a.
To find: The Solution of the linear system and find the value of x, y and z.
a.
Answer to Problem 2CRT
The solution of the system is
Explanation of Solution
Given:
The set of equation
Concept Used:
1. Determinant of any mented matrix is calculated. If determinant is non zero then surface is exist. If determinant value of zero then there is no solution of given set of equation.
2. Elimination method is used to solve the equation.
Calculation:
Writing in the matrix form of given set of equations
Find the determinant of above matrix.
Since determinant is non − zero hence there are unique solution for given set of equation.
Using elimination method, eliminate z from set of equation
Using z in rest of two equation we get
or
Multiplying first equation by
Putting u value in
Using x and y value in
We get
Hence
Conclusion:
The required values of x. y and z are
b.
To write: The coefficient of x, y, z in matrix form.
b.
Answer to Problem 2CRT
Explanation of Solution
Given information:
Concept Used:
The determinant of matrix
Calculation:
The determinant of matrix is given below:
Conclusion:
Determinant is zero, hence this set of equation has no solution.
Chapter 11 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
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