Chapter 13.5, Problem 39SPR

a.

To determine

To determine circumference of safety circle.

Answer to Problem 39SPR

Circumference is 5026.5 feet.

Explanation of Solution

Given information:

Radius is 800 feet.

Circumference of a circle with radius $r$ is $2\pi r$

Hence circumference is,

  $2\pi \left(800\right)=5026.5$ feet.

b.

To determine

To determine the radius of explosion circle.

Answer to Problem 39SPR

Range of values for the radius of the explosion circle is 500-600 feet.

Explanation of Solution

Given information:

Safety circle are 200 and 300 feet farther from the center than the explosion circle.

  

Range of values for the radius of the explosion circle are (800-300) and (800-200)

Hence range of values for the radius of the explosion circle is 500-600 feet.

c.

To determine

To determine the radius of explosion circle.

Answer to Problem 39SPR

Least circumference is 3140 feet.

Maximum circumference is 3770 feet.

Explanation of Solution

Given information:

Radius range is 500-600 feet

  

Circumference of a circle with radius $r$ is $2\pi r$

Hence the circumference of the circle with radius 500 is,

  $2\pi \left(500\right)=3142$ feet.

The circumference of the circle with radius 600 is,

  $2\pi \left(600\right)=3770$ feet.