Concept explainers
(a)
Interpretation:
The answers for the given set of calculations have to be given in scientific notations.
Concept introduction:
Scientific notation: The expression of very big or very small numbers into a comfortable decimal form.
To give: the scientific notation for the given calculation
(b)
Interpretation:
The answers for the given set of calculations have to be given in scientific notations.
Concept introduction:
Scientific notation: The expression of very big or very small numbers into a comfortable decimal form.
To give: the scientific notation for the given calculation
(c)
Interpretation:
The answers for the given set of calculations have to be given in scientific notations.
Concept introduction:
Scientific notation: The expression of very big or very small numbers into a comfortable decimal form.
To give: the scientific notation for the given calculation
(d)
Interpretation:
The answers for the given set of calculations have to be given in scientific notations.
Concept introduction:
Scientific notation: The expression of very big or very small numbers into a comfortable decimal form.
To give: the scientific notation for the given calculation
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Check out a sample textbook solutionChapter 1 Solutions
Chemistry: Atoms First
- Perform the following arithmetic operations, and report the result to the proper number of significantfigures: (a) 1.0267 cm × 2.508 cm × 12.599 cm, (b) 15.0 kg ÷ 0.036 m3 , (c) 1.113 × 1010 kg − 1.050 × 109 kg, (d) 25.75 mL + 15.00 mL, (e) 46 cm3 + 180.5 cm3arrow_forwardFor each of the following numbers, determine the number ofsignificant figures it contains, rewrite it without using scientific notation, and determine thenumber of significant figures in the result. (a) 3.050 × 10–4 , (b) 4.3200 × 102 , (c) 8.001 × 10–7, (d) 2.006080 × 105 , (e) 1.503 × 10–5 , (f) 6.07510 × 104arrow_forwardPerform the following calculations and report each answer with the correct number of significant figures.(a) 62.8 × 34(b) 0.147 + 0.0066 + 0.012(c) 38 × 95 × 1.792(d) 15 – 0.15 – 0.6155(e) 8.78 × ((0.0500)/(0.478))(f) 140 + 7.68 + 0.014(g) 28.7 – 0.0483(h) ((88.5 − 87.57)/(45.13))arrow_forward
- Give the name and symbol of the prefixes used with SI units to indicate multiplication by the following exact quantities.(a) 103(b) 10−2(c) 0.1(d) 10−3(e) 1,000,000(f) 0.000001arrow_forwardPerform the following arithmetic operations and report the result to the proper number of significant figures: (a) 317.5 mL + 0.675 mL,(b) 47.80 L − 2.075 L, (c) 13.5 g ÷ 45.18 L, (d) 6.25 cm × 1.175 cm, (e) 5.46 × 102 g + 4.991 × 103g.arrow_forwardLight travels in a vacuum at a speed of 3.00 × 108 m s-1 .(a) Convert this speed to miles per second.(b) Express this speed in furlongs per fortnight, a littleused unit of speed. (A furlong, a distance used in horse racing, is 660 ft; a fortnight is exactly 2 weeks.)arrow_forward
- Carry out the following conversions: (a) 1.42 lightyears to miles (a light-year is an astronomical measure of distance—the distance traveled by light in a year, or 365 days; the speed of light is 3.00x10^8 m/s), (b) 32.4 yd to centimeters, (c) 3.0 3x10^10 cm/s to ft/s.arrow_forwardReport all numerical answers to the correct number of significant figures! (a) Give the names of the following elements: (i) Ag (ii) V (b) Give the symbols of the following elements: (i) aluminum (ii) copper 1. 2. Report the answers of these calculations to the correct number of significant figures: (a) 3.7793 x 8.324 x 7.4976 = ? (b) 10.4071 +66.1441 +12.515 = ? (c) (7.971 x 10¹7) (3.75 x 10³)/7.8416 = ? (Report answer in exponential notation.)arrow_forward(a) A cube of osmium metal 1.500 cm on a side has a mass of76.31 g at 25 °C. What is its density in g/cm3 at this temperature?(b) The density of titanium metal is 4.51g/cm3 at 25 °C.What mass of titanium displaces 125.0 mL of water at 25 °C? (c) The density of benzene at 15 °C is 0.8787 g/mL. Calculatethe mass of 0.1500 L of benzene at this temperature.arrow_forward
- How many significant figures are there in each of the following?(a) 81.0 ± 0.8 (b) 3.827 ✕ 109 (c) 2.94 ✕ 10−6 (d) 0.0015arrow_forwardThe volume of a certain bacterial cell is 2.56 mm3. (a) What is its volume in cubic millimeters (mm3)? (b) What is the volume of 105 cells in liters (L)?arrow_forwardExpress the results of the following additions and subtractions to the proper number of significant figures. All of thenumbers are measured quantities.(a) 245.876+ 4.65+ 0.3678 =(b) 798.36 - 1005.7 + 129.652 =(c) 7.98 × 1017 + 6.472 × 1019 =(d) (4.32 × 10-15) - (6.257 × 10-14) - (2.136 × 10-13) =arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning