Fundamentals of Electromagnetics with Engineering Applications
1st Edition
ISBN: 9780470105757
Author: Stuart M. Wentworth
Publisher: Wiley, John & Sons, Incorporated
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Chapter 10, Problem 10.40P
To determine
To design: A third order Chebyshev bandpass filter.
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Chapter 10 Solutions
Fundamentals of Electromagnetics with Engineering Applications
Ch. 10 - A matching network consists of a length of a...Ch. 10 - Design an L-section matching network to match a...Ch. 10 - Design an L-section matching network to match an...Ch. 10 - Design an L-section matching network to match a...Ch. 10 - Suppose you want to match a 100 line to a load...Ch. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Prob. 10.10PCh. 10 - Suppose the L-section matching network of Example...
Ch. 10 - Find the scattering matrices for the simple...Ch. 10 - Cut a 50- T-line and insert a series 50- resistor...Ch. 10 - Prob. 10.14PCh. 10 - A series capacitor of value C=2.0pF is inserted in...Ch. 10 - A series inductor of value L=3.5nH is inserted in...Ch. 10 - Prob. 10.17PCh. 10 - The scattering matrix (assuming a 50- impedance...Ch. 10 - Three T-lines with the same characteristic...Ch. 10 - Consider a three-port network that is matched at...Ch. 10 - Prob. 10.21PCh. 10 - Calculate the insertion loss and the VSWR for the...Ch. 10 - Prob. 10.23PCh. 10 - Verify the scattering matrix (10.27) for the...Ch. 10 - Prob. 10.25PCh. 10 - Prob. 10.26PCh. 10 - A four-port 20-dB coupler is specified as having...Ch. 10 - Suppose the coupling for an ideal symmetrical...Ch. 10 - Suppose to port 1 of an ideal ring hybrid coupler...Ch. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Suppose you join a pair of quadrature hybrid...Ch. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Prob. 10.39PCh. 10 - Prob. 10.40PCh. 10 - Starting with the Figure 10.28b circuit...Ch. 10 - Starting with the Figure lO.28b circuit...Ch. 10 - Prob. 10.43PCh. 10 - Starting with the Figure 10.28a circuit...Ch. 10 - Prob. 10.45PCh. 10 - For Problem 10.45, (a) design open-ended shunt...Ch. 10 - Prob. 10.47PCh. 10 - Prob. 10.48PCh. 10 - Prob. 10.49PCh. 10 - Prob. 10.50PCh. 10 - Prob. 10.51PCh. 10 - Referring to Example 10.21 and Figure 10.48,...
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- [Q2] Illustrate the signal waveforms of PAM, PWM, and PPM in simple drawings. [Q3] Suppose (t) has the spectrum in the figure below, where f = 550kHz and € = 460kHz. Sketch Xs(f) for f. = 1.6MHz if ideal sampling is considered. X(f) AÏN -f f₁ + E 0 fuarrow_forwardReport: - 1. What is the advantage of angle modulation for (noise and interference), the bandwidth of transmission and the average power of the transmission? comparison with the amplitude modulation ? Eunloin briefly when the frequency modulation can be NREM andarrow_forwardExplain what we mean when we say that two filters are cascaded.arrow_forward
- in FM , the maximum allowable frequency deviation is 4kHz and the frequency deviation by noise is 156.42HZ? then the signal to noise ratio is .......arrow_forwardCan you classify this filter, please?arrow_forwardThe following low pass giter specifrcations arereqoired for a butterworth analog fitter design. p Pussband garn, &,> -os dB, Stupband gain, Gs 5-200B, We= l000 roadls Ws = = 2000 radls Determine the order of the low pass butterworth filter O a. n= 6 O b. n= 4 O c. n=7 o d. n = 5arrow_forward
- please answer question 1.b quickly… please answer base on my matric number not as same like question.. my matric no is 201061325 so the last 3 digit is 325 so the selected low cut-off frequency is equal to the 32 khz while the high cut-off frequency is 5khz … so use the value that i give... thank youarrow_forwardQ1 A: Define the amplitude modulation (AM), state the types of AM. For the circuit-diagram given below: 1- Name the circuit-diagram. 2- Find v(t), v. (t), and vs (1). D. VUUR (Volt)! Bandpass filter #fcarrow_forwardQ)Design a Discrete Time Low Pass Filter for a signal. Butterworth Filter. Chebeyshev Filter The specifications are:(Voice Signal) 1) Passband Fp=4 kHz, with 0.2 dB ripple; Stopband FS 4.5 kHz, with 45 dB ripple. Sampling Frequency Fs = 22 kHz. (Use For Both Filters). 2) passband ripple = 0.2 stopband ripple-45 passband frequency- 1300 stopband frequency = 1500 sampling frequency = 10000. (Chebeyshev Filter) 3) Passband ripple = 0.5 stopband ripple = 50 passband frequency = 1200 stopband frequency = 2400 Sampling Frequency= 10000. (Butterworth filter)."arrow_forward
- Q2: A modulating signal is used to modulate a carrier signal(AM modulation). Let Pr, Pc, PsB, PUSB, PLSB and u are the total power, carrier power, side band power, upper side band power, lower side band power and modulation index respectively. Prove the following: a. Pc = Pr (m2) m2 b. PsB = Pr m2 PT c. PUSB = PLSB 2+m2 2+m2arrow_forwardMark the false statement. O A. Coupling capacitor doesn't work in high frequency B. Bypass capacitor acts in lowband C. L (lower end of midband) is the frequency when the gain falls off by 3 DB D. Internal capacitance affect in midbandarrow_forward3.7 A modulating signal is of the form: m(t) = 5 sin (2000nt) and the carrier signal c(t) = 10 sin (20000rt) 1. Determine the modulation index. 2. Find the percentage of modulation. 3. Find the frequencies of the sideband. 4. Find the amplitude of each the side bands. 5. What will be the bandwidth of the modulated signal?arrow_forward
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