Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 10, Problem 10.99QE
The molecular orbital diagram of NO shown in Figure 10.47 also applies to the following species. Write the molecular orbital electron configuration of each, indicating the bond order and the number of unpaired electrons.
- (a) CN
- (b) CO–
- (c) BeB–
- (d) BC+
Figure 10.47 Molecular orbital diagram for nitric oxide (NO). The molecular orbital diagram for NO predicts a bond order of 2.5 and predicts that the molecule is paramagnetic with one unpaired electron. These predictions are verified by experimental measurements.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Consider the reaction BF3 + NH3 -> F3B-NH3
(a) Describe the changes in hybridization of the B and N atoms as a result of this reaction.
(b) Describe the shapes of all the reactant molecules with their bond angles.
(c) Draw the overall shape of the product molecule and identify the bond angles around B and N atoms.
(d) What is the name of the bond between B and N.
(e)Describe the bonding orbitals that make the B and F, B and N & N and H bonds in the product molecule.
The structure of caffeine is shown below.
(a) Complete the Lewis structure.
(b) How many pi bonds are present in caffeine? How many sigma bonds?
(c) Identify the hybridization of the carbon atoms.
(d) What is the value of the O-C-N angle?
Butadiene, C4H6, is a planar molecule that has the followingcarbon–carbon bond lengths:
(a) Predict the bond angles around each of the carbon atoms and sketch the molecule. (b) From left to right, what is the hybridization of each carbon atom in butadiene? (c) The middle C—C bond length in butadiene (1.48 Å) is a little shorter than the average C—C single bond length (1.54 Å). Does this imply that the middle C—C bond in butadiene is weaker or stronger than the average C—C single bond? (d) Based on your answer for part (c), discuss what additional aspects of bonding in butadiene might support the shorter middle C—C bond.
Chapter 10 Solutions
Chemistry: Principles and Practice
Ch. 10 - Prob. 10.1QECh. 10 - Prob. 10.2QECh. 10 - Prob. 10.3QECh. 10 - Prob. 10.4QECh. 10 - Prob. 10.5QECh. 10 - Prob. 10.6QECh. 10 - Prob. 10.7QECh. 10 - Prob. 10.8QECh. 10 - Prob. 10.9QECh. 10 - Prob. 10.10QE
Ch. 10 - Which atomic orbitals overlap to form the bonds in...Ch. 10 - Prob. 10.12QECh. 10 - Identify the hybrid orbitals used by boron in BCl3...Ch. 10 - Identify the hybrid orbitals used by antimony in...Ch. 10 - Prob. 10.15QECh. 10 - Prob. 10.16QECh. 10 - Prob. 10.17QECh. 10 - Prob. 10.18QECh. 10 - Prob. 10.19QECh. 10 - Prob. 10.20QECh. 10 - Compare and contrast the molecular orbital and...Ch. 10 - Describe the bonding in molecular orbital terms...Ch. 10 - Prob. 10.23QECh. 10 - Prob. 10.24QECh. 10 - Prob. 10.25QECh. 10 - Prob. 10.26QECh. 10 - Prob. 10.27QECh. 10 - Prob. 10.28QECh. 10 - Prob. 10.29QECh. 10 - Prob. 10.30QECh. 10 - Prob. 10.31QECh. 10 - Prob. 10.32QECh. 10 - Prob. 10.33QECh. 10 - Prob. 10.34QECh. 10 - Prob. 10.35QECh. 10 - Prob. 10.36QECh. 10 - Prob. 10.37QECh. 10 - Prob. 10.38QECh. 10 - Prob. 10.39QECh. 10 - Use the VSEPR model to predict the bond angles...Ch. 10 - Prob. 10.41QECh. 10 - Prob. 10.42QECh. 10 - For each of the following molecules, complete the...Ch. 10 - Prob. 10.44QECh. 10 - Prob. 10.45QECh. 10 - Prob. 10.46QECh. 10 - Indicate which molecules are polar and which are...Ch. 10 - Prob. 10.48QECh. 10 - Indicate which of the following molecules are...Ch. 10 - Prob. 10.50QECh. 10 - Prob. 10.51QECh. 10 - Prob. 10.52QECh. 10 - Prob. 10.53QECh. 10 - Prob. 10.54QECh. 10 - Prob. 10.55QECh. 10 - Prob. 10.56QECh. 10 - Prob. 10.57QECh. 10 - Prob. 10.58QECh. 10 - Prob. 10.59QECh. 10 - Prob. 10.60QECh. 10 - Prob. 10.61QECh. 10 - Prob. 10.62QECh. 10 - Prob. 10.63QECh. 10 - Prob. 10.64QECh. 10 - Prob. 10.65QECh. 10 - Prob. 10.66QECh. 10 - Prob. 10.67QECh. 10 - Prob. 10.68QECh. 10 - Prob. 10.69QECh. 10 - Prob. 10.70QECh. 10 - Prob. 10.71QECh. 10 - Prob. 10.72QECh. 10 - Identify the orbitals on each of the atoms that...Ch. 10 - Prob. 10.74QECh. 10 - Prob. 10.75QECh. 10 - How many sigma bonds and how many pi bonds are...Ch. 10 - Give the hybridization of each central atom in the...Ch. 10 - Prob. 10.78QECh. 10 - Prob. 10.79QECh. 10 - Prob. 10.80QECh. 10 - Prob. 10.81QECh. 10 - Predict the hybridization at each central atom in...Ch. 10 - Prob. 10.83QECh. 10 - Tetrafluoroethylene, C2F4, is used to produce...Ch. 10 - Prob. 10.85QECh. 10 - Prob. 10.86QECh. 10 - Prob. 10.87QECh. 10 - Prob. 10.88QECh. 10 - Prob. 10.89QECh. 10 - Prob. 10.90QECh. 10 - Prob. 10.91QECh. 10 - Prob. 10.92QECh. 10 - Prob. 10.93QECh. 10 - Prob. 10.94QECh. 10 - Prob. 10.95QECh. 10 - Prob. 10.96QECh. 10 - Prob. 10.97QECh. 10 - Prob. 10.98QECh. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - Prob. 10.102QECh. 10 - Prob. 10.103QECh. 10 - Prob. 10.104QECh. 10 - Prob. 10.105QECh. 10 - Following are the structures of three isomers of...Ch. 10 - The ions ClF2 and ClF2+ have both been observed....Ch. 10 - Aspirin, or acetylsalicylic acid, has the formula...Ch. 10 - Aspartame is a compound that is 200 times sweeter...Ch. 10 - Prob. 10.110QECh. 10 - Prob. 10.111QECh. 10 - Calcium cyanamide, CaNCN, is used both to kill...Ch. 10 - Histidine is an essential amino acid that the body...Ch. 10 - Formamide, HC(O)NH2, is prepared at high pressures...Ch. 10 - Prob. 10.115QECh. 10 - Prob. 10.116QECh. 10 - Prob. 10.117QECh. 10 - Prob. 10.118QECh. 10 - Prob. 10.119QECh. 10 - Prob. 10.120QECh. 10 - Prob. 10.121QECh. 10 - Prob. 10.122QECh. 10 - Prob. 10.123QECh. 10 - Prob. 10.124QECh. 10 - Two compounds have the formula S2F2. Disulfur...Ch. 10 - Prob. 10.126QECh. 10 - Prob. 10.127QE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- What hybrid orbitals would be expected for the central atom in each of the following molecules or ions?arrow_forwardIdentify the hybrid orbitals used by boron in BCl3 and in BCl4, the ion formed from the reaction of BCl3 and Cl. Explain your choices.arrow_forwardDraw the Lewis structure for 1, 1-dimethylhydrazine [(CH3)2NNH2, a compound used as a rocket fuel]. What: is the hybridization for the two nitrogen atoms in this molecule? What orbitals overlap to form the bond between the nitrogen atoms?arrow_forward
- The structure of amphetamine, a stimulant, is shown below. (Replacing one H atom on the NH2, or amino, group with CH3 gives methamphetamine a particularly dangerous drug commonly known as speed.) (a) What are the hybrid orbitals used by the C atoms of the C6 ring. by the C atoms of the side chain, and by the N atom? (b) Give approximate values for the bond angles A, B, and C. (c) How many bonds and bonds are in the molerule? (d) Is the molecule polar or nonpolar? (e) Amphetamine reacts readily with a proton (H+) in aqueous solution. Where does this proton attach to the molecule? Explain how the electrostatic potential map predicts this site of protonation.arrow_forwardConsider the molecule, CHCIBII, which statement is INCORRECT? (1) The molecule has a tetrahedral structure (2) The size of the H-C-Br bond angle is 109.5°. (3) The carbon atom is sp3 hybridized (4) The carbon atom is sp2 hybridizedarrow_forward7. Nitrogen is the central atom in each of the species given. (a) Draw the Lewis electron-dot structure for each of the species. + NO₂ NO₂ NO₂ (b) List the species in order of increasing bond angle. Justify your answer. (c) For NO₂ and NO₂, give the hybridization of the nitrogen atom in it. (d) Identify the only one of the species that dimerizes and explain what causes it to do so.arrow_forward
- Draw the molecular orbital energy diagrams for the valence electrons in the following diatomic molecules. Calculate the bond order and indicate if each of them is diamagnetic or paramagnetic. (а) В> (b) С. (c) CO (d) NO (е) Оzarrow_forward. Assume that the third-period element phosphorus forms a diatomic molecule, P2, in an analogous way as nitrogen does to form N2. (a) Write the electronic configuration for P2. Use [Ne2] to represent the electron configuration for the first two periods. (b) Calculate its bond order. (c) What are its magnetic properties (diamagnetic or paramagnetic)?arrow_forwardValence bond theory The skeletal structure for methyleneimine (CH₂NH) is shown. Draw for yourself the best Lewis structure. Propose a bonding scheme by indicating the hybridization of the central atoms and the orbital overlaps for each bond. (a) H one (b) H-C-N-H The bond labeled (a) forms from The bond labeled (b) forms from: ● one o-overlap of a C (c) π-overlap (s) of a C -overlap of a C sp2 orbital and a N orbital and a N orbital and a H 1s The ideal bond angle <(C-N-H) around the N atom is orbital, and orbital. The bond labeled (c) forms from O - overlap of a N There is/are one lone pair(s) around the N atom. Lewis structures do not attempt to portray 3D shape, but you can predict the molecular geometry from VSEPR theory. The ideal bond angle <(H-C-H) around the C atom is 120 orbital and a H 1s degrees. orbital. degrees. orbital.arrow_forward
- Use valence bond theory to explain the bonding in F2, HF, and ClBr. (a) F2 This molecule is symmetrical. The single bond present in this molecule is derived from the overlap of two (1s, 2s, 2p, 3s, 3d, 3p, 4s, 4d, 4p) orbitals contributed by each of the F atoms. (b) HF This molecule is asymmetrical. The single bond present in this molecule is derived from the overlap of one (1s, 2s, 2p, 3s, 3d, 3p, 4s, 4d, 4p) orbital contributed by the H atom and one (1s, 2s, 2p, 3s, 3d, 3p, 4s, 4d, 4p) orbital contributed by the F atom. (c) ClBr This molecule is also asymmetrical. The single bond present in this molecule is derived from the overlap of one (1s, 2s, 2p, 3s, 3d, 3p, 4s, 4d, 4p) orbital contributed by the Cl atom and one (1s, 2s, 2p, 3s, 3d, 3p, 4s, 4d, 4p) orbital contributed by the Br atom. Sketch the overlap of the atomic orbitals involved in the bonds.arrow_forwardFormaldehyde (H.CO) molecules (H: 1s!, C: 1s 2s 2p and O: 1s 2s 2p+) (a) Use Orbital Hybridization theory to determine the molecular shape of H.CO. (b) What bonds are formed between the C and O atoms in formaldehyde molecules?arrow_forwardWhich of the following statements is INCORRECT? (1) In the hybridized state, mixing of the 2s orbitals with the 2px, 2py and/or 2pz orbitals can give sp, sp2 or sp3 hybrid orbitals. (2) A sp3 hybrid orbital is formed from one s-orbital and three p-orbitals to give a total of four orbitals. (3) There are no unhybrized orbitals when carbon is sp3 hybridized. (4) There are no unhybrized orbitals when carbon is sp2 hybridized.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
General Chemistry 1A. Lecture 12. Two Theories of Bonding.; Author: UCI Open;https://www.youtube.com/watch?v=dLTlL9Z1bh0;License: CC-BY