Chapter 13, Problem 16SGR

(a)

To determine

Find the probability of event P(hole).

Answer to Problem 16SGR

About 0.025

Explanation of Solution

Given:

Measures for a beanbag game are shown.

Calculation:

Area of the whole area = (24)(48) = 1152 square inches

Area of hole = $\pi {\left(\frac{6}{2}\right)}^2=9\pi \approx 28.27i{n}^2$

So, $P(hole)=\frac{\text{favourable area}}{\text{total area}}=\frac{28.27}{1152}\approx 0.025$

(b)

To determine

Find the probability of event P(hole).

Answer to Problem 16SGR

About 0.975

Explanation of Solution

Given:

Measures for a beanbag game are shown.

From part (a) , P(hole) = 0.025

Formula Used:

P(not A) = 1-P(A)

Calculation:

P(not hole) = 1- P(hole)

So,

P(not hole) = 1 − 0.025 = 0.975