Q89. Explain why evolution would favor the emergence of new incompatibility alleles, making the gene increasingly polymorphic in populations of tomatoes or petunias.
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Genetic Variation
Genetic variation refers to the variation in the genome sequences between individual organisms of a species. Individual differences or population differences can both be referred to as genetic variations. It is primarily caused by mutation, but other factors such as genetic drift and sexual reproduction also play a major role.
Quantitative Genetics
Quantitative genetics is the part of genetics that deals with the continuous trait, where the expression of various genes influences the phenotypes. Thus genes are expressed together to produce a trait with continuous variability. This is unlike the classical traits or qualitative traits, where each trait is controlled by the expression of a single or very few genes to produce a discontinuous variation.
Q89. Explain why evolution would favor the emergence of new incompatibility alleles, making the gene increasingly polymorphic in populations of tomatoes or petunias.
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- Q5.1. Which of the following is FALSE? If a genetic disease reduces fertility and the allele that causes the disease offers no other advantage, the allele will likely eventually disappear, due to natural selection. Natural selection does not favor individuals who are homozygous for the sickle-cell allele, because these individuals typically die before they are old enough to reproduce. Individuals who are heterozygous HbA/ HbS are protected from malaria, and this is why sickle-cell disease persists in wetter, mosquito-prone regions in Africa. OIn regions where malaria does not occur, individuals who are heterozygous HBAIHBS have a fitness advantage over those who are homozygous for the normal hemoglobin allele (HbA). Submit Q5.2. AFTER malaria is cured, the frequency of the HbS allele should decrease in regions with lots of mosquitoes because: People will no longer die from sickle-cell disease in these regions. Having one copy of the HbS allele will no longer be advantageous in these…Q5.1. Which of the following is FALSE? O If a genetic disease reduces fertility and the allele that causes the disease offers no other advantage, the allele will likely eventually disappear, due to natural selection. Natural selection does not favor individuals who are homozygous for the sickle-cell allele, because these individuals typically die before they are old enough to reproduce. Individuals who are heterozygous HbAlHbS are protected from malaria, and this is why sickle-cell disease persists in wetter, mosquito-prone regions in Africa. O In regions where malaria does not occur, individuals who are heterozygous HbAIHbS have a fitness advantage over those who are homozygous for the normal hemoglobin allele (HbA).Activity 1 Write down the correct biological term for each of the following descriptions in the space provided. DESCRIPTION TERM 1.1 A cross involving a single characteristic 1.2 A cross involving two characteristics A representation that traces the transmission of a characteristic over many generations of a family Allele that influences the phenotype only when in the homozygous combination but not in the heterozygous condition 1.3 1.4 1.5 Allele that influences the phenotype whether in the homozygous or heterozygous combination 1.6 Alternative forms of a gene found at the same locus 1.7 Characteristics controlled by alleles of a gene that are located on the sex chromosomes Cross involving alleles of a gene that are equally dominant, leading to a third phenotype which is a combination of the other two phenotypes 1.8 1.9 Cross involving alleles that are neither dominant or recessive, leading to an intermediate phenotype 1.10 Cross involving characteristics controlled by dominant and…
- l Metro by T-Mobile 1 2:29 PM • 16% I In flies, long wings are a dominant trait, and short wings are a recessive trait. Medium wings are the heterozygous trait. Based on this information, if a homozygous long-winged fly is crossed with another a heterozygous'fly, their offspring will have which percentages for long, medium, and short wings? Assume random chromosome segregation. 17) A) 25% long, 75% medium, 0% short B) 50% long, 25% medium, 25% short 50% long, 50% medium, 0% short D) 100% medium, 0% long, 0% short30: 3. The genes for the human blood types MN and Ss are closely linked genes on chromosome 4. A sample of 2000 British people returns the following numbers of each type of chromosome: MS Ms F2 a) Estimate the gametic and allele frequencies. b) Calculate D. English (United States) Accessibility: Unavailable c) Test whether the two loci are in linkage disequilibrium in this population. #3 E d) What is the amount of disequilibrium relative to its maximum (or minimum) value? D e) What are the expected frequencies of chromosomes assuming linkage equilibrium? 80 F3 $ 474 4 Q F4 R F % 5 611 S F5 T G 6 NS 142 F6 MacBook Air Y H & 7 F7 U Ns 773 * 00 8 J DII F8 ( 9 Focus E F9 K 0 F10 L E I PQ6. Guinea pigs, which were homozygous for long, black hair were crossed with ones which were homozygous for short, white hair. All the F1 offspring had short, black hair. 14)Using suitable symbols, draw a genetic diagram showing parents genotypes, to explain this result in F1 offspring. I
- 5. In a population genetic study of a species of California wild oat, the following genotype frequencies were found for a trait (hairiness of the leaf sheath) which is controlled by a single locus: HH 0.571 Hh 0.071 hh 0.358 a) What are the expected frequencies of these genotypes under Hardy-Weinberg? b) Calculate F. c) Briefly explain what the value in b) implies regarding heterozygosity and suggest what might be going on in this population to explain this result.CH 1-4 X ← → C Maya X Credibi X app.wizer.me/learn/00E0A8 wizer.TIE a Maya S x BW x BW To-do X Assign x b M Dashb X BB x BW Figura X Figurat X A chicken breeder has chickens that are white, black, or speckled. Speckled chickens have both black and white feathers. The allele for white feathers is (W). The allele for black feathers is (B). Determine the genotypes of the rooster and hen that would breed the greatest percentage of speckled chickens. BW x WW Dashboard Incomp X Interac X STILCI GIESS LUUC BB x WW + with white (W). The heterozygous phenotype is brown and white V < ☆ GOQ6. Guinea pigs, which were homozygous for long, black hair were crossed with ones which were homozygous for short, white hair. All the F1 offspring had short, black hair. (a) Using suitable symbols, draw a genetic diagram showing parents genotypes, to explain this result in F1 offspring.
- The red color of the tomato pulp depends on the presence of the R factor, dominant over its r allele for yellow. Dwarfism is due to a recessive gene d. There is a homozygous variety with yellow pulp and normal size and another dwarf variety with red pulp.• From the available varieties, could a homozygous variety with red pulp and normal size be obtained?• And a variety of yellow pulp and dwarf size?Give reasons for the answer.Q10. 1) What is meant by epistasis? The natural colouration of wild mice is called agouti and is produced from banded genes are involved, each with a dominant (A and B) and a recessive allele (a and b). The allele A codes for the ability to produce hair pigment: AA and Aa mice have pigmented hairs but all aa individuals are albinos. The Ballele codes for the ability to make hair with grduated colouration: BB and Bb mice have graduated hair, bb mice have hair that is all one colour which is black. hairs. Two MacBook ProQ10. 1) What is meant by epistasis? The natural colouration of wild mice is called agouti and is produced from banded genes are involved, each with a dominant (A and B) and a recessive allele (a and b). The allele A codes for the ability to produce hair pigment: AA and Aa mice have pigmented hairs but all aa individuals are albinos. The B allele codes for the ability to make hair with grduated colouration: BB and Bb mice have graduated hair, bb mice have hair that is all one colour which is black. hairs. Two