You have set up a fly cross between red-eyed male flies and white-eyed female flies. Several days later, you look at the F1 progeny to examine the eye phenotypes. You notice that all of the F1 males have white eyes and all of the F1 females have red eyes. These observations tell you that the gene for red eye color is most likely:
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You have set up a fly cross between red-eyed male flies and white-eyed female flies. Several days later, you look at the F1 progeny to examine the eye
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- Two pure-breeding strains of flies are mated, and the F1 are intercrossed. The first strain has curled wings and black bodies. The second strain has straight wings and brown bodies. The F2 progeny are 271 straight wings with brown bodies, 31 curled wings with black bodies, 94 curled wings with brown bodies and 90 straight wings with black bodies. If instead of the above, assume the wing shape gene and the body color gene are completely linked. From parents that are curled winged with brown bodies mated to straight winged with black bodies, what would be the outcome of an F1 intercross? (Specify the phenotypes and the frequency of each expected).In pea plants, yellow seeds (Y) are dominant to green seeds (y) and round seeds (R) are dominant to wrinkled seeds (). The genes for seed color and seed shape are on different chromosomes. Two true-breeding parents, one with yellow round peas and the other with green wrinkled peas, are crossed to produce a hybrid (heterozygous) F₁. Two F₁ individuals are crossed to give an F2; this is depicted in the Punnett square below. Place the correct genotypes in the Punnett square and the place the correct phenotypic ratios next to their appropriate phenotype on the right. YYRR YYRr YyRR YYrr yyRR yyRr Yyrr YyRr 3/16 1/16 yyrr 9/16 3/16 1/4 E 1/2 16/16 YR ✪✪✪ Yr yR YYRR Y YyRr Yr yR YR YYRr YYRR YyRr yr YyRr yyrr yr YyRr Yyrr yyRr F2 phenotype Phenotypic ratio AYou are studying the inheritance pattern of hair color in troll dolls, which have XY sex determination. You cross a true-breeding blue-haired male with a true-breeding orange-haired female. The F1 offspring (males and females) are all orange-haired. You cross an F1 orange-haired female to an F1 orange-haired male. What phenotypic ratio would you expect if the troll doll hair gene is X-linked? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "O" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2). orange-haired females : blue-haired females : orange-haired male : blue haired males What phenotypic ratio would you expect if the troll doll hair gene is autosomal? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2).…
- You are studying the inheritance pattern of hair color in troll dolls, which have XY sex determination. You cross a true-breeding blue-haired male with a true-breeding orange- haired female. The F1 offspring (males and females) are all orange-haired. You cross an F1 orange-haired female to an F1 orange-haired male. What phenotypic ratio would you expect if the troll doll hair gene is X-linked? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use,2:1 rather than 4:2). 1:1 € 1:1 1:1 orange-haired females : 1:1 orange-haired male : What phenotypic ratio would you expect if the troll doll hair gene is autosomal? Fill in each blank with a numeral (ie, 0, 1, 2, 3, 4, etc). Do not include extra spaces or decimals. Use "0" if a phenotypic group would not be present. Make sure your ratio is reduced (ie, use 2:1 rather than 4:2). 1:1 blue-haired females :…A mutant sex-linked trait called “notched” (N) is deadly in Drosophila when homozygous in females. Males who have a single N allele will also die. The heterozygous condition (Nn) causes small notches on the wing. The normal condition in both male and females is represented by the allele n. a) Indicate the phenotypes of the F1 generation from the following cross: XNXn x XnY b) Explain why dead females are never found in the F1 generation no matter which parents are crossed. c) Explain why the mating of female XNXn and a male XNy is unlikely.In the following cross, imagine that you have a female fly that has two Xs and one Y due to a nondisjunction event in her mother's germ cells. Draw out what the possible gametes are for both the female and the male and also a Punnett square showing the genotypes, phenotypes, and sex of the possible flies as a result of this cross. You do not need to provide the probabilities of each of these. Red-eyed wi C Ở Red-eyed wt XX Y X Y Meiosis
- In silkmoths (Bombyx mori), red eyes (re) and white-banded wings (wb) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (re+ and wb+); these two genes are on the same chromosome. A moth homozygous for red eyes and white-banded wings is crossed with a moth homozygous for the wild-type traits. The F1 have wild-type eyes and wild-type wings. The F1 are crossed with moths that have red eyes and white-banded wings in a testcross. The progeny of this testcross are wild-type eyes, wild-type wings red eyes, wild-type wings wild-type eyes, white-banded wings red eyes, white-banded wings a. What phenotypic proportions would be expected if the genes for red eyes and for white-banded wings were located on different chromosomes? b. What is the rate of recombination between the gene for red eyes and the gene for white-banded wings?Two pure-breeding strains of flies are mated, and the F1 are intercrossed. The first strain has curled wings and black bodies. The second strain has straight wings and brown bodies. The F2 progeny are 271 straight wings with brown bodies, 31 curled wings with black bodies, 94 curled wings with brown bodies and 90 straight wings with black bodies. If the F1 were backcrossed to the straight, wing brown bodied parent, what phenotypes would be produced among the progeny? What would be the proportion of each phenotype?A squash comes in one of three shapes (long, oval, or round) and one of three colors (green, yellow, or white). A cross between long green female squash and round white male squash produced all oval and yellow. What is the the genotype of the parents and F1 progenies? if the F1 progenies were crossed, what is the probability that an F2 offspring will have the same phenotype as the female parent?
- You have set up a fly cross between red-eyed male flies and white-eyed female flies. Several days later, you look at the F1 progeny to examine the eye phenotypes. You notice that all of the F1 males have white eyes and all of the F1 females have red eyes. These observations tell you that the gene for red eye color is most likely: Group of answer choices not involved in the observed phenotypes sex-linked autosomal located on chromosome IIIIn Drosophila, the vermilion eye color is determined by a recessive allele, v, of an X-linked gene. The wildtype color is determined by the v+ allele and causes a brick red eye color. In a cross of a heterozygous female with a wild type male you observe 340 red eye females, 136 red eye males, and 90 vermillion males. Do these results follow your expectations?In Drosophila, white eyes (w) are recessive to red eyes (w+) at one locus and black body (b) is recessive to gray body (b+). A homozygous white eyes, gray bodied female is crossed with a homozygous red eyes, black bodied male to produce the F1 progeny. The F1 progeny are testcrossed and produce the following progeny: White eyes, black body: 212 White eyes, gray body: 288 Red eyes, black body: 308 Red eyes, gray body: 192 Does the evidence indicate that w and b loci are linked? Explain why or why not? If they are linked, what is the map distance between the two loci? If they are not linked, what is the map distance between the two loci? If they are linked, are the allels in the F1 in coupling or repulsion? How do you know? Draw the genotypes of all individuals described in the problem (original parents, F1, testcross, and F2 progeny) using the appropriate notation.