule OH exists in the gas phase....Ch. 14 - Prob. 55ECh. 14 - Describe the bonding in the O3 molecule and the...Ch. 14 - Prob. 57ECh. 14 - The space-filling model for benzoic acid is shown...Ch. 14 - Prob. 59ECh. 14 - Prob. 60ECh. 14 - The microwave spectrum of 12C16O shows that the...Ch. 14 - Prob. 62ECh. 14 - Prob. 63ECh. 14 - Prob. 64ECh. 14 - Draw the Lewis structures, predict the molecular...Ch. 14 - Prob. 66AECh. 14 - Prob. 67AECh. 14 - Prob. 68AECh. 14 - Prob. 69AECh. 14 - Prob. 70AECh. 14 - Prob. 71AECh. 14 - Prob. 72AECh. 14 - Prob. 73AECh. 14 - Vitamin B6 is an organic compound whose deficiency...Ch. 14 - Prob. 75AECh. 14 - Prob. 76AECh. 14 - Prob. 77AECh. 14 - Prob. 78AECh. 14 - Prob. 79AECh. 14 - Draw the Lewis structures for TeCl4 , ICl5 , PCl5...Ch. 14 - Prob. 81AECh. 14 - Pelargondin is the molecule responsible for the...Ch. 14 - Prob. 83AECh. 14 - Prob. 84AECh. 14 - Prob. 85AECh. 14 - Prob. 86AECh. 14 - Given that the ionization energy of F2 is...Ch. 14 - Bond energy has been defined in the text as the...Ch. 14 - a.A flask containing gaseous N2 is irradiated with...Ch. 14 - Use the MO model to determine which of the...Ch. 14 - Cholesterol (C27H46O) has the following structure:...Ch. 14 - Arrange the following from lowest to highest...Ch. 14 - Carbon monoxide (CO) forms bonds to a variety of...Ch. 14 - Prob. 94CPCh. 14 - In Exercise71 in Chapter13 , the Lewis structures...Ch. 14 - Prob. 96CPCh. 14 - Prob. 97CPCh. 14 - Prob. 98MP
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