Chapter 1, Problem 1.40QP

(a)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{242}\text{amu}$

General unit conversion

$\text{1}\text{.6605378}\text{×}{\text{10}}^{\text{-24}}\text{g}\text{=}\text{1}\text{amu}$

Conversion of atomic mass unit to gram unit

$\begin{array}{l}\text{242}\text{amu}\text{×}\left(\frac{\text{1}\text{.6605378}\text{×}{\text{10}}^{\text{-24}}\text{g}}{\text{1 amu}}\right)\\ \text{=}\text{401}\text{.85}\text{×}{\text{10}}^{\text{-24}}\text{g}\\ \text{=}\text{4}\text{.02}\text{×}{\text{10}}^{\text{-22}}\text{g}\end{array}$

(b)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{87}\text{amu}$

General unit conversions

$\text{1}\text{amu}\text{=}\text{1}\text{.6605378}\text{×}{\text{10}}^{\text{-27}}\text{kg}$

Conversion of atomic mass unit to kilogram unit

$\begin{array}{l}\text{87}\text{amu}\text{×}\frac{\text{1}\text{.6605378}\text{×}{\text{10}}^{\text{-27}}\text{kg}}{\text{1}\text{amu}}\\ \text{=}\text{144}\text{.466}\text{×}{\text{10}}^{\text{-27}}\text{kg}\\ \text{=}\text{1}\text{.4}\text{×}{\text{10}}^{\text{-25}}\text{kg}\end{array}$

(c)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{2}\text{.21}\stackrel{\text{o}}{\text{A}}$

General unit conversions

$\text{1}\text{×}{\text{10}}^{\text{-10}}\text{meter}\text{=}\text{1}\stackrel{\text{o}}{\text{A}}$

Conversion of Angstrom to meter unit

$\begin{array}{l}\text{2}\text{.21}\stackrel{\text{o}}{\text{A}}\text{×}\frac{\text{1}\text{×}{\text{10}}^{\text{-10}}\text{meter}}{\text{1}\stackrel{\text{o}}{\text{A}}}\\ \text{=}\text{2}\text{.21}\text{×}{\text{10}}^{\text{-10}}\text{m}\end{array}$

(d)

Interpretation Introduction

Interpretation:

Given set of unit conversions have to be given.

Given data:

$\text{1}\text{.73}\stackrel{\text{o}}{\text{A}}$

General unit conversions

$\begin{array}{l}\text{1}\text{×}{\text{10}}^{\text{-10}}\text{meter}\text{=}\text{1}\stackrel{\text{o}}{\text{A}}\\ \text{1}\text{×}{\text{10}}^{\text{-9}}\text{meter}\text{=}\text{1}\text{nanometer}\end{array}$

Conversion of Angstrom to nanometre unit

$\begin{array}{l}\text{1}\text{.73}\stackrel{\text{o}}{\text{A}}\text{×}\frac{\text{1}\text{×}{\text{10}}^{\text{-10}}\text{ m}}{\text{1}\stackrel{\text{o}}{\text{A}}}\text{×}\frac{\text{1}\text{nm}}{\text{1}\text{×}{\text{10}}^{\text{-9}}\text{ m}}\\ \text{=}\text{0}\text{.173}\text{nm}\end{array}$