Biology: Concepts and Investigations
5th Edition
ISBN: 9781260259049
Author: Hoefnagels
Publisher: MCG
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Chapter 10, Problem 11WIO
X inactivation explains the large color patches in calico cat fur and the smaller patches in tortoiseshell cat fur. In which type of cat do you expect X inactivation occurs earlier in development? Why?
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Chapter 10 Solutions
Biology: Concepts and Investigations
Ch. 10.1 - Describe the relationships among chromosomes, DNA,...Ch. 10.1 - Prob. 2MCCh. 10.2 - Why did Gregor Mendel choose pea plants as his...Ch. 10.2 - Distinguish between dominant and recessive;...Ch. 10.2 - Prob. 3MCCh. 10.3 - What is a monohybrid cross, and what are the...Ch. 10.3 - How are Punnett squares helpful in following...Ch. 10.3 - Prob. 3MCCh. 10.3 - How does the law of segregation reflect the events...Ch. 10.4 - Prob. 1MC
Ch. 10.4 - Prob. 2MCCh. 10.4 - How can the product rule be used to predict the...Ch. 10.5 - How do patterns of inheritance differ for unlinked...Ch. 10.5 - What is the difference between recombinant and...Ch. 10.5 - Prob. 3MCCh. 10.6 - Prob. 1MCCh. 10.6 - Differentiate between pleiotropy and epistasis.Ch. 10.6 - How can the same phenotype stem from many...Ch. 10.6 - Figures 10.18 and 10.20 show two ways that a...Ch. 10.7 - Prob. 1MCCh. 10.7 - Prob. 2MCCh. 10.7 - Why do males and females express recessive...Ch. 10.7 - Prob. 4MCCh. 10.8 - Prob. 1MCCh. 10.8 - Prob. 2MCCh. 10.9 - Prob. 1MCCh. 10.9 - Prob. 2MCCh. 10.10 - Prob. 1MCCh. 10.10 - Prob. 2MCCh. 10 - In the list of four terms below, which term is the...Ch. 10 - According to Mendel, if an individual is...Ch. 10 - Prob. 3MCQCh. 10 - Which of the following is a possible gamete for an...Ch. 10 - Use the product rule to determine the chance of...Ch. 10 - Refer to the linkage map in figure 10.16b. A...Ch. 10 - How can epistasis decrease the number of...Ch. 10 - Prob. 8MCQCh. 10 - Prob. 9MCQCh. 10 - Prob. 1WIOCh. 10 - Prob. 2WIOCh. 10 - Some people compare a homologous pair of...Ch. 10 - How did Mendel use evidence from monohybrid and...Ch. 10 - Prob. 5WIOCh. 10 - Prob. 6WIOCh. 10 - Prob. 7WIOCh. 10 - Prob. 8WIOCh. 10 - Prob. 9WIOCh. 10 - A family has an X-linked dominant form of...Ch. 10 - X inactivation explains the large color patches in...Ch. 10 - Prob. 12WIOCh. 10 - Prob. 13WIOCh. 10 - Design an experiment using twins to determine the...Ch. 10 - Prob. 1GPCh. 10 - In Mexican hairless dogs, a dominant allele...Ch. 10 - A species of ornamental fish comes in two colors;...Ch. 10 - Two lizards have green skin and large dewlaps...Ch. 10 - Prob. 5GPCh. 10 - Prob. 6GPCh. 10 - Prob. 7GPCh. 10 - Prob. 8GPCh. 10 - Prob. 9GPCh. 10 - Prob. 1PITCh. 10 - Explain the effects of a mutation, using allele,...Ch. 10 - 3. Add meiosis, gametes, incomplete dominance,...
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- Several loci affect hair development in dogs. The allele for wire hair (W) is dominant to Its allele for straight hair (w). Allow H to represent hairlessness in the Mexican hairless dog and its recessive allele h to represent the gene for typical hair growth in other breeds. The Mexican hairless dog is homozygous for straight hair, but because of epistatic effects of H, alleles for hair formation cannot be expressed. Write genotypes of the following animals with respect to the two loci mentioned. a.) a Mexican hairless dog b.) a dog with straight hair c.) a dog from a strain that is pure breeding for wire hair.arrow_forwardHuman females who are heterozygous for an X-linked recessive allele sometimes exhibit mild expression of the trait. However, such mild expression of X-linked traits in females who are heterozygous for Xlinked alleles is not seen in Drosophila. What might cause this difference in the expression of X-linked genes between human females and female Drosophila? (Hint: In Drosophila, dosage compensation is accomplished by doubling the activity of genes on the X chromosome of males.)arrow_forwardA number of genes that control expression of Hox genes in Drosophila have been identified. One of these homozygous mutants is extra sex combs, where some of the head and all of the thorax and abdominal segments develop as the last abdominal segment. In other words, all affected segments develop as posterior segments. What does this phenotype tell you about which set of Hox genes is controlled by the extra sex combs gene?arrow_forward
- What would be the most likely effect on development of puncturing the posterior end of a Drosophila egg, allowing a small amount of cytoplasm to leak out, and then injecting that cytoplasm into the anterior end of another egg?arrow_forwardIn domesticated cats, the following are Independently assorting: 6. Normal ears (T) is dominant to tufted ears (t); Curved whiskers (C) is dominant to straight whiskers (c); The presence of six toes (S) is dominant to five toes (s); Gene for hair length is an X-linked codominant. The three phenotypes for hair length are long (XHXH), medium (X"X*), and short (X"Xh); medium is the heterozygous condition. Given two parents: TtccSSXHXh x TtCcSsXHY a) How many different gametes could be formed in the female cat with respect to these four traits? b) How many different phenotypes are possible in the offspring from this mating?arrow_forwardIn Drosophila sex determination (Check all that apply.) A) XY individuals transcribe the Sxl gene early but not late. B XX individuals carry the Sxl gene, XY individuals do not. XX individuals transcribe the Sxl gene, XY individuals do not. XX individuals express the Sxl protein, XY individuals do not. E) The Sxl transcript (Pre-MRNA) is spliced differently in XX compared to XY individuals.arrow_forward
- In wheat, aleurone cells form a thin layer of the seed coat that is critical to early gene expression in plant development. The color of this layer of cells is controlled by two alleles of a gene [colored aleurone (R) is dominant to colorless (r)]. A second gene is known to control the color of leaf tips [green leaf tip (G) is dominant to yellow (g)]. Two plants, each heterozygous for both characteristics, are test crossed to homozygous recessives, and their progeny are combined to produce the following totals: colored green 102 colored yellow 98 colorless green 103 colorless yellow 97 a) Use chi-square analysis to test these data for an independent assortment of the two characteristics (table provided). Please show work, how your expected values are calculated, and explain what your results indicate about the data. b) You decide to be cautious in your analysis, and decide to analyze the progeny from each of the crosses individually (instead of adding them together as shown above).…arrow_forwardDescribe all the possible genotypes for a mouse with that phenotype.arrow_forwardThere are two genes that determine the coat colour expression in some dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype Phenotype MM White Mm Half colour (Grey or light red) mm Full colour (Black or Red) Two dogs heterozygous for both traits were crossed. What phenotypic ratio is expected in the F1 generation? Answer: Phenotype: White Grey Black Light Red Redarrow_forward
- There are two genes that determine the coat colour expression in some dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype Phenotype MM White Mm Half colour (Grey or light red) mm Full colour (Black or Red) A grey dog that is heterozygous for the eumelanin gene mates with a light red dog. 1. What is the probability they would have a grey puppy? 2. What is the probability they would have a grey or light red puppy?arrow_forwarda) Assume that colour is controlled by a single sex-influenced gene where green is expressed preferentially in males. Individuals I-1 and I-2 are homozygous for red and green respectively. Which individual/s in generation II will be red? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be green?arrow_forwardIn mice there are two loci responsible for coat color: Locus 1B- determines whether hair has bands: B- results in hair with bands & produces an agouti coat pigment (brown) b- homozygotes have no bands & their coat pigment is black Locus 2A- affects enzymes responsible for pigment production: A- results in normal pigment production a- homozygotes block all of the pigment production & are albino (white) What are the possible genotypes & phenotypes of the progeny if you were to cross 2 mice, which are heterozygous for both traits? What type of gene action is being expressed in this example?arrow_forward
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