Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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Through PCR, we have determined the PER3 genotypes for a class of students as follows:
H4/H4 = 125 individuals; H4/H5 = 90 individuals and H5/H5=85 individuals.
Using the allele frequencies experimentally derived, calculate the frequency of the H4/H5 genotype that would be expected if the class were a population in Hardy-Weinberg equilibrium.
1- 0.43
2- 0.24
3- 0.49
4- 0.30
5- 0.57
6- 0.14
7- 0.19
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- A total of 6500 North American Caucasians were blood typed for the MN locus, which is determined by two codominant alleles LM and LN. The following data were obtained: Blood Type M MN N a. 0.52, b. 0.23 a. 0.52, b. 0.12 0.48, 0.12 Number a. What is the allele frequency of LM in the population (LM=p) b. What is the genotypic frequency of LNLN? a. 0.48, b. 0.23 1800 3200 1500arrow_forwardPretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…arrow_forwardConsider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33arrow_forward
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