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- A cross is made between a heterozygote, +++/abc, and a recessive homozygote, abc/abc. Analysis of the progeny gave the following results: + + + 450 + + C 10 a + c 70 + b c 210 + b + 65 a + + 200 a bc 460 ab + 15 What is the map distance between the a and c genes? O 25.12 map units O 27.71 map units O 29.39 map units O 32.53 map units O None of the above Next» • Previous PgUp End F10 PrtScn Home 23 F2 DII F3 F4 F5 FB F9 F1 @ %23 %24 1. 3. 4. 8. To W R. Y U S D G H. C M B+ ec +/Y + + w/Y y ec +/Y + ec +/y ec w ++ w/y ec w у ес +у ес и Determine the order in which the three loci y, ec, and w Occur on the chromosome and prepare a linkage map. 7.22 A cross involving X-linked genes was made between yellow, bar, vermilion female fies and wild males, and the F1 females were crossed with y B v males. The following phenotypes were obtained when 1000 progeny were exam- ined: Dra ord ma the 7.2 546 244 160 50 + + + + Bv y Bv y+ + y+v y B+ and an and and and +B + re + + v ge Determine the order in which the three loci occur on the chromosome and prepare a linkage map. 7.23 Female Drosophila heterozygous for ebony (e"le), scarlet (st*/st), and spineless (ss*/ss) were testcrossed, and the following progeny were obtained: PROGENCY PHENOTYPES NUMBER ir Wild type Ebony Ebony, scarlet Ebony, spineless Ebony, scarlet, spineless Scarlet 67 8. 68 347 78 368 Scarlet, spineless Spineless (a) Are these genes linked? Justify your answer. (b) Write the genes given on a…In fruit flies, you are mapping three genes in a three point cross. The mutants are hairy body (h), sepia colored eyes (se) and female sterility (g). You cross a heterozygous parent with a homozygous recessive parent and obtain the following results: Type Number h se g. 5 + se + 450 + se g 27 ++g_ h se + + + + h + g. h + + TOTAL is the gene in the middle and the distance in map units between se and g is Oh; 16.4 se; 7.1 Oh; 7.1 70 82 7 327 32 1000 se; 16.4
- The result of a test cross of a yeast cell that is heterozygous for three genes are summarized in the table (below), which shows the number of offspring that inherited each combination of alleles from the heterozygous parent. Use the data collected to make a genetic map of the three genes L, Q, and D. • D-Q: o D-L: | o Q-L: | - L L I L L cM CM Alleles CM Ơ Ơ o Q o d D D d d d # 104 27 78 Report your results by entering the genetic distance between each pair of genes in the blanks below. Round to the nearest 0.1 cm. 64 28 62 106 81SET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg b + lg b v lg + + lg 305 148 58 bv + + + + 62 + v + b + + 152 275 1000 Total Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.In a diploid plant species, an F1 with the genotype Gg Ll Tt is test-crossed to a pure-breeding recessive plant with the genotype gg ll tt. The offspring genotypes are listed in the table. Genotype Number Gg Ll Tt 621 Gg Ll tt 3 Gg ll Tt 64 Gg ll tt 109 gg Ll Tt 103 gg Ll tt 67 gg ll Tt 7 gg ll tt 626 1600 Calculate the recombination frequency between G and T pair of genes. A. 0.227 B. 0.139 C. 0.454 D. 0.233
- SET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg 305 b + lg b v lg + + lg b v + 148 58 + + + 62 + y + 152 b + + 275 Total 1000 Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.Use the image to observe the results of a cross between a tall pea plant and a short pea plant. What phenotypes and proportions will be produced for the two crosses? P generation Tall Tt Gametes Tt F₁ generation T Fertilization Tt t Tall tt Short Tt Tall tt tt Short Conclusion (a) Short (b) Genotypic ratio 1Tt:1tt Phenotypic ratio 1 tall: 1 short Tall F₁ progeny backcrossed to the short parent Answer Bank one-fourth tall and three-fourths short one-half tall and one-half short three-fourths tall and one-fourth short Tall F₁ progeny backcrossed to the tall parent all tall all shorUsing the conventions of Figure 4-15, draw parents andprogeny classes from a crossP M′′′/p M′ × p M′/p M′′′′
- SET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b > plant color booster vs. non-booster +lg → with ligule vs. without ligule +/v > green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg b + lg b v lg 305 148 58 + + lg b v + + + + 62 + v + 152 b + + 275 Total 1000 Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.n corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines sing the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspringCIUSS O An organism has the genotype a g*/a"g*; qf"/q+f*;r+h+/rth*. Indicate the correct genes/ alleles at all the positions numbered 1-12 in the image below such that the diagram accurately represents the genotype of this organism. Note: assume the first chromosome in each pair shown in the genotype is the top chromosome shown in the diagram. 1 i 2: a gene g gene 6. q gene fgene 7 8. | 10 r gene h gene 12 Only place the genes/ alleles you need. You will not need them all. You may need to use some more than once. • gene / allele 1 a- ; gene / allele 2 g+ ; gene / allele 3 a- gene/allele 4 g++ • gene / allele 5 q- ; gene / allele 6 f- gene / allele 7 q+; gene / allele 8 f- gene / allele 9 r+; gene / allele 10 h+ gene / allele 11 r+ gene / allele 12 h+ a+ a- f+ f- g+ g- h+ h- q+ q- r+ r- 2.