Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 11, Problem 12P
To determine

To Find: The time required by the spring.

Expert Solution & Answer
Check Mark

Answer to Problem 12P

The spring will take 0.282 s .

Explanation of Solution

Given info:

Mass m = 2.62 kg .

Distance x = 0.315 m .

Formula used:

Spring constant that can be found from the stretch distance corresponding to the weight suspended from spring.

Expression of force :

  F = k×xk = Fx = m×gx

Here,

  F is force,

  x is the displacement of spring,

  k is spring constant,

  m is mass on spring.

After being stretched further & released the maximum oscillate it takes one quarter of a period for a mass to move from a maximum displacement to the equilibrium position.

  t = 14×TT = 2π×mk

Here,

  T is the time period of oscillation.

  m is mass on spring.

  k is spring constant.

Calculation:

Substitute the given values in the above equation,

  k = 2.62 × 9.80.315 = 81.5 N/m t = 14 × 2π × 2.6281.5t = 0.282 s

Conclusion:

Thus, the new equilibrium position will be reach by spring in 0.282 s .

Chapter 11 Solutions

Physics: Principles with Applications

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