You have a 5'(A/T)–3' SNV potential. Draw out to explain why using the sense strand and template strand would both yield the same color if you were heterozygous at this SNV location. (The color is red, by the way.) How do vou distinguish between sex-linked and limited expression in male traits in pedigrees?
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- In a 4th year honours project, Amy described short nucleotide polymorphism (SNP) on chromosome #1 of drosophila. Among this polymorphism for the DM3 locus, Amy described 2 alleles (DM1" and DM1°): 5'.TCTTGATC. 3' DM1T 3'.AGAACTAG. 5' or 5'.TCTCGATC.3' 3'.AGAGCTAG. 5' DM1C Amy then wanted to test if the DM1 SNP was linked to the gene for purple eyes. To do so, she first generated heterozygous flies by crossing true breeding red eyed flies with the DM1" marker with true- breeding purple eyed drosophila with the DM1C marker: pr+ PM1 heterozygote! pr DMIT She then did a testcross to perform a linkage analysis between the DM3 marker and the gene for purple eyes: pr+ DM1C pr PMIT pr DMIC pr DMIC X A) Complete the following table by indicating the types of gametes the heterozygous fly can produce (column 1); whether or not the gamete is of the parental type (P) or a recombinant (R) (column 2); and the genotype of the F2 progeny (column 3). Parental (P) Genotype of gamete of the F1 fly…O Macmillan Learning Assume that the length of wheat leaves is controlled by three loci, each with two alleles: L and I, W and w, H and h. Determine the differences in leaf length between two homozygous strains of wheat. Assume each allele contributes equally to the length of the plant leaves. One homozygous strain, Il ww hh, has leaves that are 100 mm in length, and the other strain, LL WW HH, has 220 mm leaves. The two homozygous strains are crossed, and the resulting F₁ are selfed to produce F₂ progeny. What length will the leaves of the Ll Ww Hh genotype plant be? leaf length: What proportion of the F2 progeny will have the same phenotype as the LI Ww Hh genotype? Input answer as a decimal. proportion: mmFrom DNA to Protein and Inheritance Co-Dominance: In co-dominance, the heterozygous individual exhibits the phenotype for both alleles. We used the ABO blood groups as an example of co-dominance. 8. What potential blood types can be present in the offspring if two type "O" mate with one another? (alams 1) Ilgq xal Ligg 9. What are the potential blood types present in the offspring if two parents with type A blood mate with each other? parents 10. What are the potential blood types for offspring that are produced by a parent that is A+ and one that is AB-? Sgningatlo odi nol om sig gonda borooqxs Post-Lab Questions 1. In the human species, polydactyly (the
- The red color of the tomato pulp depends on the presence of the R factor, dominant over its r allele for yellow. Dwarfism is due to a recessive gene d. There is a homozygous variety with yellow pulp and normal size and another dwarf variety with red pulp.• From the available varieties, could a homozygous variety with red pulp and normal size be obtained?• And a variety of yellow pulp and dwarf size?Give reasons for the answer.Explain at the biochemical or enzymatic level, the phenotypic consequencesof alleles incase of following cross. Rr (pink flower) x Rr (pink flower) (progeny are 1 RR (red flower) :2 Rr (pink flower): 1rr(white flower) how alleles contribute to a phenotype through metabolism.Genetics 181 Rule of Incomplete Dominance When two different pure-breeding strains are crossed, and their offspring show a blending of phenotypes, then neither allele is dominant. This is easily recognized when the phenotype is somewhere between two extremes. Counting the parents, there are three phenotypes (black, white, grey) being expressed in these flowers instead of only two, and that third phenotype is intermediate between the other two. This heterozygous condition is called incomplete dominance. 1. On the chart you did earlier, which of the three hair types (wavy, curly, or straight) represents incomplete dominance-the blended heterozygous condition? 2. You cross a herd of red cattle with white cattle and all of the calves appear to be roan (reddish white). Is this an example of incomplete dominance? How do you know? 3. You cross a blue flowering pea plant with a white flowering pea plant and all of the offspring are blue flowered. Is this an example of incomplete dominance? How…
- . The human IGF2 gene is autosomal and maternallyimprinted. Copies of the gene received from themother are not expressed, but copies received fromthe father are expressed. You have found two allelesof this gene that encode two different forms of theIGF2 protein distinguishable by gel electrophoresis.One allele encodes a 60K (Kilodalton) blood protein;the other allele encodes a 50K blood protein. In ananalysis of blood proteins from a couple named Billand Joan, you find only the 60K protein in Joan’sblood and only the 50K protein in Bill’s blood. Youthen look at their children: Jill is producing only the50K protein, while Bill Jr. is producing only the 60Kprotein.a. With these data alone, what can you say about theIGF2 genotype of Bill Sr. and Joan?b. Bill Jr. and a woman named Sara have two children, Pat and Tim. Pat produces only the 60K protein and Tim produces only the 50K protein. Withthe accumulated data, what can you now say aboutthe genotypes of Joan and Bill Sr.?In fruit flies, red eyes (pr+_) are dominant to purple eyes (prpr) and normal wings (vg+_) are dominant to vestigial wings (vgvg). The genes are located on the same chromosome. A pure breeding red-eyed fly with vestigial wings was crossed with a pure-breeding purple-eyed fly with normal wings. All of the F1 progeny had a WT phenotype. •What isthe arrangement of alleles on the F1's chromosome? •The recombination frequency between the two genes is 15%. If an F1 individual were test crossed, what percentage of the progeny would you expect to have the WT phenotype?Gene interaction and Epistasis Dog ears may either be drooping or erect. In terms of their barking, some always bark, others sometimes bark, and still other are non-barking. Two dogs from the same species but of different phenotypes were used in the cross: P1 phenotype drooping ears & Non-barking X erect ears & sometimes bark P1 genotype AABB aabb F1 phenotype 100% drooping ears & Non-barking F1 genotype AaBb Mating the male and female from F1 produced: F2 phenotypes F2 genotypes 4 drooping ears & non-barking A_B_ 1 drooping ears & always bark A_bb 2 erect ears & sometimes bark aaB_ aabb Using the same…
- When crossing 2 different parental strains of plants to establish the F1 generation, one of the assumptions that must be made in order to predict what the F1 phenotype will be is that.... both parsnts are heterozygous both parents are homozygous dominant both parents are homozygous recessive each patent is homozygous dominant for one trait and homozygous recessive for each otherF1 female Drosophila heterozygous for cinnabar eye (cn), vestigial wings (vg) and roof wings (rf) genes were test crossed with males homozygous for all three traits. The following result were obtained. 382 cinnabar, vestigial 401 roof 3 cinnabar 4 roof, vestigial 59 cinnabar, roof, vestigial 67 wild 44 cinnabar, roof 40 vestigial The chromosomal interference is equal to? 0.24 0.32 0.42 0.58 0.49A homozygous tall plant (T) bearing red coloured ( R) flowers is crossed with homozygous dwarf plant (t ) bearing white flowers (r ): Give the genotype and phenotype of the F1 generation.