Biology: Concepts and Investigations
5th Edition
ISBN: 9781260259049
Author: Hoefnagels
Publisher: MCG
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Chapter 10, Problem 5GP
Summary Introduction
To describe:
The proportion of offspring being heterozygous for all the genes.
Concept introduction:
Mating between two ferns, one having genotype
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Students have asked these similar questions
A heterozygous pea plant that is tall with yellow seeds, TtGg, is allowed to self-fertilize. What is the probability that an offspring will be either tall with yellow seeds, tall with green seeds or dwarf with yellow seeds? Use the Sum Rule to calculate the probability asked in the problem.
A pea plant is heterozygous for both pod shape and color. I is the allele for dominant, inflated pod; i is the allele for recessive, constricted pod. G is the allele for dominant, green pod; g is the allele for recessive, yellow color characteristic. Suppose this plant is crossed with a homozygous pea with inflated, green pod, what will be the possible genotype of the offspring?
Construct the punnet square, then identify the following:
1. Parents’ genes?2. Parents’ traits?3. Genes (genotype)?4. Shape, color? (phenotype)?5. Genotypic ratio?6. Phenotypic ratio?
The diagram shows a plant that is heterozygous for two genes.
G = yellow; g = green; R = round; r = wrinkled
G
Four different types of gametes are produced by a heterozygous individual when crossing over occurs, and two different types of gametes are produced when
crossing over does not occur. What does this information reveal about crossng over?
O Crossing over introduces variety by producing different combinations of alleles.
O Crossing over reduces the incidence of DNA and chromosomal mutations.
O Crossing over introduces variety in
by creating
types of genes.
O Crossing over maintains the count of genes and the original alleles in both chromosomes.
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Chapter 10 Solutions
Biology: Concepts and Investigations
Ch. 10.1 - Describe the relationships among chromosomes, DNA,...Ch. 10.1 - Prob. 2MCCh. 10.2 - Why did Gregor Mendel choose pea plants as his...Ch. 10.2 - Distinguish between dominant and recessive;...Ch. 10.2 - Prob. 3MCCh. 10.3 - What is a monohybrid cross, and what are the...Ch. 10.3 - How are Punnett squares helpful in following...Ch. 10.3 - Prob. 3MCCh. 10.3 - How does the law of segregation reflect the events...Ch. 10.4 - Prob. 1MC
Ch. 10.4 - Prob. 2MCCh. 10.4 - How can the product rule be used to predict the...Ch. 10.5 - How do patterns of inheritance differ for unlinked...Ch. 10.5 - What is the difference between recombinant and...Ch. 10.5 - Prob. 3MCCh. 10.6 - Prob. 1MCCh. 10.6 - Differentiate between pleiotropy and epistasis.Ch. 10.6 - How can the same phenotype stem from many...Ch. 10.6 - Figures 10.18 and 10.20 show two ways that a...Ch. 10.7 - Prob. 1MCCh. 10.7 - Prob. 2MCCh. 10.7 - Why do males and females express recessive...Ch. 10.7 - Prob. 4MCCh. 10.8 - Prob. 1MCCh. 10.8 - Prob. 2MCCh. 10.9 - Prob. 1MCCh. 10.9 - Prob. 2MCCh. 10.10 - Prob. 1MCCh. 10.10 - Prob. 2MCCh. 10 - In the list of four terms below, which term is the...Ch. 10 - According to Mendel, if an individual is...Ch. 10 - Prob. 3MCQCh. 10 - Which of the following is a possible gamete for an...Ch. 10 - Use the product rule to determine the chance of...Ch. 10 - Refer to the linkage map in figure 10.16b. A...Ch. 10 - How can epistasis decrease the number of...Ch. 10 - Prob. 8MCQCh. 10 - Prob. 9MCQCh. 10 - Prob. 1WIOCh. 10 - Prob. 2WIOCh. 10 - Some people compare a homologous pair of...Ch. 10 - How did Mendel use evidence from monohybrid and...Ch. 10 - Prob. 5WIOCh. 10 - Prob. 6WIOCh. 10 - Prob. 7WIOCh. 10 - Prob. 8WIOCh. 10 - Prob. 9WIOCh. 10 - A family has an X-linked dominant form of...Ch. 10 - X inactivation explains the large color patches in...Ch. 10 - Prob. 12WIOCh. 10 - Prob. 13WIOCh. 10 - Design an experiment using twins to determine the...Ch. 10 - Prob. 1GPCh. 10 - In Mexican hairless dogs, a dominant allele...Ch. 10 - A species of ornamental fish comes in two colors;...Ch. 10 - Two lizards have green skin and large dewlaps...Ch. 10 - Prob. 5GPCh. 10 - Prob. 6GPCh. 10 - Prob. 7GPCh. 10 - Prob. 8GPCh. 10 - Prob. 9GPCh. 10 - Prob. 1PITCh. 10 - Explain the effects of a mutation, using allele,...Ch. 10 - 3. Add meiosis, gametes, incomplete dominance,...
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- If a pea plant with the genotype YyRr is self-fertilized, what is the probability of obtaining offspring that are homozygous dominant for both traits?arrow_forwardIf a pea plant with the genotype YyRr is self-fertilized, what is the probability of obtaining offspring that are heterozygous for seed color and homozygous dominant for seed shape.arrow_forwardA plant with a genotype MmNN is self-fertilized. What is the genotypic ratio of the offspring?arrow_forward
- Crosses between white and red flowered plants may result in pink flowered offspring. When a pink flowered plant is crossed with a red flowered plant the phenotypic ratio of their offspring would be O 2 white : 2 red 2 red : 2 pink O1 white : 2 pink : 1 red O1 white : 2 red : 1 pink 2 pink : 2 whitearrow_forwardThe genetic identity of the female parent is RrGg and the genetic identity of the male parent is Rrgg. They produce 320 offspring together from a single mating: 57 red-eyed females with grey bodies, 61 red-eyed females with yellow bodies, 22 brown-eyed females with grey bodies, 20 brown-eyed females with yellow bodies.59 red-eyed males with grey bodies, 63 red-eyed males with yellow bodies, 20 brown-eyedmales with grey bodies, 18 brown-eyed males with yellow bodies. Show the simultaneous transmission of the two genes involved to give rise to the progeny given with the use of genetic diagrams and summaries as required. (Hint: you are only requiredto show the simultaneous transmission from the P to F1 generations)arrow_forwardUse the figure and the following description to answer the question(s) below. In a particular plant, leaf color is controlled by gene locus D. Plants with at least one allele D have dark green leaves, and plants with the homozygous recessive dd genotype have light green leaves. A true- breeding, dark- leaved plant is crossed with a light- leaved one, and the F1 offspring is allowed to self- pollinate. The predicted outcome of the F2 is diagrammed in the Punnett square shown in the figure, where 1,2,3, and 4 represent the genotypes corresponding to each box within the square. D d D 1 2 4 Which of the boxes marked 1- 4 correspond to plants with a heterozygous genotype? 2 and 3 1 1,2, and 3 2, 3, and 4 3.arrow_forward
- A pea plant is heterozygous for both pod shape and color. I is the allele for dominant, inflated pod; i is the allele for recessive, constricted pod. G is the allele for dominant, green pod; g is the allele for recessive, yellow color characteristic. Suppose this plant is crossed with a homozygous pea with inflated, green pod, what will be the possible genotype of the offspring? Identify the: Parents’ genes?Parents’ traits?Genes (genotype)?Shape, color? (phenotype)?Genotypic ratio?Phenotypic ratio?arrow_forwardCOU f) What kind of offspring can be produced if a red-flowered plant is crossed with a pink-flowered plant? Show your work. g) What kind of offspring is/are produced if a pink-flowered plant is crossed with a white-flowered plant? Show your work. hleodarrow_forwardUse the following information about pea plants: S = spherical seeds; s = wrinkled seeds Y = yellow seeds; y = green seeds P = purple flowers; p = white flowers I = inflated pods; i = constricted pods Write the possible genotypes for the following conditions: Heterozygous for spherical seeds Homozygous for wrinkled seeds Homozygous for spherical seeds and heterozygous for flower colorarrow_forward
- In plants known as “ four o’ clocks”, the allele for the dominant red- flower color is is completely dominant over the allele for white-flowers. A gardener allows several heterozygous pink-flowered four o'clock to self pollinate and collects 200 seeds. Identify the flower color phenotypes and theoretical percentage.arrow_forwardThe trait of medium-sized leaves in iris is determined by the heterozygous genotype RT. Plants with large leaves are IKIK, whereas plants with small leaves are l'I A cross is made between two plants, each with medium-sized leaves. If they produce 80 seedlings, what would be the expected number of seedlings with small leaves? O a) 0 O b) 20 Oc) 40 Od) 80arrow_forwardThe trait of medium-sized leaves in iris is determined by the heterozygous genotype TRir. Plants with large leaves are IRIR, whereas plants with small leaves are l'I A cross is made between two plants, each with medium-sized leaves. If they produce 80 seedlings, what would be the expected number of seedlings with small leaves? O a) 0 O b) 20 Oc) 40 d) 80arrow_forward
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