which one of the following processes causes a dramatic increase in the hardness of a steel part? A quenching B) tempering normalizing D full annealing
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- A batch of casted mild steel has a modulus of elasticity of 200 GPa and a yield strength of 250 MPa. Calculate for its modulus of resilience. After cold working the steel, the yield strength increases to 310 MPa. Calculate for the percent reduction in the average grain diameter given σo = 70 MPa and k = 0.74.i need quickly please please please Which of these cast iron would allow the greatest amount of plastic deformation before fracture . Nodular cast iron Grey cast iron White cast iron None of them can be worked. If the diameter of steel specimen stretched by tension load is doubled , then it’s tensile strength will be Halved Remain unaffected Doubled Become four times Temperature is proportional with Percent of elongation Tensile strength Modulus of elasticity All above The tensile strength of a steel specimen that have a 182 HB , equals to 490 MPa 910 MPa 627 MPa Not given…. Properties of steel can be altered by applying a variety of heat treatments. Pleaseexplain full annealing for steel.
- The most common method for production of steel is Group of answer choices Slip casting Continuous casting Hot pressing Investment castingGiven your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder C. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failured) No increase Which of the following is not a property of steel materials? C a) Homogeneous and isotropic b) Linearly elastic stress-strain behavior c) Recyclable d) Fire-resistant
- A specimen of alloy having the following engineering stresses produces the corresponding plastic engineering strains, prior to necking: Engineering Stress (MPa) Engineering Strain 353.7 0.0357 371.3 0.0436Which mechanism(s) cause(s) an increase in the strength of medium-carbon steels? A) decreasing the grain size B) strain hardening (c) heat treatment to provide martensitic microstructure D) AllThe yield strength for an alloy that has an average grain diameter of 4.4 x 10-2 mm is 133 MPa. At a grain diameter of 8.3 x 10-3 mm, the yield strength increases to 243 MPa. At what grain diameter, in mm, will the yield strength be 226 MPa? d = i mm
- Compare the difference in hardenability of plain carbon steels given below. Hardenability is the strengthening of steels by the process of quenching + tempering. Chemical compositions ( wt % ) C Mn P S Fe Steel 1 0.2 0.45 0.04 0.05 99.26 Steel 2 0.4 0.75 0.04 0.05 98.76 Steel 3 0.6 0.75 0.04 0.05 98.56Task (3) you are asked to perform tensile test on specimens of two different materials (A and B) and you obtained the stress-strain diagram of the two specimens as shown in Figure 2: 400 350 300 250 Material A 200 150 100 50 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 Strain (mm/mm) 50 Material B 30 20 10 0.02 0.04 0.06 0.08 0.1 Strain (mm/mm) Figure 2: Tensile Test Analysis Stress (MPa) Stress (MPa)Is a steel a heterogeneous or homogeneous mixture?