n an F1 cross, Y/y x Y/y, 3/4 of the plants are yellow and 1/4 of the plants are green. Determine the genoty corresponding ratios of the plants. O 1:4 Yy; 3:4 yy O 1:2 YY; 1:4 Yy; 1:4 yy O 1:4 YY; 3:4 yy O 1:4 YY; 1:2 Yy; 1:4 yy
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- Individuals of genotype AaBb were mated to individuals of genotype aabb. One thousand offspring were counted, with the following results: 474 Aabb, 480 aaBb, 20 AaBb, and 26 aabb. What type of cross is it? Are these loci linked? What are the two parental classes and the two recombinant classes of offspring? What is the percentage of recombination between these two loci? How many map units apart are they?In pineapples, leaves may be spiny, spiny-tipped or piping. Pineapples of different phenotypes were used in the following crosses: Pl phenotype piping X spiny P1 genotype Fl phenotype 100% piping F1 genotype Crossing the Fls produced: F2 phenotypes F2 genotypes ww gm 95 piping 25 spiny tipped 8 spiny Using the letters A and B, give the COMPLETE genotypes of ALL the individuals. SOLUTION Get the total of the F2 generationGiven the following information, determine the inheritance of flower color in this plant and determine the genotypes of the parental individuals, which are from pure- breeding lines. CROSS 1 CROSS 2 purple X colorless all purple 9/16 purple colorless X red all purple as in Cross 1 F1 F1 F2 F2 3/16 red 4/16 colorless
- In the following dihybrid cross: B/b; E/e x B/b; e/e What are the phenotypes of the offspring? 9/16 Black 3/16 brown 4/16 golden 9/16 Brown 3/16 Black 4/16 golden 9/16 Black 3/16 golden 4/16 brown 3/8 Black 1/8 brown 4/8 golden 3/8 golden 4/8 Black 1/8 brownIn some plants a red pigment is synthesized from a colorless precursor. The addition of a hydroxyl group to the precursor molecule causes it to become purple. In a cross between two randomly selected purple plants, the following results were obtained. 94 purple 31 red 43 white Q:What are the genotypes of the two random purple plants? R/r; P/p X R/r; P/p R/r; p/p X R/r; p/p r/r; P/p X r/r; P/p r/r; p/p X r/r; p/p R/R; P/P X r/r; p/pCalculate the probability of either all-dominant or all-recessive genotypes for the alleles A, B, E, and F in the following cross: A/a;B/b;c/c;d/d;E/e;F/fx A/a;B/b;C/c;d/d;E/e;F/f 1/64 1/128 1/256 1/32 1/16
- In a diploid plant species, an F1 with the genotype Gg Ll Tt is test-crossed to a pure-breeding recessive plant with the genotype gg ll tt. The offspring genotypes are listed in the table. Genotype Number Gg Ll Tt 621 Gg Ll tt 3 Gg ll Tt 64 Gg ll tt 109 gg Ll Tt 103 gg Ll tt 67 gg ll Tt 7 gg ll tt 626 1600 Calculate the recombination frequency between G and T pair of genes. A. 0.227 B. 0.139 C. 0.454 D. 0.233type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSWhat are the phenotypes? What is the ratio of those phenotypes? The phenotypes would be: (a) Yellow with smooth (b) Yellow with wrinkled 3:1 Part 2: Data Tables Table 1: Parent Genotypes: Monohybrid Crosses Generation Genotype of Individual #1 Genotype of Individual #2 P Yy Ss P1 Yy Ss P2 Yy ss P3 Yy SS P4 YY SS Table 2: Generation Data Produced by Monohybrid Crosses Generation Possible Offspring Genotypes Possible Offspring Phenotypes Genotype Ratio Phenotype Ratio P yySs P1 yySs P2 Yyss P3 YySS P4 YYSS Part 2: Post-Lab Questions How much genotypic variation do you find in the randomly picked parents of your crosses? How much in the offspring? Pool all of the offspring from your five replicates. How much phenotypic variation do you find? Is the ratio of observed…
- In onion, male sterility is produced when the nuclear genotype is aa and the mitochondrial gene S (sterile) are present. Any other combination of nuclear genotype and mitochondrial gene (including gene F for fertile) will result in a male fertile plant. Give the genotypic ratio and the phenotypic ratio or the percentage of male sterile and male fertile offspring that will be produced in the following crosses. 1. Aa + S male x aa + F female 2. Reciprocal cross of number 1. (Note that when we do reciprocal cross, we interchange/swap the genotypes of the parents (if there is a nuclear gene involved, you interchange the nuclear genotype as well). 3. Aa + S female x Aa + F male 4. Reciprocal cross of number 3.к, х Ааv AdBbCc AaBbCc No Spacing AaBbCc 三、相、 1 Normal Heading 1 Font Paragraph 6. Let's assume that the non-taster, daughter in question 5 is a carrier of the albino trait. She marries a Styles taster man, normally pigmented, whose mother was a non-taster albino. Show the cross between these parents. Genotype of the woman Genotype of the man Genotypes Phenotypes What is the chance that their child will be a taster? Footer What is the chance that their child will be albino? What is the chance that their child will be a taster albino? J.S.)The trihybrid e+f+g+/efg is test crossed to the triple recessive efg/efg and the following genotypes were obtained in the progeny: efg = 2; efg = 28; e'fg* = 9; e*rg 32; efg 73; e*fg* = 10; ef g* =10; e'fg 2; %3D "The odd gene is The gene order is The gene distance between e-f is The gene distance between f-g is The gene distance between e-g is