Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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Why is the rate of cotransformation for all three genes (M S F) almost the same as the rate of cotransformation for M F alone?
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- You have identified a SNP marker that in one largefamily shows no recombination with the locus causinga rare hereditary autosomal dominant disease.Furthermore, you discover that all afflicted individuals in the family have a G base at this SNP on theirmutant chromosomes, while all wild-type chromosomes have a T base at this SNP. You would like tothink that you have discovered the disease locus andthe causative mutation but realize you need to consider other possibilities.a. What is another possible interpretation of the results?b. How would you go about obtaining additional genetic information that could support or eliminateyour hypothesis that the base-pair difference is responsible for the disease?arrow_forwardFour E. coli strains of genotype a+ b- are labeled 1, 2, 3, and 4. Four strains of genotype a- b+ are labeled 5, 6, 7, and 8. The two genotypes are mixed in all possible combinations and (after incubation) are plated to determine the frequency of a+ b+ recombinants. The following results are obtained, where M = many recombinants, L = low numbers of recombinants, and 0 = no recombinants:On the basis of these results, assign a sex type (either Hfr, F+, or F-) to each strain.arrow_forwardDNA from a strain of Bacillus subtilis with the genotype trp" tyr* was used to transform a recipient strain with the genotype trp tyr". The following numbers of transformed cells were recovered: Number of transformed Genotype cells trp* tyr 154 trp tyr* trp" tyr* 312 354 What do these results suggest about the linkage of the trp and tyr genes?arrow_forward
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