Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- please help with chartarrow_forwardYou are working with a new species of spider in the lab. Wild type spiders have black legs and long mandibles. Mutants have black/brown striped legs and short mandibles. You perform a cross between wild type and mutant spiders. Your results : 5,502 wild type; 5,877 mutant; 69 black/brown striped, long mandibles; 52 black, short mandibles. What information does the recombination frequency tell you about the traits? (You will need to solve the RF first if you haven't done so in the other problem.) * A. Crossing over occurs frequently between the two traits. B. They are unlinked genes. C. They are located on separate chromosomes D. They are located very close together on the same chromosome.arrow_forwardAnswer was wrongarrow_forward
- Answer the questions as if you were crossing flies with a “big head” mutant trait with flies that have normal sized heads.arrow_forwardIf two genes are completely linked, the value of r = : 1.00 0.75 0.25 0.50arrow_forwardTest Cross Progeny 680 ABC 620 A* B*C* 301 A*B C+ 369 A B* C 105 AB C+ 127 A* B* C 4 A*BC A B* C+ Total Progeny = 2217 %3D B 6.5 mu 10.4 mu 16.9 mu Based on the above data calculate the expected number of Double crossovers (DCOS). Round to the nearest whole number. Do not attempt to determine the map distances!arrow_forward
- please make sure to read the question (THERE ARE OTHER VARIATIONS OF THE QUESTION ON DIFFERNT WEBSITES THAT ARE DIFFERENT THAN MINE)arrow_forwardPunnett Square for a Dihybrid Cross to Investigate Coat Colour in Mice be Вс BbCc Answer: D Ova BBCC BbCc bc) bb Cc (BC) BbCC D BbCc Bbcc X BBCC bbcc BBcc bbcc Bb Cc BC O Sperm BbCC Bb Cc Bbcc bc BBCC bbcc Вс BbCc Legend Black Brown White Coat colour in mice is controlled by the interaction of two genes. Three phenotypes result: black coat, brown coat, and white coat. The expected phenotypic ratio resulting from a cross between a bbCc female mouse and BbCc male mouse, is black: brown : white Enter only the number values in the order black brown white (Do not include spaces, commas, etc.)arrow_forward#5 pleasearrow_forward
- Consider the following Test Cross results & chromosome map: Test Cross Progeny 525 A B C 500 A+ B+C+ 456 A+ B C 308 A B+C+ 101 A B C+ 100 A+ B+C 2 A+ B C+ 1 A B+C Total Progeny = 1993 1-Calculate the interference.?arrow_forwardThe e-gram (graph to the right of allelic ladder image) and above is from a woman. She has variations 14 and 15 at STR D3S1358. If she has children with a man who has variations 12 and 19 at the same STR, what are the possible combinations of variations that their children would have?arrow_forwardBased upon the attached image and your answer above, what is the genotype of the unknown individual? Please explain your answer. (The attached image is the results of the test cross from the question above).arrow_forward
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