Q. Mate the F1 generation with each other to produce F2 offspring. We can cross-pure breed strainsof flies that differ for two traits:eye colour and body colour. Forexample, red eye (YY) isdominant to yellow colour (yy).For the second trait which isbody colour, green body (BB) isdominant to brown body (bb).

Name: Q. Mate the F1 generation with each other to produce F2 offspring. We
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: Q. Mate the F1 generation with each other to produce F2 offspring. We can cross-pure breed strainsof flies that differ for two traits:eye colour and body colour. Forexample, red eye (YY) isdominant to yellow colour (yy).For the second trait which isb

Two strains- eye color and body color Parents- red eye and green body× yellow eye and brown body…

Answered: Mate the F1 generation with each other…

Science

Biology

Mate the F1 generation with each other to produce F2 offspring.

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

See similar textbooks

Similar questions

Heliodors are either red (R), yellow (Y) or an intermediate phenotype, orange. What is the genotype of the orange heliodor?
Tallness (T) is dominant to shortness (t) in pea plants. Draw a punnett square cross between a heterozygous tall and a heterozygous tall plant. The Phenotype ratio is Tall: Short The Genotype ratio is TT: Tt: tt Blank 1: T Blank 2: t Blank 3: T Blank 4: TT Blank 5: Tt Blank 6: t Blank 7: Blank 8: Blank 9: Blank 10: Blank 11: Blank 12: Blank 13:
Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?
Heterozygous Cc chickens express a condition called creeper, in which the leg and wing bones are shorter than normal (cc). The dominant C allele is lethal when homozygous. Skin color is determined by the alleles W and w. W_ chickens have white skin and ww chickens have yellow skin. In a mating between 2 chickens heterozygous for both of these genes: 1) What phenotypes will be observed in the progeny? 2) What fraction of the offspring will have each phenotype? Assign alleles. List possible phentoypes. Make gametes, draw Punnett square, and list fractions of genotypes and/or phenotypes of offspring,
A corn geneticist wants to obtain a corn plant that hasthe three dominant phenotypes: anthocyanin (A), longtassels (L), and dwarf plant (D). In her collection ofpure lines, the only lines that bear these alleles are AALL dd and aa ll DD. She also has the fully recessive lineaa ll dd. She decides to intercross the first two and testcross the resulting hybrid to obtain in the progeny aplant of the desired phenotype (which would have to beAa Ll Dd in this case). She knows that the three genesare linked in the order written, that the distance between the A/a and the L/l loci is 16 m.u., and that thedistance between the L/l and the D/d loci is 24 m.u.a. Draw a diagram of the chromosomes of the parents,the hybrid, and the tester.b. Draw a diagram of the crossover(s) necessary toproduce the desired genotype.c. What percentage of the testcross progeny will be ofthe phenotype that she needs?d. What assumptions did you make (if any)?
A wild-type fruit fly (heterozygous for gray body color andred eyes) is mated with a black fruit fly with purple eyes. Theoffspring are wild-type, 721; black purple, 751; gray purple, 49;black red, 45. What is the recombination frequency betweenthese genes for body color and eye color? Using informationfrom problem 3, what fruit flies (genotypes and phenotypes)would you mate to determine the order of the body color, wingsize, and eye color genes on the chromosome?
Aristapedia is alethal allele that is also dominant. Individuals with this trait must be heterozygous (Aa) because the homozygous condition (AA) is lethal. Wild type alleles do not carry the allele for aristapedia (aa). Predict what the outcome of a cross between a male and a female fly which both carry the aristapedia allele by showing a diagram. Then, go to FlyLab JS virtual lab and simulate the cross. Determine if the observed offspring is fit to the ratio that you obtained from your cross.(Use whole number only)
We have crossed true-breeding flies today. Wild type to mutant. Their phenotypes were wt and vg se. (Let’s not worry about males and females for now, just assume both genes are autosomal, which is normal in a Mendelian experiment). The results of a cross are phenotypes. I will be asking you for numbers or a ratio of phenotype numbers you expect to see in the offspring from this cross. To answer this, you’ll need to start with the genotypes of parents, then write their gametes, then write the offspring genotypes, then get the phenotypes based on them. Predict the results of this cross: In case both mutations are recessive; In case both mutations are dominant; In case vestigial wings are recessive and the sepia eyes are dominant.
Color in fish is determined by alleles B and b. Fish with genotype B- are blue in color. The genotype bb results in gold color. Pigment production in trout only occurs when allele G is present. Fish without pigment are alampic. The following results were obtained in a dihibrid test cross. Alampic 228 Blue 95 Gold 110 Are the results of the testcross in agreement with the expected ratio? Show all of your calculations.
Fruit fly body color is wild type (meaning normal) Gray = B+ and black = b Fruit fly wing type is wild type normal wings = vg+ and vg = vestigial A fly which was heterozygous for both traits was crossed with a fly that was recessive for both traits. Write the genotype and phenotype that would be expected from this cross. Write the genotype and phenotype percentages that would be expected from this cross.
Colored aleurone in the kernels of corn is due to the dominant allele R. The recessive allele r, when homozygous, produces colorless aleurone. The plant color (not kernel color) is controlled by another gene with two alleles, Y and y. The dominant Y allele results in green color, whereas the homozygous presence of the recessive y allele causes the plant to appear yellow. In a testcross between a plant of unknown genotype and phenotype and a plant that is homozygous recessive for both traits, the following progeny were obtained: colored, green 88colored, yellow 12colorless, green 8colorless, yellow 92Explain how these results were obtained by determining theexact genotype and phenotype of the unknown plant, including the precise association of the two genes on the homologs (i.e., the arrangement).
Punnett Square for a Dihybrid Cross to Investigate Coat Colour in Mice be Вс BbCc Answer: D Ova BBCC BbCc bc) bb Cc (BC) BbCC D BbCc Bbcc X BBCC bbcc BBcc bbcc Bb Cc BC O Sperm BbCC Bb Cc Bbcc bc BBCC bbcc Вс BbCc Legend Black Brown White Coat colour in mice is controlled by the interaction of two genes. Three phenotypes result: black coat, brown coat, and white coat. The expected phenotypic ratio resulting from a cross between a bbCc female mouse and BbCc male mouse, is black: brown : white Enter only the number values in the order black brown white (Do not include spaces, commas, etc.)