Biology: Concepts and Investigations
5th Edition
ISBN: 9781260259049
Author: Hoefnagels
Publisher: MCG
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Chapter 10, Problem 8MCQ
Summary Introduction
Introduction:
The X linked disorder means that the genes causing the disorder or disease is present on the X chromosomes. The X linked disorder can be dominant or recessive. If the father carries the affected X chromosome, it will pass the affected chromosomes to all daughters not to son. If the mother carries the affected X chromosomes, it will pass the affected chromosomes to all the progeny.
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Students have asked these similar questions
For an X-linked recessive allele, what proportion of female offspring will be carriers in the cross of an affected father and a noncarrying mother?
a.50 percent
b.0 percent
c.100 percent
Baldness is a phenomenon where individuals lose hair as they grow older. As an X-linked recessive gene, what instances do females manifest this trait?
a. heterozygous recessive
b. heterozygous dominant
c. homozygous recessive
d. homozygous dominant
Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is a sex-linked disease which is caused by the recessive allele. Suppose, a man with hemophilia marries a woman who is homozygous dominant for the trait. Predict the genotype of the man. (XH = normal; Xh= hemophiliac) *
a. XH Y
b. XHXh
c. XhXh
d. Xh Y
Chapter 10 Solutions
Biology: Concepts and Investigations
Ch. 10.1 - Describe the relationships among chromosomes, DNA,...Ch. 10.1 - Prob. 2MCCh. 10.2 - Why did Gregor Mendel choose pea plants as his...Ch. 10.2 - Distinguish between dominant and recessive;...Ch. 10.2 - Prob. 3MCCh. 10.3 - What is a monohybrid cross, and what are the...Ch. 10.3 - How are Punnett squares helpful in following...Ch. 10.3 - Prob. 3MCCh. 10.3 - How does the law of segregation reflect the events...Ch. 10.4 - Prob. 1MC
Ch. 10.4 - Prob. 2MCCh. 10.4 - How can the product rule be used to predict the...Ch. 10.5 - How do patterns of inheritance differ for unlinked...Ch. 10.5 - What is the difference between recombinant and...Ch. 10.5 - Prob. 3MCCh. 10.6 - Prob. 1MCCh. 10.6 - Differentiate between pleiotropy and epistasis.Ch. 10.6 - How can the same phenotype stem from many...Ch. 10.6 - Figures 10.18 and 10.20 show two ways that a...Ch. 10.7 - Prob. 1MCCh. 10.7 - Prob. 2MCCh. 10.7 - Why do males and females express recessive...Ch. 10.7 - Prob. 4MCCh. 10.8 - Prob. 1MCCh. 10.8 - Prob. 2MCCh. 10.9 - Prob. 1MCCh. 10.9 - Prob. 2MCCh. 10.10 - Prob. 1MCCh. 10.10 - Prob. 2MCCh. 10 - In the list of four terms below, which term is the...Ch. 10 - According to Mendel, if an individual is...Ch. 10 - Prob. 3MCQCh. 10 - Which of the following is a possible gamete for an...Ch. 10 - Use the product rule to determine the chance of...Ch. 10 - Refer to the linkage map in figure 10.16b. A...Ch. 10 - How can epistasis decrease the number of...Ch. 10 - Prob. 8MCQCh. 10 - Prob. 9MCQCh. 10 - Prob. 1WIOCh. 10 - Prob. 2WIOCh. 10 - Some people compare a homologous pair of...Ch. 10 - How did Mendel use evidence from monohybrid and...Ch. 10 - Prob. 5WIOCh. 10 - Prob. 6WIOCh. 10 - Prob. 7WIOCh. 10 - Prob. 8WIOCh. 10 - Prob. 9WIOCh. 10 - A family has an X-linked dominant form of...Ch. 10 - X inactivation explains the large color patches in...Ch. 10 - Prob. 12WIOCh. 10 - Prob. 13WIOCh. 10 - Design an experiment using twins to determine the...Ch. 10 - Prob. 1GPCh. 10 - In Mexican hairless dogs, a dominant allele...Ch. 10 - A species of ornamental fish comes in two colors;...Ch. 10 - Two lizards have green skin and large dewlaps...Ch. 10 - Prob. 5GPCh. 10 - Prob. 6GPCh. 10 - Prob. 7GPCh. 10 - Prob. 8GPCh. 10 - Prob. 9GPCh. 10 - Prob. 1PITCh. 10 - Explain the effects of a mutation, using allele,...Ch. 10 - 3. Add meiosis, gametes, incomplete dominance,...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is referred to as a sex-linked disease. The recessive allele causes the disease. A man with hemophilia (xhy) marries a woman who is homozygous dominant (XHXH. A. Illustrate using a Punnett square the probability that their children will have the disease. B. Will any of their children have the disease? C. Predict the probabilities of their children having the disease.arrow_forwardTay-Sach's disease is caused by one gene. The disease is recessive. Is it possible for two healthy people to have a child with the disease? A. Yes B. No Is it possible for two people who both have the disease to have a healthy child? A. Yes B. Noarrow_forwardA boy is color-blind (X-linked recessive) and has a straight hairline (autosomal recessive). Which could be the genotype of his mother? Select one: А. Вbxwxw B. Bbww C. Xbxbww D. Xbywwarrow_forward
- A boy is color-blind (X-linked recessive) and has a straight hairline (autosomal recessive). Which could be the genotype of his mother? Select one: A. Bbxwxw B. Bbww C. Xbxbww D. Xbywwarrow_forwardA woman is a carrier for the color-blindness gene, found on the X chromosome. She does not have color blindness, however. What are the chances that her female child will also inherit this gene? a. no chance (0%) b. 1 in 4 chance (25%) c. 2 in 4 chance (50%) d. 100% chancearrow_forwardColor blindness is an x-linked recessive disorder. A woman who is a carrier for color blindness has children with a man who is color blind. Determine the probability that their child will be color blind. a. 0 % b. 25% c. 50% d. 100%arrow_forward
- Colorblindness is a recessive x-linked trait. Which genotype represents a male with normal vision? a. XNXN b. XYN c. XnY d. XNYarrow_forwardIf two parents are heterozygous for a genetically inherited dominant trait, what is the probability that they will have a child together who has this trait in his or her phenotype? a. 25% b. 50% c. 75% d. 100%arrow_forwardWhich statement about the pattern of inheritance for a recessive X-linked allele is true? A. Unaffected parents can produce daughters who are affected. B. Unaffected parents can have sons who are affected and daughters who are carriers. C. Unaffected fathers can be carriers. D. Affected parents do not produce affected children. E. Every affected person has an affected parent.arrow_forward
- If a woman is homozygous normal and her husband is heterozygous for a genetically inherited recessive disease and they decide to become parents, what is the probability that they will have a healthy child? a. 1 out of 4 b. 2 out of 4 c. 3 out of 4 d. 4 out of 4arrow_forwardPhenylketonuria (PKU) is a disease that results from a recessive gene.Suppose that two unaffected parents produce a child with PKU. a. What is the probability that a sperm from the father will contain the PKU allele?b. What is the probability that an egg from the mother will contain the PKU allele?c. What is the probability that their next child will have PKU?d. What is the probability that their next child will be heterozygous for the PKU gene?arrow_forwardPhenylketonuria (PKU) is a disease that results from a recessive gene. Suppose that two unaffected parents produce a child with PKU. a. What is the probability that a sperm from the father will contain the PKU allele? b. What is the probability that an egg from the mother will contain the PKU allele? c. What is the probability that their next child will have PKU? d. What is the probability that their next child will be heterozygous for the PKU gene?arrow_forward
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