The major product obtained on treating the compounds in problem 29 with Br 2 at 125 ° C should be identified. Concept introduction: Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical. Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength. Bromination: 1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 28P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

How many potential E2 elimination products can form from the addition of NaOH to the following: (free hint: trans-decalin cannot undergo a ring flip) → 1/2/3/no products H Br "H. H, Br

8. The following molecules (X, Y, and Z) were the products of an ozonolysis reaction of which species? X H A B Z देउर C D E

Which is the major product from the acid catalyzed hydrolysis of cyclohexene oxide? но OH но он || II IV

Answer 2

Question

Chapter 13, Problem 28P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 13, Problem 28P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 13, Problem 28P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 13, Problem 28P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 6

Chapter 13, Problem 28P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 7

Chapter 13, Problem 28P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 8

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 9

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 10

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 11

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 13.2 - Prob. 1P Ch. 13.2 - Write the steps for formation of...Ch. 13.3 - Prob. 3P Ch. 13.4 - Prob. 4P Ch. 13.5 - Prob. 7P Ch. 13.5 - a. Would chlorination or bromination produce a...Ch. 13.5 - Prob. 10P Ch. 13.6 - Prob. 11P Ch. 13.7 - Prob. 12P Ch. 13.7 - Prob. 13P

Solution Summary: The author explains that the major product obtained on treating the compounds in problem 29 should be identified.

Concept explainers

Want to see the full answer?

Chapter 13 Solutions