Chapter 13.5, Problem 35SPR

To determine

To determine probability of given event.

Answer to Problem 35SPR

P(pointer landing on green) $=\frac{25}{360}=\frac{5}{72}\approx 0.069$

Explanation of Solution

Given information:

  

Here we have to find P(pointer landing on green)

To determine this we shall find the fraction of angle covered by the green color on the spinner.

Hence the fraction of angle of green color is $\frac{{25}^{\circ }}{{360}^{\circ }}$ (total angle of a circle is ${360}^{\circ }$ )

Now probability of the event will be same as the fraction of green color as total possibilities of rotation of pointer can be 360 (considering for each degree)

Hence,

P(pointer landing on green) $=\frac{25}{360}=\frac{5}{72}\approx 0.069$