PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Chapter 1.2, Problem 71E

a.

To determine

To describe the overall shape of the distribution of monthly returns for the U.S. stock market over a 273-month period.

a.

Expert Solution
Check Mark

Answer to Problem 71E

The distribution is skewed to the left and the distribution appears to contain 3 outliers with 2 gaps.

Explanation of Solution

The figure below shows a histogram of the distribution of monthly returns for the U.S. stock market over a 273-month period:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.2, Problem 71E , additional homework tip  1

The distribution is skewed to the left, because the highest bars are to the right in the histogram with a tail of smaller bars to the left.

The distribution appears to contain 3 outliers, because there are two bars (one with frequency 2 and the other with frequency 1) which are separated by a gap from the other bars of the histogram.

The gaps are roughly at -20 and -13, while there are two potential outliers between -25 and -22.5, with one other potential outlier between -17.5 and -15.

b.

To determine

To determine the approximate center of this distribution of monthly returns for the U.S. stock market over a 273-month period.

b.

Expert Solution
Check Mark

Answer to Problem 71E

The center of this distribution to be between 0% and 2.5%.

Explanation of Solution

The figure below shows a histogram of the distribution of monthly returns for the U.S. stock market over a 273-month period:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.2, Problem 71E , additional homework tip  2

We expect the center of the distribution to be roughly at the highest bar in the histogram.

The highest bar has monthly percent returns between 0% and 2.5%, thus we then estimate the center of this distribution to be between 0% and 2.5%.

c.

To determine

To determine why we cannot find the exact value for the minimum return and between what two values does it lie.

c.

Expert Solution
Check Mark

Answer to Problem 71E

We cannot determine the exact value of the minimum return, because we have not been given its exact value and we only know a range of possible values for the minimum return by the corresponding bar in the histogram.

The minimum return is between -25% and -22.5%.

Explanation of Solution

The figure below shows a histogram of the distribution of monthly returns for the U.S. stock market over a 273-month period:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.2, Problem 71E , additional homework tip  3

The minimum return is represented by the left most bar in the histogram.

However, we cannot determine the exact value of the minimum return, because we have not been given its exact value and we only know a range of possible values for the minimum return by the corresponding bar in the histogram.

We note that the leftmost bar in the histogram takes on monthly percent returns on common stocks between -25% and -22.5%, which then implies that the minimum return is between -25% and -22.5%.

d.

To determine

To determine about what percent of all months had returns less than 0 for the U.S. stock market over a 273-month period.

d.

Expert Solution
Check Mark

Answer to Problem 71E

Approximately, 37.36% of the months has returns less than 0.

Explanation of Solution

The figure below shows a histogram of the distribution of monthly returns for the U.S. stock market over a 273-month period:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.2, Problem 71E , additional homework tip  4

Let us first estimate the frequency of corresponding to the interval of each bar, which is given by the height of the bars.

    IntervalFrequency
    -25 < -22.52
    -22.5 < -200
    -20 < -17.50
    -17.5 < -151
    -15 < -12.50
    -12.5 < -104
    -10 < -7.56
    -7.5 < -511
    -5 < -2.528
    -2.5 < 050
    0 < 2.578
    2.5 < 558
    5 < 7.524
    7.5 < 108
    10 < 12.53

Let us next add the frequencies of all intervals with negative returns.

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.2, Problem 71E , additional homework tip  5

Thus we then note that 102 of the 273 months in the sample have a return less than 0.

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 1.2, Problem 71E , additional homework tip  6

This then implies that approximately 37.36% of the months has returns less than 0.

Chapter 1 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.2 - Prob. 45ECh. 1.2 - Prob. 46ECh. 1.2 - Prob. 47ECh. 1.2 - Prob. 48ECh. 1.2 - Prob. 49ECh. 1.2 - Prob. 50ECh. 1.2 - Prob. 51ECh. 1.2 - Prob. 52ECh. 1.2 - Prob. 53ECh. 1.2 - Prob. 54ECh. 1.2 - Prob. 55ECh. 1.2 - Prob. 56ECh. 1.2 - Prob. 57ECh. 1.2 - Prob. 58ECh. 1.2 - Prob. 59ECh. 1.2 - Prob. 60ECh. 1.2 - Prob. 61ECh. 1.2 - Prob. 62ECh. 1.2 - Prob. 63ECh. 1.2 - Prob. 64ECh. 1.2 - Prob. 65ECh. 1.2 - Prob. 66ECh. 1.2 - Prob. 67ECh. 1.2 - Prob. 68ECh. 1.2 - Prob. 69ECh. 1.2 - Prob. 70ECh. 1.2 - Prob. 71ECh. 1.2 - Prob. 72ECh. 1.2 - Prob. 73ECh. 1.2 - Prob. 74ECh. 1.2 - Prob. 75ECh. 1.2 - Prob. 76ECh. 1.2 - Prob. 77ECh. 1.2 - Prob. 78ECh. 1.2 - Prob. 79ECh. 1.2 - Prob. 80ECh. 1.2 - Prob. 81ECh. 1.2 - Prob. 82ECh. 1.2 - Prob. 83ECh. 1.2 - Prob. 84ECh. 1.2 - Prob. 85ECh. 1.2 - Prob. 86ECh. 1.3 - Prob. 87ECh. 1.3 - Prob. 88ECh. 1.3 - Prob. 89ECh. 1.3 - Prob. 90ECh. 1.3 - Prob. 91ECh. 1.3 - Prob. 92ECh. 1.3 - Prob. 93ECh. 1.3 - Prob. 94ECh. 1.3 - Prob. 95ECh. 1.3 - Prob. 96ECh. 1.3 - Prob. 97ECh. 1.3 - Prob. 98ECh. 1.3 - Prob. 99ECh. 1.3 - Prob. 100ECh. 1.3 - Prob. 101ECh. 1.3 - Prob. 102ECh. 1.3 - Prob. 103ECh. 1.3 - Prob. 104ECh. 1.3 - Prob. 105ECh. 1.3 - Prob. 106ECh. 1.3 - Prob. 107ECh. 1.3 - Prob. 108ECh. 1.3 - Prob. 109ECh. 1.3 - Prob. 110ECh. 1.3 - Prob. 111ECh. 1.3 - Prob. 112ECh. 1.3 - Prob. 113ECh. 1.3 - Prob. 114ECh. 1.3 - Prob. 115ECh. 1.3 - Prob. 116ECh. 1.3 - Prob. 117ECh. 1.3 - Prob. 118ECh. 1.3 - Prob. 119ECh. 1.3 - Prob. 120ECh. 1.3 - Prob. 121ECh. 1.3 - Prob. 122ECh. 1.3 - Prob. 123ECh. 1.3 - Prob. 124ECh. 1.3 - Prob. 125ECh. 1.3 - Prob. 126ECh. 1.3 - Prob. 127ECh. 1.3 - Prob. 128ECh. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 5ECh. 1 - Prob. 6ECh. 1 - Prob. 7ECh. 1 - Prob. 8ECh. 1 - Prob. 9ECh. 1 - Prob. 10ECh. 1 - Prob. R1.1RECh. 1 - Prob. R1.2RECh. 1 - Prob. R1.3RECh. 1 - Prob. R1.4RECh. 1 - Prob. R1.5RECh. 1 - Prob. R1.6RECh. 1 - Prob. R1.7RECh. 1 - Prob. R1.8RECh. 1 - Prob. R1.9RECh. 1 - Prob. R1.10RECh. 1 - Prob. T1.1SPTCh. 1 - Prob. T1.2SPTCh. 1 - Prob. T1.3SPTCh. 1 - Prob. T1.4SPTCh. 1 - Prob. T1.5SPTCh. 1 - Prob. T1.6SPTCh. 1 - Prob. T1.7SPTCh. 1 - Prob. T1.8SPTCh. 1 - Prob. T1.9SPTCh. 1 - Prob. T1.10SPTCh. 1 - Prob. T1.11SPTCh. 1 - Prob. T1.12SPTCh. 1 - Prob. T1.13SPTCh. 1 - Prob. T1.14SPT
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