Assume that the mother's genotype is AZ/az, and the father's genotype is Az/aZ, and the recombination rate is 10%. What are the probabilities of an 'az' gamete from each parent? Group of answer choices .45 from mom, .05 from dad .4 from mom, .1 from dad .5 from mom, 0 from dad .1 from mom, .05 from dad

Calculate the probability of two heterozygous (all 4 gene loci) parents producing a child with the minimum number of active alleles.  Type the answer as a fraction (x/y).

Given the allelic frequency of A = .5 , answer the following 1. What is the homozygous dominant frequency ? 2. What is the allellc of a? 3. What is the heterozygous frequency ?

PART 2: Breeding Value, Gene Combination Value, Expected Progeny Difference For this part, you will calculate the gene combination and breeding values for Dr. Coleman's elite racing stallion, Usain Colt. Instructions: Use the online random coin flipper to generate allelic values at each locus. Use those values to calculate the GCV and EBV (BV, but since it's just an estimated value...and geneticists love acronyms and initialisms, so... EBV) for Usain Colt. For every coin that lands on heads, you will put -6 seconds for the corresponding allele at that locus and +6 seconds for every coin that lands on tails. (this is the amount of time added or subtracted from the population average) Heads: -6 seconds Tails: +6 seconds (Hint: You can flip multiple coins simultaneously using the random coin flipper.) Example: I flipped 12 coins (2 alleles for 6 loci) with the following outcome: Heads, Heads, Heads, Tails, Heads, Tails, Tails, Tails, Tails, Tails, Heads, Tails. Therefore, I would go from…

Assume that the length of a type of cucumber at maturity is controlled by two genes (A and B), each of which has two alleles. The A and B alleles each add 3 inches of cucumber growth, while the a and b alleles add only 1 inches. If a plant with genotype Aabb is crossed to a plant with genotype AaBb, what ratios of lengths are expected in the progeny?     1/8-12”, 3/8-10”, 3/8-8”, 1/8-6”     1/2-8”, 3/8-6”, 1/8 4”     1/8-10”, 3/8-8”, 3/8-6”, 1/8-4”     1/2-12”, 3/8-10”, 1/8 8”     1/2-10”, 3/8-8”, 1/8 6”

What phenotypic ratios would result from crossing the F, from Part A with the F, from Part B? pink, personate (RrPp) x pink, personate (RrPp) Drag the correct labels onto the table. Labels can be used once, more than once, or not at all. Reset Help F2 Phenotype Ratio red, personate 2/16 3/16 red, peloric 6/16 pink, personate 9/16 1/4 pink, peloric 1/2 white, personate 3/4 white, peloric Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining You labeled 6 of 6 targets incorrectly. Drovide Feedheck

In a true breeding parental cross for an Autosomal recessive disease trait, the expected proportion of males in the F2 generation that are unaffected is:

A heterozygous purple bird was crossed with a blue-feathered bird. One white-feathered offspring resulted from the cross. What is the genotype of the blue-feathered bird? (3 marks - 2 marks for the correct genotype with an explanation as to how you determined your answer, 1 mark for the Punnett square)

Genotype HA На hA ha НА НН АА НН Аа Hh AA Hh Aa На НН Аa НН аa Hh Aa Hh aa hA Hh AA Hh Aa hh AA hh Aa ha Hh Aa Hh aa hh Aa hh aa Кey: H = long hair h = short hair A = brown a = green What is the probability that among the first two offspring, one will be short-haired and green- eyed, and the other will be short-haired and brown-eyed? 3/256 3/128 O 1/16 О 3/16

What is the coefficient of coincidence and the interference? Answer in 2 decimals