Statistics Through Applications
Statistics Through Applications
2nd Edition
ISBN: 9781429219747
Author: Daren S. Starnes, David Moore, Dan Yates
Publisher: Macmillan Higher Education
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Chapter 10.1, Problem 10.20E

(a)

To determine

To Calculate: the chi-square statistics and p-value.

(a)

Expert Solution
Check Mark

Answer to Problem 10.20E

  H0: There is no connection between smoking and Drinking.

  H1: There is a connection between smoking and Drinking.

Explanation of Solution

Given:

    Alcohol consumptionSmokedDid not smoke
    Yes2013
    No4896

Formula used:

  χ2=(OE)2E

  E=np

Assume

  α=0.05=5%

The null hypothesis statement is that there is no connection between the variables, where the alternative hypothesis statement is that there is a connection between the variable.

  H0: There is no connection between smoking and Drinking.

  H1: There is a connection between smoking and Drinking.

The row and column totals are

The expected frequencies E

  E11=r1×c1n=33×68177=12.6780E12=r1×c2n=33×109177=20.3220E21=r2×c1n=144×68177=55.3220E22=r2×c2n=144×109177=88.6780

The value of the test- statistic is

  χ2=(OE)2E=(2012.6780)212.6780+(1320.3220)220.3220+(4855.3220)255.3220+(9688.6780)288.6780=8.4405

The degree of freedom is.

  df=(r1)(c1)=(21)(21)=1

The P-Value is the probability of obtaining the value of the test statistic, or a value more extreme.

  0.001<P<0.01

(b)

To determine

To Explain: the conclusion from this study in plain language.

(b)

Expert Solution
Check Mark

Explanation of Solution

If the P-value is equal or less than to the significance level, then the alternative hypothesis is accepted and null hypothesis is rejected:

  P<0.05Reject H0

There is not enough evidence to help the claim that there is a connection between smoking and drinking.

Chapter 10 Solutions

Statistics Through Applications

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