Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 10, Problem 10.17QE
Interpretation Introduction

Interpretation:

A sigma and pi bonds has to be defined and the formation of these bonds by the overlapping of p orbitals has to be given.

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Bonding in the chlorine molecule can be explained by the valence bond theory in terms of an overlap between The 1s orbital of a chlorine atom and the 1s orbital of the other chlorine atom The 3p orbital of a chlorine atom and the 3p orbital of the other chlorine atom 2p orbital of chlorine atom and 2p of other chlorine atom The 2s orbital of chlorine atom and 2s of other chlorine The 3s orbital of chlorine and 3s of other chlorine atom
Sketch an orbital picture of ethylene, H2C = CH2, and highlight the orbitals that overlap to formeach σ and π bond. Identify the orbitals from each atom that overlap to form the σ and π bonds. Why isthe C⎯ C π bond weaker than the C⎯ C σ bond? Use orbital structure as part of your explanation.
Use the molecular orbital model to fully describe the bonding in O2+, O2, O2-, and O22-.Determine which of the following statements are true and which are false. True or false? : Bond length increases with increasing bond order while bond energy decreases.The number of unpaired electrons in O2- and O2 is, respectively, 1 and 2. The electron configuration of O2 is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)1.  The electron configuration of O2- is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)3.  The bond order in O2- and O22- is, respectively, 2.5 and 1.    The bond lengths increase in the order: O22- < O2- < O2 < O2+.

Chapter 10 Solutions

Chemistry: Principles and Practice

Ch. 10 - Which atomic orbitals overlap to form the bonds in...Ch. 10 - Prob. 10.12QECh. 10 - Identify the hybrid orbitals used by boron in BCl3...Ch. 10 - Identify the hybrid orbitals used by antimony in...Ch. 10 - Prob. 10.15QECh. 10 - Prob. 10.16QECh. 10 - Prob. 10.17QECh. 10 - Prob. 10.18QECh. 10 - Prob. 10.19QECh. 10 - Prob. 10.20QECh. 10 - Compare and contrast the molecular orbital and...Ch. 10 - Describe the bonding in molecular orbital terms...Ch. 10 - Prob. 10.23QECh. 10 - Prob. 10.24QECh. 10 - Prob. 10.25QECh. 10 - Prob. 10.26QECh. 10 - Prob. 10.27QECh. 10 - Prob. 10.28QECh. 10 - Prob. 10.29QECh. 10 - Prob. 10.30QECh. 10 - Prob. 10.31QECh. 10 - Prob. 10.32QECh. 10 - Prob. 10.33QECh. 10 - Prob. 10.34QECh. 10 - Prob. 10.35QECh. 10 - Prob. 10.36QECh. 10 - Prob. 10.37QECh. 10 - Prob. 10.38QECh. 10 - Prob. 10.39QECh. 10 - Use the VSEPR model to predict the bond angles...Ch. 10 - Prob. 10.41QECh. 10 - Prob. 10.42QECh. 10 - For each of the following molecules, complete the...Ch. 10 - Prob. 10.44QECh. 10 - Prob. 10.45QECh. 10 - Prob. 10.46QECh. 10 - Indicate which molecules are polar and which are...Ch. 10 - Prob. 10.48QECh. 10 - Indicate which of the following molecules are...Ch. 10 - Prob. 10.50QECh. 10 - Prob. 10.51QECh. 10 - Prob. 10.52QECh. 10 - Prob. 10.53QECh. 10 - Prob. 10.54QECh. 10 - Prob. 10.55QECh. 10 - Prob. 10.56QECh. 10 - Prob. 10.57QECh. 10 - Prob. 10.58QECh. 10 - Prob. 10.59QECh. 10 - Prob. 10.60QECh. 10 - Prob. 10.61QECh. 10 - Prob. 10.62QECh. 10 - Prob. 10.63QECh. 10 - Prob. 10.64QECh. 10 - Prob. 10.65QECh. 10 - Prob. 10.66QECh. 10 - Prob. 10.67QECh. 10 - Prob. 10.68QECh. 10 - Prob. 10.69QECh. 10 - Prob. 10.70QECh. 10 - Prob. 10.71QECh. 10 - Prob. 10.72QECh. 10 - Identify the orbitals on each of the atoms that...Ch. 10 - Prob. 10.74QECh. 10 - Prob. 10.75QECh. 10 - How many sigma bonds and how many pi bonds are...Ch. 10 - Give the hybridization of each central atom in the...Ch. 10 - Prob. 10.78QECh. 10 - Prob. 10.79QECh. 10 - Prob. 10.80QECh. 10 - Prob. 10.81QECh. 10 - Predict the hybridization at each central atom in...Ch. 10 - Prob. 10.83QECh. 10 - Tetrafluoroethylene, C2F4, is used to produce...Ch. 10 - Prob. 10.85QECh. 10 - Prob. 10.86QECh. 10 - Prob. 10.87QECh. 10 - Prob. 10.88QECh. 10 - Prob. 10.89QECh. 10 - Prob. 10.90QECh. 10 - Prob. 10.91QECh. 10 - Prob. 10.92QECh. 10 - Prob. 10.93QECh. 10 - Prob. 10.94QECh. 10 - Prob. 10.95QECh. 10 - Prob. 10.96QECh. 10 - Prob. 10.97QECh. 10 - Prob. 10.98QECh. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - The molecular orbital diagram of NO shown in...Ch. 10 - Prob. 10.102QECh. 10 - Prob. 10.103QECh. 10 - Prob. 10.104QECh. 10 - Prob. 10.105QECh. 10 - Following are the structures of three isomers of...Ch. 10 - The ions ClF2 and ClF2+ have both been observed....Ch. 10 - Aspirin, or acetylsalicylic acid, has the formula...Ch. 10 - Aspartame is a compound that is 200 times sweeter...Ch. 10 - Prob. 10.110QECh. 10 - Prob. 10.111QECh. 10 - Calcium cyanamide, CaNCN, is used both to kill...Ch. 10 - Histidine is an essential amino acid that the body...Ch. 10 - Formamide, HC(O)NH2, is prepared at high pressures...Ch. 10 - Prob. 10.115QECh. 10 - Prob. 10.116QECh. 10 - Prob. 10.117QECh. 10 - Prob. 10.118QECh. 10 - Prob. 10.119QECh. 10 - Prob. 10.120QECh. 10 - Prob. 10.121QECh. 10 - Prob. 10.122QECh. 10 - Prob. 10.123QECh. 10 - Prob. 10.124QECh. 10 - Two compounds have the formula S2F2. Disulfur...Ch. 10 - Prob. 10.126QECh. 10 - Prob. 10.127QE
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