Using the product rule, what is the total frequency of the profile, given the following genotype frequencies for each of the loci: D3S1358 = 0.04453 vWA = 0.02725 D5S818 = 0.07534 0.008406 0.0000914 0.14712 10,491 0.914208
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Using the product rule, what is the total frequency of the profile, given the following genotype frequencies for each of the loci:
D3S1358 = 0.04453
vWA = 0.02725
D5S818 = 0.07534
0.008406 |
||
0.0000914 |
||
0.14712 |
||
10,491 |
||
0.914208 |
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- A worldwide survey of genetic variation in human populations reported the autosomal codominant MN blood group types in a sample of 1029 Chinese individuals from Hong Kong. The sample contained 342 people with blood type M, 500 with blood type MN, and 187 with blood type N. Part A The number of people expected in each blood-type category is: Enter the values expected for MM, MN and NN blood-type categories, respectively, separated by commas and using two decimal places (example 1.02, 2.30, 3.45).stion 6 of 18 Suppose that a geneticist discovers a new mutation in Drosophila melanogaster that causes the flies to shake and quiver. She calls this mutation quiver, qu, and determines that it is due to an autosomal recessive gene. She wants to determine whether the gene encoding quiver is linked to the recessive gene for vestigial wings, vg. She crosses a fly homozygous for quiver and vestigial traits with a fly homozygous for the wild-type traits, and then uses the resulting F, females in a testcross. She obtains the flies from this testcross. Phenotype Number of flies vg* qu+ 230 vg qu 224 vg qut vg* qu 97 99 Test the hypothesis that the genes quiver and vestigial assort independently by calculating the chi-squared, X², for this hypothesis. Provide the X2 to one decimal place. X2 = Does the X value support the hypothesis that the quiver and vestigial genes assort independently? Why or why not? the partial table of critical values for X2 calculations to test this hypothesis.What is the expected genotype frequency of the heterozygous genotype under the Hardy-Weinberg equation P = 0.7?
- What is the first variable that can be calculated given these data, and what is the final variable we are requesting you to calculate? "In Finland, 256 people out of 10,000 are homozygous for the CCR5 allele mutation resulting in HIV resistance. Assuming the locus is in Hardy-Weinberg equilibrium, what is the expected genotype frequency of heterozygous carriers for the CCR5 mutation?"Following the analysis of a pedigree, a genetic link at 4cM is considered between a mutation leading to a pathology and the molecular marker HUMTH01. The study counts 14 "parental" and 3 "recombinant" individuals. We call p(theta=0.04) is the probability of obtaining such a pedigree in case of a 4cM genetic linkage, p(theta=0.5) is the probability of obtaining such a pedigree in case of independence between the mutation and the marker, Z(theta=0.04) the value of the Lod-score under the assumption of 4cM genetic linkage. Tick all the correct answers: p(theta=0,04)=1,79.10E-9 and Z(theta=0,04)=0,47 p(theta=0,5)=7,18.10E-12 and Z(theta=0,04)=0,77 and Z(theta=0,04)=0,67 p(theta=0,04)=2,75.10E-10 p(theta=0,5)=6,04.10E-10 and Z(theta=0,04)=0,47 p(theta=0,5)=9,36.10E-12 and Z(theta=0,04)=1,33 p(theta =0,5)=5,82.10E-11 and Z(theta=0,04)=0,67 no correct answer p(theta=0,04)=4,31.10E-11 p(theta=0,04)=2,01.10E-10 and Z(theta=0,04)=0,77 and Z(theta=0,04)=1,33Calculate the Variance of the following data set: 10, 15, 13, 12, 14
- Use the scoring system described to calculate the alignment score for IPNI AAIG DV VAGP VKGIYA VG DV C-GK Scoring system: • Each identity results in +10 points. • Each gap has a penalty of -25 points. score = What is the percent identity (also called percent identity match)? percent identity: %For the following Chi-square table, how many degrees of freedom should be used when calculating the p-value? Gender Phenotype O E O-E (O-E)2 (O-E)2/E Male Disease 99 101.5 -2.5 6.25 0.061576 WT 105 101.5 3.5 12.25 0.12096 Female Disease 0 0 0 0 0 WT 202 203 -1 1 0.004926 Total 406 406 19.5 0.187192 You do not need to know the degrees of freedom to calculate the p-value. a. 4 b. 5 c. 2 d. 3The genotype of EB27 and EB67 are unknown. Based on pedigree, what are the most likely genotype of each individual?
- Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?The gel image above shows 7 alleles, let's call them 1-7 in order of size, with 1 being the largest and 7 being the smallest. What is the approximate size in Kbp of allele 4? Please type your answer as a number, please do not add units. ANSWER: The approximate size of allele 4 in the gel image below is Blank 1 Kbp Photograph of UV illuminated 1 % agarose TBE gel run for 40 minutes at 120 V, showing the result of PCR from a variable number tandem repeat region in 11 different individuals (A-K) 2000 1650 1000 850 600 500 Key: Lane 1: Lanes 2-12: A B C D E F G H I J K DNA ladder, see image for fragment sizes in base pairs (bp) PCR Products from the same variable number tandem repeat (VNTR) autosomal region of DNA from 11 different individuals (A-K)What would be the gene map for the following genes with known recombination frequencies? D and A is 5.1 cM, A and C is 15.8 cM, A and B is 7.8 cM, C and D is 10.7 cM, and C and B is 8.0 cM.