The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 12, Problem 21PT4
To determine

To select appropriate option.

Expert Solution & Answer
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Answer to Problem 21PT4

(e) There are no outliers by the 1.5IQR rule in either distribution.

Explanation of Solution

Given:

  The Practice of Statistics for AP - 4th Edition, Chapter 12, Problem 21PT4

The options are:

a) Team A has the same number of players in their 30s as does Team B.

(b) The median age of both teams is the same.

(c) Both age distributions arc skewed to the right.

(d) The age ranges of both teams are similar.

(e) There are no outliers by the 1.5IQR rule in either distribution.

The options a, b, c and d explain the steam and leaf plot. All these options are justified. Option e does not justify because it requires some calculations. That is, we need to first find IQR and then need to find bounds using Q11.5IQRandQ3+1.5IQR . Hence, option e cannot be justified.

Chapter 12 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 12.1 - Prob. 7ECh. 12.1 - Prob. 8ECh. 12.1 - Prob. 9ECh. 12.1 - Prob. 10ECh. 12.1 - Prob. 11ECh. 12.1 - Prob. 12ECh. 12.1 - Prob. 13ECh. 12.1 - Prob. 14ECh. 12.1 - Prob. 15ECh. 12.1 - Prob. 16ECh. 12.1 - Prob. 17ECh. 12.1 - Prob. 18ECh. 12.1 - Prob. 19ECh. 12.1 - Prob. 20ECh. 12.1 - Prob. 21ECh. 12.1 - Prob. 22ECh. 12.1 - Prob. 23ECh. 12.1 - Prob. 24ECh. 12.1 - Prob. 25ECh. 12.1 - Prob. 26ECh. 12.1 - Prob. 27ECh. 12.1 - Prob. 28ECh. 12.1 - Prob. 29ECh. 12.1 - Prob. 30ECh. 12.1 - Prob. 31ECh. 12.1 - Prob. 32ECh. 12.2 - Prob. 1.1CYUCh. 12.2 - Prob. 1.2CYUCh. 12.2 - Prob. 1.3CYUCh. 12.2 - Prob. 1.4CYUCh. 12.2 - Prob. 33ECh. 12.2 - Prob. 34ECh. 12.2 - Prob. 35ECh. 12.2 - Prob. 36ECh. 12.2 - Prob. 37ECh. 12.2 - Prob. 38ECh. 12.2 - Prob. 39ECh. 12.2 - Prob. 40ECh. 12.2 - Prob. 41ECh. 12.2 - Prob. 42ECh. 12.2 - Prob. 43ECh. 12.2 - Prob. 44ECh. 12.2 - Prob. 45ECh. 12.2 - Prob. 46ECh. 12.2 - Prob. 47ECh. 12.2 - Prob. 48ECh. 12.2 - Prob. 49ECh. 12.2 - Prob. 50ECh. 12.2 - Prob. 51ECh. 12.2 - Prob. 52ECh. 12 - Prob. 1CRECh. 12 - Prob. 2CRECh. 12 - Prob. 3CRECh. 12 - Prob. 4CRECh. 12 - Prob. 5CRECh. 12 - Prob. 6CRECh. 12 - Prob. 1PTCh. 12 - Prob. 2PTCh. 12 - Prob. 3PTCh. 12 - Prob. 4PTCh. 12 - Prob. 5PTCh. 12 - Prob. 6PTCh. 12 - Prob. 7PTCh. 12 - Prob. 8PTCh. 12 - Prob. 9PTCh. 12 - Prob. 10PTCh. 12 - Prob. 11PTCh. 12 - Prob. 12PTCh. 12 - Prob. 1PT4Ch. 12 - Prob. 2PT4Ch. 12 - Prob. 3PT4Ch. 12 - Prob. 4PT4Ch. 12 - Prob. 5PT4Ch. 12 - Prob. 6PT4Ch. 12 - Prob. 7PT4Ch. 12 - Prob. 8PT4Ch. 12 - Prob. 9PT4Ch. 12 - Prob. 10PT4Ch. 12 - Prob. 11PT4Ch. 12 - Prob. 12PT4Ch. 12 - Prob. 13PT4Ch. 12 - Prob. 14PT4Ch. 12 - Prob. 15PT4Ch. 12 - Prob. 16PT4Ch. 12 - Prob. 17PT4Ch. 12 - Prob. 18PT4Ch. 12 - Prob. 19PT4Ch. 12 - Prob. 20PT4Ch. 12 - Prob. 21PT4Ch. 12 - Prob. 22PT4Ch. 12 - Prob. 23PT4Ch. 12 - Prob. 24PT4Ch. 12 - Prob. 25PT4Ch. 12 - Prob. 26PT4Ch. 12 - Prob. 27PT4Ch. 12 - Prob. 28PT4Ch. 12 - Prob. 29PT4Ch. 12 - Prob. 30PT4Ch. 12 - Prob. 31PT4Ch. 12 - Prob. 32PT4Ch. 12 - Prob. 33PT4Ch. 12 - Prob. 34PT4Ch. 12 - Prob. 35PT4Ch. 12 - Prob. 36PT4Ch. 12 - Prob. 37PT4Ch. 12 - Prob. 38PT4Ch. 12 - Prob. 39PT4Ch. 12 - Prob. 40PT4Ch. 12 - Prob. 41PT4Ch. 12 - Prob. 42PT4Ch. 12 - Prob. 43PT4Ch. 12 - Prob. 44PT4Ch. 12 - Prob. 45PT4Ch. 12 - Prob. 46PT4
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